Electric Circuits. (11th Edition)
11th Edition
ISBN: 9780134746968
Author: James W. Nilsson, Susan Riedel
Publisher: PEARSON
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Question
Chapter 13, Problem 82P
(a)
To determine
Find the transfer function
(b)
To determine
Find the steady state expression for
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Chapter 13 Solutions
Electric Circuits. (11th Edition)
Ch. 13.2 - The parallel circuit in Example 13.1 is placed in...Ch. 13.3 - Prob. 2APCh. 13.3 - The energy stored in the circuit shown is zero at...Ch. 13.3 - The dc current and dc voltage sources are applied...Ch. 13.3 - Prob. 6APCh. 13.3 - Using the results from Example 13.7 for the...Ch. 13.3 - The energy stored in the circuit shown is zero at...Ch. 13.4 -
Derive the numerical expression for the transfer...Ch. 13.5 - Find (a) the unit step and (b) the unit impulse...Ch. 13.5 - The unit impulse response of a circuit is
υo(t) =...
Ch. 13.7 - The current source in the circuit shown is...Ch. 13.7 - For the circuit shown, find the steady-state...Ch. 13 - Prob. 1PCh. 13 - Prob. 2PCh. 13 - Prob. 3PCh. 13 - Prob. 4PCh. 13 - An 2 kΩ resistor, a 6.25 H inductor, and a 250 nF...Ch. 13 - A 250 Ω resistor is in series with an 80 mH...Ch. 13 - Find the poles and zeros of the impedance seen...Ch. 13 - Find the poles and zeros of the impedance seen...Ch. 13 - Prob. 9PCh. 13 - The switch in the circuit in Fig. P13.10 has been...Ch. 13 - Find Vo and υo in the circuit shown in Fig. P13.11...Ch. 13 - Prob. 12PCh. 13 - Prob. 13PCh. 13 - Find the time-domain expression for the current in...Ch. 13 - Prob. 15PCh. 13 - Prob. 16PCh. 13 - The make-before-break switch in the circuit in...Ch. 13 - Prob. 18PCh. 13 - Prob. 19PCh. 13 - There is no energy stored in the circuit in Fig....Ch. 13 - Prob. 21PCh. 13 - There is no energy stored in the circuit in Fig....Ch. 13 - Prob. 23PCh. 13 - Prob. 24PCh. 13 - Prob. 25PCh. 13 - Prob. 26PCh. 13 - Prob. 27PCh. 13 - Prob. 28PCh. 13 - Prob. 29PCh. 13 - Prob. 30PCh. 13 - There is no energy stored in the capacitance in...Ch. 13 - The switch in the circuit seen in Fig. P13.32 has...Ch. 13 - Prob. 33PCh. 13 - Prob. 35PCh. 13 - There is no energy stored in the circuit in Fig....Ch. 13 - Prob. 37PCh. 13 - Prob. 38PCh. 13 - Prob. 39PCh. 13 - Prob. 40PCh. 13 - Prob. 41PCh. 13 - Prob. 42PCh. 13 - Prob. 43PCh. 13 - Prob. 44PCh. 13 - Prob. 45PCh. 13 - The op amp in the circuit shown in Fig. P13.46 is...Ch. 13 - Prob. 47PCh. 13 - Prob. 48PCh. 13 - Prob. 49PCh. 13 - Find the transfer function H(s) − Vo/Vi for the...Ch. 13 - Prob. 51PCh. 13 - Prob. 52PCh. 13 - Prob. 53PCh. 13 - Prob. 54PCh. 13 - The operational amplifier in the circuit in Fig....Ch. 13 - Prob. 56PCh. 13 - The operational amplifier in the circuit in Fig....Ch. 13 - Find the transfer function Io/Ig as a function of...Ch. 13 - Prob. 60PCh. 13 - Prob. 61PCh. 13 - Prob. 62PCh. 13 - Prob. 66PCh. 13 - Prob. 69PCh. 13 - The input voltage in the circuit seen in Fig....Ch. 13 - Find the impulse response of the circuit shown in...Ch. 13 - Assume the voltage impulse response of a circuit...Ch. 13 - Prob. 75PCh. 13 - Prob. 76PCh. 13 - Prob. 77PCh. 13 - The transfer function for a linear time-invariant...Ch. 13 - The transfer function for a linear time-invariant...Ch. 13 - Prob. 80PCh. 13 - The op amp in the circuit seen in Fig. P13.81 is...Ch. 13 - Prob. 82PCh. 13 - Prob. 83PCh. 13 - Prob. 84PCh. 13 - There is no energy stored in the circuit in Fig....Ch. 13 - Prob. 86PCh. 13 - Prob. 87PCh. 13 - Prob. 89PCh. 13 - Prob. 90PCh. 13 - The switch in the circuit in Fig P13.91 has been...Ch. 13 - The parallel combination of R2 and C2 in the...Ch. 13 - Show that if R1C1 = R2C2 in the circuit shown in...
