Explanation 1) Concept: We can use the definition of work done as integral force times displacement. Then we can find work done by the applied force during the move by integrating the gravitational force along the given radial distance. 2) Formulae: i) W = F → · S → ii) W = ∫ 1 2 d W → = ∫ 1 2 F → · d S → 3) Given: An object of mass m in placed initially at position r 1 = 3 R E and then moved to other position r 2 = 4R E along the radial line. 4) Calculation: Work done by an applied force during the displacement S is given by W = F → · S → In given situation, the force and displacement both are along the radial direction of the earth. Hence, the angle between F → and S → is zero. Therefore, the work done is W = FS When the displacement is considered through a small magnitude dS, the differential work done is dW = F ds and the total work done is W = ∫ 1 2 d W → = ∫ 1 2 F → · d S → In the given problem, F = - G M E m r 2 and the displacement is dr = distance between position r 1 = 3 R E and r 2 = 4R E

Fundamentals of Physics, Volume 1, Chapter 1-20

10th Edition

ISBN: 9781118233764

Author: David Halliday

Publisher: WILEY

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Chapter 13, Problem 97P

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The work done by the applied force during the move

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Chapter 13, Problem 96P

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Fundamentals of Physics, Volume 1, Chapter 1-20

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The work done by the applied force during the move

Solution Summary: The author explains how to find the work done by the applied force during the move by integrating the gravitational force along the given radial distance.

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Chapter 13 Solutions

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The work done by the applied force during the move