EBK ELECTRIC CIRCUITS
11th Edition
ISBN: 9780134747224
Author: Riedel
Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)
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Chapter 13, Problem 93P
To determine
Show that the output voltage
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Q1: Design a logic circuit for the finite-state machine described by the assigned
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Using D flip-flops.
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b.
Using T flip-flops.
Present
Next State
Output
State
x=0
x=0
YE
Y₁Y
Y₁Y
Z
00
00
01
0
0
от
00
0
0
10
00
10
11
00
10
0
Find Va and Vb using mesh analysis
Find Va and Vb using Mesh analysis
Chapter 13 Solutions
EBK ELECTRIC CIRCUITS
Ch. 13.2 - The parallel circuit in Example 13.1 is placed in...Ch. 13.3 - Prob. 2APCh. 13.3 - The energy stored in the circuit shown is zero at...Ch. 13.3 - The dc current and dc voltage sources are applied...Ch. 13.3 - Prob. 6APCh. 13.3 - Using the results from Example 13.7 for the...Ch. 13.3 - The energy stored in the circuit shown is zero at...Ch. 13.4 -
Derive the numerical expression for the transfer...Ch. 13.5 - Find (a) the unit step and (b) the unit impulse...Ch. 13.5 - The unit impulse response of a circuit is
υo(t) =...
Ch. 13.7 - The current source in the circuit shown is...Ch. 13.7 - For the circuit shown, find the steady-state...Ch. 13 - Prob. 1PCh. 13 - Prob. 2PCh. 13 - Prob. 3PCh. 13 - Prob. 4PCh. 13 - An 2 kΩ resistor, a 6.25 H inductor, and a 250 nF...Ch. 13 - A 250 Ω resistor is in series with an 80 mH...Ch. 13 - Find the poles and zeros of the impedance seen...Ch. 13 - Find the poles and zeros of the impedance seen...Ch. 13 - Prob. 9PCh. 13 - The switch in the circuit in Fig. P13.10 has been...Ch. 13 - Find Vo and υo in the circuit shown in Fig. P13.11...Ch. 13 - Prob. 12PCh. 13 - Prob. 13PCh. 13 - Find the time-domain expression for the current in...Ch. 13 - Prob. 15PCh. 13 - Prob. 16PCh. 13 - The make-before-break switch in the circuit in...Ch. 13 - Prob. 18PCh. 13 - Prob. 19PCh. 13 - There is no energy stored in the circuit in Fig....Ch. 13 - Prob. 21PCh. 13 - There is no energy stored in the circuit in Fig....Ch. 13 - Prob. 23PCh. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 27PCh. 13 - Prob. 28PCh. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - There is no energy stored in the capacitance in...Ch. 13 - The switch in the circuit seen in Fig. P13.32 has...Ch. 13 - Prob. 33PCh. 13 - Prob. 35PCh. 13 - There is no energy stored in the circuit in Fig....Ch. 13 - Prob. 37PCh. 13 - Prob. 38PCh. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - Prob. 43PCh. 13 - Prob. 44PCh. 13 - Prob. 45PCh. 13 - The op amp in the circuit shown in Fig. P13.46 is...Ch. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - Find the transfer function H(s) − Vo/Vi for the...Ch. 13 - Prob. 51PCh. 13 - Prob. 52PCh. 13 - Prob. 53PCh. 13 - Prob. 54PCh. 13 - The operational amplifier in the circuit in Fig....Ch. 13 - Prob. 56PCh. 13 - The operational amplifier in the circuit in Fig....Ch. 13 - Find the transfer function Io/Ig as a function of...Ch. 13 - Prob. 60PCh. 13 - Prob. 61PCh. 13 - Prob. 62PCh. 13 - Prob. 66PCh. 13 - Prob. 69PCh. 13 - The input voltage in the circuit seen in Fig....Ch. 13 - Find the impulse response of the circuit shown in...Ch. 13 - Assume the voltage impulse response of a circuit...Ch. 13 - Prob. 75PCh. 13 - Prob. 76PCh. 13 - Prob. 77PCh. 13 - The transfer function for a linear time-invariant...Ch. 13 - The transfer function for a linear time-invariant...Ch. 13 - Prob. 80PCh. 13 - The op amp in the circuit seen in Fig. P13.81 is...Ch. 13 - Prob. 82PCh. 13 - Prob. 83PCh. 13 - Prob. 84PCh. 13 - There is no energy stored in the circuit in Fig....Ch. 13 - Prob. 86PCh. 13 - Prob. 87PCh. 13 - Prob. 89PCh. 13 - Prob. 90PCh. 13 - The switch in the circuit in Fig P13.91 has been...Ch. 13 - The parallel combination of R2 and C2 in the...Ch. 13 - Show that if R1C1 = R2C2 in the circuit shown in...
