Finding Maximum and Minimum Values (a) Let f ( x , y ) = x − y and g ( x , y ) = x 2 + y 2 = 4 . Graph various level curves of f ad the constraint g in the x y -plane. Use the graph to determine the maximum value of f subject to the constraint g = 4 . Then verify your answer using Lagrange multipliers. (b) Let f ( x , y ) = x − y and g ( x , y ) = x 2 + y 2 = 0 . Find the maximum and minimum values of f subject to the constraint g = 0 . Does the Method of Lagrange Multipliers work in this case? Explain.
Finding Maximum and Minimum Values (a) Let f ( x , y ) = x − y and g ( x , y ) = x 2 + y 2 = 4 . Graph various level curves of f ad the constraint g in the x y -plane. Use the graph to determine the maximum value of f subject to the constraint g = 4 . Then verify your answer using Lagrange multipliers. (b) Let f ( x , y ) = x − y and g ( x , y ) = x 2 + y 2 = 0 . Find the maximum and minimum values of f subject to the constraint g = 0 . Does the Method of Lagrange Multipliers work in this case? Explain.
Solution Summary: The author explains how to calculate f(x,y) = x-y and g (x), based on Lagrange's Theorem.
(a) Let
f
(
x
,
y
)
=
x
−
y
and
g
(
x
,
y
)
=
x
2
+
y
2
=
4
. Graph various level curves of
f
ad the constraint
g
in the
x
y
-plane. Use the graph to determine the maximum value of
f
subject to the constraint
g
=
4
. Then verify your answer using Lagrange multipliers.
(b) Let
f
(
x
,
y
)
=
x
−
y
and
g
(
x
,
y
)
=
x
2
+
y
2
=
0
. Find the maximum and minimum values of
f
subject to the constraint
g
=
0
. Does the Method of Lagrange Multipliers work in this case? Explain.
The velocity of a particle moves along the x-axis and is given by the equation ds/dt = 40 - 3t^2 m/s. Calculate the acceleration at time t=2 s and t=4 s. Calculate also the total displacement at the given interval. Assume at t=0 s=5m.Write the solution using pen and draw the graph if needed.
4. Use method of separation of variable to solve the following wave equation
მłu
J²u
subject to
u(0,t) =0, for t> 0,
u(л,t) = 0, for t> 0,
=
t> 0,
at²
ax²'
u(x, 0) = 0,
0.01 x,
ut(x, 0) =
Π
0.01 (π-x),
0
Solve the following heat equation by method of separation variables:
ди
=
at
subject to
u(0,t) =0, for
-16024
ძx2 •
t>0, 0 0,
ux (4,t) = 0, for
t> 0,
u(x, 0) =
(x-3,
\-1,
0 < x ≤2
2≤ x ≤ 4.
Chapter 13 Solutions
Student Solutions Manual For Larson/edwards? Multivariable Calculus, 11th
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