(II) Water and then oil (which don't mix) are poured into a U-shaped tube, open at both ends. They come to equilib- rium as shown in Fig. 10-50. What is the density of the oil? [Hint: Pressures at points a and b are equal. Why?] 8.62 cm Oil 27.2 cm a b FIGURE 10–50 Water. Problem 18.

(II) One liter of alcohol (1000 cm3) in a flexible container is carried to the bottom of the sea, where the pressure is 2.6 x106 N m2.What will be its volume there?

(5) Logs sometimes float vertically in a lake because one end has become water-logged and denser than the other. What is the average density (in kg/m3 ) of a uniform-diameter log that floats with 30.0% of its length above water?

(II) If the base of an insect’s leg has a radius of about 3.0 x10-5 m and the insect’s mass is 0.016 g, would you expect the six-legged insect to remain on top of the water? Why or why not?

(II) A two-component model used to determine percent body fat in a human body assumes that a fraction f (< 1) of the body's total mass m is composed of fat with a density of 0.90 g/cm?, and that the remaining mass of the body is composed of fat-free tissue with a density of 1.10 g/cm³. If the specific gravity of the entire body's density is X, show that the percent body fat (= f × 100) is given by 3 495 % Body fat 450. X

(I) If the force F needed to move the wire in Fig. 10–34 is 3.4 x 10-3 N, calculate the surface tension Y of the enclosed fluid. Assumel = 0.070 m. %3D

(II) On dry land, an athlete weighs 70.2 kg. The same athlete, when submerged in a swimming pool and hanging from a scale, has an "apparent weight" of 3.4 kg. Using Example 10-8 as a guide, (a) find the total volume V of the submerged athlete. (b) Assume that when submerged, the athlete's body contains a residual volume VR = 1.3 × 10-³ m³ of air (mainly in the lungs). Taking V – Vg to be the actual volume of the athlete's body, find the body's specific gravity, SG. (c) What is the athlete's percent body fat assuming it is given by the formula (495/SG) – 450? | lift

An impermeable membrane is placed at the bottom of a U-tube, then equal amounts of water and oil are poured into each limb of the tube such that the height on both sides reads 18.7cm. if the permeable membrane is removed, calculate the height difference in cm of the U-tube, assuming a uniform cross-sectional area of the U-tube and given that the specific gravity of oil is 0.808

9. (I) Estimate the pressure exerted on a floor by (a) one pointed heel of area = 0.45 cm?, and (b) one wide heel of area 16 cm², Fig. 10-48 O. The person wearing the shoes has a mass of 56 kg.