A spring 1.50 m long with force constant 475 N/m is hung from the ceiling of an elevator, and a block of mass 10.0 kg is attached to the bottom of the spring. (a) By how much is the spring stretched when the block is slowly lowered to its equilibrium point? (b) If the elevator subsequently accelerates upward at 2.00 m/s 2 , what is the position of the block, taking the equilibrium position found in part (a) as y = 0 and upwards as the positive y -direction. (c) If the elevator cable snaps during the acceleration, describe the subsequent motion of the block relative to the freely falling elevator. What is the amplitude of its motion?
A spring 1.50 m long with force constant 475 N/m is hung from the ceiling of an elevator, and a block of mass 10.0 kg is attached to the bottom of the spring. (a) By how much is the spring stretched when the block is slowly lowered to its equilibrium point? (b) If the elevator subsequently accelerates upward at 2.00 m/s 2 , what is the position of the block, taking the equilibrium position found in part (a) as y = 0 and upwards as the positive y -direction. (c) If the elevator cable snaps during the acceleration, describe the subsequent motion of the block relative to the freely falling elevator. What is the amplitude of its motion?
Solution Summary: The author calculates the stretch in the spring when the block is slowly lowered to its equilibrium position.
A spring 1.50 m long with force constant 475 N/m is hung from the ceiling of an elevator, and a block of mass 10.0 kg is attached to the bottom of the spring. (a) By how much is the spring stretched when the block is slowly lowered to its equilibrium point? (b) If the elevator subsequently accelerates upward at 2.00 m/s2, what is the position of the block, taking the equilibrium position found in part (a) as y = 0 and upwards as the positive y-direction. (c) If the elevator cable snaps during the acceleration, describe the subsequent motion of the block relative to the freely falling elevator. What is the amplitude of its motion?
Calculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were:
222.22 800.00
61.11 641.67
0.00 588.89
11.11 588.89
8.33 588.89
11.11 588.89
5.56 586.11
2.78 583.33
Give in the answer window the calculated repeated experiment variance in m/s2.
No chatgpt pls will upvote
Can you help me solve the questions please
Chapter 13 Solutions
Student Solutions Manual With Study Guide, Volume 2 For Serway/vuilles College Physics, 10th
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