Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Introductory Chemistry (6th Edition)
6th Edition
ISBN: 9780134565927
Author: Nivaldo J. Tro
Publisher: PEARSON
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Question
Chapter 13, Problem 80E
Interpretation Introduction
Interpretation:
The concentration of cation and anion in each of the given aqueous solution to be determined.
Concept Introduction:
The concentration of a solution that contains molecular compound tells about the concentration of the solute as it exists in the solution. The concentration of the solution that contains an ionic compound tells about the concentration of the solute before it is dissolved.
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 13 Solutions
Mastering Chemistry with Pearson eText -- Standalone Access Card -- for Introductory Chemistry (6th Edition)
Ch. 13 - Which compound forms an electroIyte solution When...Ch. 13 - A solution is saturated in O2 gas and KNO3 at room...Ch. 13 -
Q3. What is the mass percent concentration of a...Ch. 13 - Prob. 4SAQCh. 13 - What mass of glucose (C6H12O6) is contained in...Ch. 13 - What is the molar concentration of potassium ions...Ch. 13 - Prob. 8SAQCh. 13 - Potassium iodide reacts with lead(ll) nitrate in...Ch. 13 - Prob. 10SAQCh. 13 -
Q11. Calculate the freezing point of 1.30 m...
Ch. 13 - What mass of ethylene glycol (C2H6O6) must be...Ch. 13 - Prob. 1ECh. 13 - Prob. 2ECh. 13 - Prob. 3ECh. 13 - Explain what like dissolves like means.Ch. 13 - What is solubility?Ch. 13 - Describe what happens when additional solute is...Ch. 13 -
7. Explain the difference between a strong...Ch. 13 -
8. How does gas solubility depend on...Ch. 13 - Prob. 9ECh. 13 - Prob. 10ECh. 13 -
11. When you heat water on a stove, bubbles form...Ch. 13 - Prob. 12ECh. 13 - How does gas solubility depend on pressure? How...Ch. 13 -
14. What is the difference between a dilute...Ch. 13 -
15. Define the concentration units mass percent...Ch. 13 - Prob. 16ECh. 13 -
17. How does the presence of a nonvolatile solute...Ch. 13 - What are colligative properties?Ch. 13 - Prob. 19ECh. 13 - Prob. 20ECh. 13 -
21. Two shipwreck survivors were rescued from a...Ch. 13 - 22 Why are intravenous fluids always isoosmotic...Ch. 13 - Prob. 23ECh. 13 - Prob. 24ECh. 13 - Identify the solute and solvent in each solution....Ch. 13 - Prob. 26ECh. 13 - Pick an appropriate solvent from Table 13.2 to...Ch. 13 - Prob. 28ECh. 13 - What are the dissolved particles in a solution...Ch. 13 - What are the dissolved particles in a solution...Ch. 13 - A solution contains 35 g of Nacl per 100 g of...Ch. 13 -
