Explanation Given: r ( t ) = 〈 cos 2 t sin t , sin 2 t , cos 2 t cos t 〉 Radius of sphere = 1. Center of sphere = (0,0,0) Formula used: General equation of sphere is ( x − a ) 2 + ( y − b ) 2 + ( z − c ) 2 = r 2 , Where a,b,c is center of sphere and r is radius of sphere. sin 2 x + cos 2 x = 1 Calculation: First we will find equation of sphere: ( x − a ) 2 + ( y − b ) 2 + ( z − c ) 2 = r 2 ⇒ ( x − 0 ) 2 + ( y − 0 ) 2 + ( z − 0 ) 2 = ( 1 ) 2 ⇒ x 2 + y 2 + z 2 = 1 r ( t ) = 〈 cos 2 t sin t , sin 2 t , cos 2 t cos t 〉 ⇒ x = cos 2 t sin t ⇒ y = sin 2 t ⇒ z = cos 2 t cos t To show that curve lies on the sphere, we will substitute the coordinates of curve in sphere. If we get value as 0, then we can confirm that the curve lies on the sphere To determine (b) Show that curve intersects the x-axis, the y-axis, and the z-axis.

ACHIEVE FOR CALCULUS 1 TERM >CSI CUSTOM<

4th Edition

ISBN: 9781319411657

Author: Rogawski

Publisher: MAC HIGHER

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Question

Chapter 13.1, Problem 23E

To determine

(a)

Show that curve r(t)=〈cos2tsint,sin2t,cos2tcost〉 lies on the sphere of radius 1 centered at the origin.

To determine

(b)

Show that curve intersects the x-axis, the y-axis, and the z-axis.

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Chapter 13.1, Problem 22E

Chapter 13.1, Problem 24E

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Chapter 13 Solutions

ACHIEVE FOR CALCULUS 1 TERM >CSI CUSTOM<

Ch. 13.1 - Prob. 1PQ Ch. 13.1 - Prob. 2PQ Ch. 13.1 - Prob. 3PQ Ch. 13.1 - Prob. 4PQ Ch. 13.1 - Prob. 5PQ Ch. 13.1 - Prob. 6PQ Ch. 13.1 - Prob. 1E Ch. 13.1 - Prob. 2E Ch. 13.1 - Prob. 3E Ch. 13.1 - Prob. 4E

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(a) Show that curve r ( t ) = 〈 cos 2 t sin t , sin 2 t , cos 2 t cos t 〉 lies on the sphere of radius 1 centered at the origin.

Solution Summary: The author explains the equation of sphere: r(t)=langle mathrmcos2t, centered at the origin.

Concept explainers

(a)

Show that curve r(t)=〈cos2tsint,sin2t,cos2tcost〉 lies on the sphere of radius 1 centered at the origin.

(b)

Show that curve intersects the x-axis, the y-axis, and the z-axis.

Want to see the full answer?

Chapter 13 Solutions

(a) Show that curve r ( t ) = 〈 cos 2 t sin t , sin 2 t , cos 2 t cos t 〉 lies on the sphere of radius 1 centered at the origin.

Solution Summary: The author explains the equation of sphere: r(t)=langle mathrmcos2t, centered at the origin.

Concept explainers

(a) Show that curve r(t)=〈cos2tsint,sin2t,cos2tcost〉 lies on the sphere of radius 1 centered at the origin.

(b) Show that curve intersects the x-axis, the y-axis, and the z-axis.

Want to see the full answer?

Chapter 13 Solutions

(a)

Show that curve r(t)=〈cos2tsint,sin2t,cos2tcost〉 lies on the sphere of radius 1 centered at the origin.

(b)

Show that curve intersects the x-axis, the y-axis, and the z-axis.