
Concept explainers
(a)
The fraction of the submarines volume is above the water surface when the tanks are filled with air.
(a)

Answer to Problem 92P
Explanation of Solution
Given:
Total mass of a submarine (including crew and equipment) is
The volume of a pressure hull is
The volume of a ballast tank is
Total volume of the submarine is,
Formula used:
The fraction of the submarine’s volume above the surface when the tanks are filled with air can be written as,
Where
Apply
Where
Using Archimedes’ principle, the buoyant force
Where,
Weight of the submarine is,
Where,
Substituting for
Substituting for
Calculation:
Substituting the numerical values in equation
Conclusion:
The fraction of the submarines volume is above the water surface when the tanks are filled with air is
(b)
The quantity of water must be admitted in to the tanks to give the submarine a neutral buoyancy.
(b)

Answer to Problem 92P
Explanation of Solution
Given:
Total mass of a submarine (including crew and equipment) is
The volume of a pressure hull is
The volume of a ballast tank is
Total volume of the submarine is,
Neglect the mass of any air in the tanks,
Specific gravity of sea water is
Formula used:
The volume of the sea water in terms of its mass and density is,
Applying the condition for neutral buoyancy,
Where,
Using Archimedes’ principle, the buoyant force
Where,
Weight of the submarine is,
Where,
Weight of the sea water is,
Where,
Substituting for
Substituting for
Calculation:
Substitute the numerical values in equation
Conclusion:
The quantity of water must be admitted in to the tanks to give the submarine a neutral buoyancy is
Want to see more full solutions like this?
Chapter 13 Solutions
EBK PHYSICS FOR SCIENTISTS AND ENGINEER
- Can someone help mearrow_forwardNeed help on the following questions on biomechanics. (Please refer to images below)A gymnast weighing 68 kg attempts a handstand using only one arm. He plants his handat an angle resulting in the reaction force shown.A) Find the resultant force (acting on the Center of Mass)B) Find the resultant moment (acting on the Center of Mass)C) Draw the resultant force and moment about the center of mass on the figure below. Will the gymnast rotate, translate, or both? And in which direction?arrow_forwardPlease help me on the following question (Please refer to image below)An Olympic lifter (m = 103kg) is holding a lift with a mass of 350 kg. The barexerts a purely vertical force that is equally distributed between both hands. Each arm has amass of 9 kg, are 0.8m long and form a 40° angle with the horizontal. The CoM for each armis 0.5 m from hand. Assuming the lifter is facing us in the diagram below, his right deltoidinserts 14cm from the shoulder at an angle of 13° counter-clockwise from the humerus.A) You are interested in calculating the force in the right deltoid. Draw a free body diagramof the right arm including the external forces, joint reaction forces, a coordinate system andstate your assumptions.B) Find the force exerted by the right deltoidC) Find the shoulder joint contact force. Report your answer using the magnitude and directionof the shoulder force vector.arrow_forward
- I need help with part B. I cant seem to get the correct answer. Please walk me through what youre doing to get to the answer and what that could bearrow_forwardQuestion 6: Chlorine is widely used to purify municipal water supplies and to treat swimming pool waters. Suppose that the volume of a particular sample of Cl₂ gas is 8.70 L at 895 torr and 24°C. (a) How many grams of Cl₂ are in the sample? ⚫ Atomic mass of CI = 35.453 g/mol • Molar mass of Cl₂ = 2 x 35.453 = 70.906 g/mol Solution: Use the Ideal Gas Law: Step 1: Convert Given Values • Pressure: P = 895 torr → atm PV= = nRT 1 P = 895 × = 1.1789 atm 760 • Temperature: Convert to Kelvin: T24273.15 = 297.15 K • Gas constant: R = 0.0821 L atm/mol. K Volume: V = 8.70 L Step 2: Solve for n . PV n = RT n = (1.1789)(8.70) (0.0821)(297.15) 10.25 n = = 0.420 mol 24.405 Step 3: Calculate Mass of Cl₂ Final Answer: 29.78 g of Cl₂. mass nx M mass= (0.420)(70.906) mass= 29.78 garrow_forwardE1 R₁ w 0.50 20 Ω 12 R₁₂ ww ΒΩ R₂ 60 E3 C RA w 15 Ω E2 0.25 E4 0.75 Ω 0.5 Ωarrow_forward
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice UniversityPhysics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillCollege PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College