32. A solution contains 28 g of per 100 g of...Ch. 13 - A KNO3 solution containing 45 g of KNO3 per 100 g...Ch. 13 - Prob. 34ECh. 13 - Refer to Figure 13.4 to determine whether each of...Ch. 13 - Prob. 36ECh. 13 - Prob. 37ECh. 13 - Prob. 38ECh. 13 - Scuba divers breathing air at increased pressure...Ch. 13 - Prob. 40ECh. 13 - Prob. 41ECh. 13 - Prob. 42ECh. 13 - 43. A soft drink contains 42 g of sugar in 311 g...Ch. 13 - A soft drink contains 32 mg of sodium in 309 g of...Ch. 13 - Prob. 45ECh. 13 - Prob. 46ECh. 13 - Prob. 47ECh. 13 - Prob. 48ECh. 13 - Prob. 49ECh. 13 - Prob. 50ECh. 13 - Prob. 51ECh. 13 - Prob. 52ECh. 13 - Prob. 53ECh. 13 - A dioxin-contaminated water source contains 0.085%...Ch. 13 - Prob. 55ECh. 13 - Prob. 56ECh. 13 - Prob. 57ECh. 13 - Prob. 58ECh. 13 - Calculate the molarity of each solution. a. 0.127...Ch. 13 - Prob. 60ECh. 13 - Calculate the molarity of each solution. a. 22.6 g...Ch. 13 - Prob. 62ECh. 13 - 63. A 205-mL sample of ocean water contains 6.8 g...Ch. 13 - 64. A 355-mL can of soda pop contains 41 g of...Ch. 13 - Prob. 65ECh. 13 - Prob. 66ECh. 13 - Prob. 67ECh. 13 - Prob. 68ECh. 13 - Prob. 69ECh. 13 - Prob. 70ECh. 13 - Calculate the mass of NaCl in a 35-mL sample of a...Ch. 13 - 72. Calculate the mass of glucose in a 105-mL...Ch. 13 - Prob. 73ECh. 13 - 74. A laboratory procedure calls for making 500.0...Ch. 13 - 75. How many liters of a 0.500 M sucrose solution...Ch. 13 - Prob. 76ECh. 13 - Prob. 77ECh. 13 - Prob. 78ECh. 13 - Prob. 79ECh. 13 - Prob. 80ECh. 13 - Prob. 81ECh. 13 - Prob. 82ECh. 13 - Prob. 83ECh. 13 - 84. Describe how you would make 500.0 mL of a...Ch. 13 - To what volume should you dilute 25 mL of a 12 M...Ch. 13 - Prob. 86ECh. 13 - Prob. 87ECh. 13 - Prob. 88ECh. 13 - 89. Determine the volume of 0.150 M NaOH solution...Ch. 13 - Prob. 90ECh. 13 - Consider the reaction:...Ch. 13 - Prob. 92ECh. 13 - Prob. 93ECh. 13 - 94. A 25.0-mL sample of an unknown solution...Ch. 13 - 95. What is the minimum amount of necessary to...Ch. 13 - Prob. 96ECh. 13 - Prob. 97ECh. 13 - Prob. 98ECh. 13 - Prob. 99ECh. 13 - Prob. 100ECh. 13 - Prob. 101ECh. 13 - Prob. 102ECh. 13 - Prob. 103ECh. 13 - Prob. 104ECh. 13 - A glucose solution contains 55.8 g of glucose...Ch. 13 - 106. An ethylene glycol solution contains 21.2 g...Ch. 13 - Prob. 107ECh. 13 - Prob. 108ECh. 13 - Prob. 109ECh. 13 - Prob. 110ECh. 13 - Prob. 111ECh. 13 - Prob. 112ECh. 13 - What is the molarity of an aqueous solution that...Ch. 13 - Prob. 114ECh. 13 - Consider the reaction:...Ch. 13 - Prob. 116ECh. 13 - Prob. 117ECh. 13 - Prob. 118ECh. 13 - Prob. 119ECh. 13 - Prob. 120ECh. 13 - 121. An ethylene glycol solution is made using...Ch. 13 - A sucrose solution is made using 144 g of sucrose...Ch. 13 - A 250.0-mL sample of a 5.00 M glucose (C6H12O6)...Ch. 13 - Prob. 124ECh. 13 - Prob. 125ECh. 13 - 126. An aqueous solution containing 35.9 g of an...Ch. 13 - Prob. 127ECh. 13 - Prob. 128ECh. 13 - A 125-g sample contains only glucose (C6H12O6) and...Ch. 13 - A 13.03-g sample contains only ethylene glycol...Ch. 13 - Consider the molecular views of osmosis cells. For...Ch. 13 - What is wrong with this molecular view of a sodium...Ch. 13 - Prob. 133ECh. 13 - Prob. 134ECh. 13 - Prob. 135QGWCh. 13 - Prob. 136QGWCh. 13 - Prob. 137QGWCh. 13 - Prob. 138QGWCh. 13 - Data Interpretation and Analysis Read CHEMISTRY IN...
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