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Similar questions
- : For the gravity concrete dam shown in the figure, the following data are available: The factor of safety against sliding (F.S sliding)=1.2 Unit weight of concrete (Yconc)=24 KN/m³ - Neglect( Wave pressure, silt pressure, ice force and earth quake force) μ=0.65, (Ywater) = 9.81 KN/m³ Find factor of safety against overturning (F.S overturning) 6m3 80m Smarrow_forwardI need help checking if its correct -E1 + VR1 + VR4 – E2 + VR3 = 0 -------> Loop 1 (a) R1(I1) + R4(I1 – I2) + R3(I1) = E1 + E2 ------> Loop 1 (b) R1(I1) + R4(I1) - R4(I2) + R3(I1) = E1 + E2 ------> Loop 1 (c) (R1 + R3 + R4) (I1) - R4(I2) = E1 + E2 ------> Loop 1 (d) Now that we have loop 1 equation will procced on finding the equation of I2 current loop. However, a reminder that because we are going in a clockwise direction, it goes against the direction of the current. As such we will get an equation for the matrix that will be: E2 – VR4 – VR2 + E3 = 0 ------> Loop 2 (a) -R4(I2 – I1) -R2(I2) = -E2 – E3 ------> Loop 2 (b) -R4(I2) + R4(I1) - R2(I2) = -E2 – E3 -----> Loop 2 (c) R4(I1) – (R4 + R2)(I2) = -E2 – E3 -----> Loop 2 (d) These two equations will be implemented to the matrix formula I = inv(A) * b R11 R12 (R1 + R3 + R4) -R4 -R4 R4 + R2arrow_forward10.2 For each of the following groups of sources, determineif the three sources constitute a balanced source, and if it is,determine if it has a positive or negative phase sequence.(a) va(t) = 169.7cos(377t +15◦) Vvb(t) = 169.7cos(377t −105◦) Vvc(t) = 169.7sin(377t −135◦) V(b) va(t) = 311cos(wt −12◦) Vvb(t) = 311cos(wt +108◦) Vvc(t) = 311cos(wt +228◦) V(c) V1 = 140 −140◦ VV2 = 114 −20◦ VV3 = 124 100◦ Varrow_forward
- Apply single-phase equivalency to determine the linecurrents in the Y-D network shown in Fig. P10.13. The loadimpedances are Zab = Zbc = Zca = (25+ j5) Warrow_forward10.8 In the network of Fig. P10.8, Za = Zb = Zc = (25+ j5) W.Determine the line currents.arrow_forwardUsing D flip-flops, design a synchronous counter. The counter counts in the sequence 1,3,5,7, 1,7,5,3,1,3,5,7,.... when its enable input x is equal to 1; otherwise, the counter count 0. Present state Next state x=0 Next state x=1 Output SO 52 S1 1 S1 54 53 3 52 53 S2 56 51 0 $5 5 54 S4 53 0 55 58 57 7 56 56 55 0 57 S10 59 1 58 58 S7 0 59 S12 S11 7 $10 $10 59 0 $11 $14 $13 5 $12 S12 $11 0 513 $15 SO 3 S14 $14 S13 0 $15 515 SO 0 Explain how to get the table step by step with drawing the state diagram and finding the Karnaugh map.arrow_forward
- For the oscillator resonance circuit shown in Fig. (5), derive the oscillation frequency Feedback and open-loop gains. L₁ 5 mH (a) ell +10 V R₁ ww R3 S C2 HH 1 με 1000 pF 100 pF R₂ 1 με RA H (b) +9 V R4 CA 470 pF C₁ R3 HH 1 με R₁ ww L₁ 000 1.5 mH R₂ ww Hi 1 μF L2 m 10 mHarrow_forwardExpert handwritten solution onlyarrow_forwardB. For the oscillator circuit shown in frequency, feedback and open-loop gains. +10 V name the circuit, derive and find the oscillation P.Av +9 V -000 4₁ 5 mH w R₁ C₂ HH 1 με w 100 pF R₂ T R CA www. 470 pF w ww www 1000 pF HH 1μF C₁ HH 1μF Ra ww HI 4₁ 000 1.5 mH H 4 AF 000 10 mHarrow_forward
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