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- Find Va and Vb using nodal analysisarrow_forward2. Using the approximate method, hand sketch the Bode plot for the following transfer functions. a) H(s) = 10 b) H(s) (s+1) c) H(s): = 1 = +1 100 1000 (s+1) 10(s+1) d) H(s) = (s+100) (180+1)arrow_forwardQ4: Write VHDL code to implement the finite-state machine described by the state Diagram in Fig. 1. Fig. 1arrow_forward
- 1. Consider the following feedback system. Bode plot of G(s) is shown below. Phase (deg) Magnitude (dB) -50 -100 -150 -200 0 -90 -180 -270 101 System: sys Frequency (rad/s): 0.117 Magnitude (dB): -74 10° K G(s) Bode Diagram System: sys Frequency (rad/s): 36.8 Magnitude (dB): -99.7 System: sys Frequency (rad/s): 20 Magnitude (dB): -89.9 System: sys Frequency (rad/s): 20 Phase (deg): -143 System: sys Frequency (rad/s): 36.8 Phase (deg): -180 101 Frequency (rad/s) a) Determine the range of K for which the closed-loop system is stable. 102 10³ b) If we want the gain margin to be exactly 50 dB, what is value for K we should choose? c) If we want the phase margin to be exactly 37°, what is value of K we should choose? What will be the corresponding rise time (T) for step-input? d) If we want steady-state error of step input to be 0.6, what is value of K we should choose?arrow_forward: Write VHDL code to implement the finite-state machine/described by the state Diagram in Fig. 4. X=1 X=0 solo X=1 X=0 $1/1 X=0 X=1 X=1 52/2 $3/3 X=1 Fig. 4 X=1 X=1 56/6 $5/5 X=1 54/4 X=0 X-O X=O 5=0 57/7arrow_forwardQuestions: Q1: Verify that the average power generated equals the average power absorbed using the simulated values in Table 7-2. Q2: Verify that the reactive power generated equals the reactive power absorbed using the simulated values in Table 7-2. Q3: Why it is important to correct the power factor of a load? Q4: Find the ideal value of the capacitor theoretically that will result in unity power factor. Vs pp (V) VRIPP (V) VRLC PP (V) AT (μs) T (us) 8° pf Simulated 14 8.523 7.84 84.850 1000 29.88 0.866 Measured 14 8.523 7.854 82.94 1000 29.85 0.86733 Table 7-2 Power Calculations Pvs (mW) Qvs (mVAR) PRI (MW) Pay (mW) Qt (mVAR) Qc (mYAR) Simulated -12.93 -7.428 9.081 3.855 12.27 -4.84 Calculated -12.936 -7.434 9.083 3.856 12.32 -4.85 Part II: Power Factor Correction Table 7-3 Power Factor Correction AT (us) 0° pf Simulated 0 0 1 Measured 0 0 1arrow_forward
- Questions: Q1: Verify that the average power generated equals the average power absorbed using the simulated values in Table 7-2. Q2: Verify that the reactive power generated equals the reactive power absorbed using the simulated values in Table 7-2. Q3: Why it is important to correct the power factor of a load? Q4: Find the ideal value of the capacitor theoretically that will result in unity power factor. Vs pp (V) VRIPP (V) VRLC PP (V) AT (μs) T (us) 8° pf Simulated 14 8.523 7.84 84.850 1000 29.88 0.866 Measured 14 8.523 7.854 82.94 1000 29.85 0.86733 Table 7-2 Power Calculations Pvs (mW) Qvs (mVAR) PRI (MW) Pay (mW) Qt (mVAR) Qc (mYAR) Simulated -12.93 -7.428 9.081 3.855 12.27 -4.84 Calculated -12.936 -7.434 9.083 3.856 12.32 -4.85 Part II: Power Factor Correction Table 7-3 Power Factor Correction AT (us) 0° pf Simulated 0 0 1 Measured 0 0 1arrow_forwardelectric plants. Prepare the load schedulearrow_forwardelectric plants Draw the column diagram. Calculate the voltage drop. by hand writingarrow_forward
- electric plants. Draw the lighting, socket, telephone, TV, and doorbell installations on the given single-story project with an architectural plan by hand writingarrow_forwardA circularly polarized wave, traveling in the +z-direction, is received by an elliptically polarized antenna whose reception characteristics near the main lobe are given approx- imately by E„ = [2â, + jâ‚]ƒ(r. 8, 4) Find the polarization loss factor PLF (dimensionless and in dB) when the incident wave is (a) right-hand (CW) An elliptically polarized wave traveling in the negative z-direction is received by a circularly polarized antenna. The vector describing the polarization of the incident wave is given by Ei= 2ax + jay.Find the polarization loss factor PLF (dimensionless and in dB) when the wave that would be transmitted by the antenna is (a) right-hand CParrow_forwardjX(1)=j0.2p.u. jXa(2)=j0.15p.u. jxa(0)=0.15 p.u. V₁=1/0°p.u. V₂=1/0° p.u. 1 jXr(1) = j0.15 p.11. jXT(2) = j0.15 p.u. jXr(0) = j0.15 p.u. V3=1/0° p.u. А V4=1/0° p.u. 2 jX1(1)=j0.12 p.u. 3 jX2(1)=j0.15 p.u. 4 jX1(2)=0.12 p.11. JX1(0)=0.3 p.u. jX/2(2)=j0.15 p.11. X2(0)=/0.25 p.1. Figure 1. Circuit for Q3 b).arrow_forward
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