Explanation Given information: Square cross sectional area of the suspender is 1.5 in. The weight of the passenger is 1500 lb. Calculation: Determine the cross sectional area of suspended arm using the relation: A = a 2 Here, a is the side of square. Substitute 1.5 in 2 for a . A = 1.5 2 = 2.25 in 2 Determine the moment of inertia ( I ) suspended arm: I = b d 3 12 Here, I is the moment of inertia, b is the width of the arm, and d is the depth. Substitute 1.5 in 2 for b and 1.5 in 2 for d . I = ( 1.5 ) ( 1.5 ) 3 12 = 0.421875 in 3 Sketch the diagram of segment AB as shown in Figure 1: Consider the weight of the passengers as w = 1500 lb acting downward. Consider the normal reaction in the rope to the loading as P A B = 1500 lb acting upward Refer to Figure 1: Determine the largest tensile stress ( σ max ) A B developed in region AB . ( σ max ) A B = P A B A Here, A is the square cross sectional area and P A B is the normal reaction at point AB . Substitute 1500 lb for P A B and 2.25 in 2 for A . ( σ max ) A B = 1500 ( 2.25 ) = 666.67 psi Hence, the largest tensile stress ( σ max ) A B developed in region AB is 667 psi _ . Sketch the diagram of segment CD as shown in Figure 2: Determine the normal stress ( σ a ) developed in region CD . σ a = P C D A Here, A is the square cross sectional area and P C D is the normal reaction at point CD

Statics and Mechanics of Materials (5th Edition)

5th Edition

ISBN: 9780134382593

Author: Russell C. Hibbeler

Publisher: PEARSON

See similar textbooks

Concept explainers

Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial …

Videos

Question

Chapter 13, Problem 4RP

To determine

Find the largest tensile stress developed in region AB and in region DC.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 13, Problem 3RP

Chapter 13, Problem 5RP

Students have asked these similar questions

this is an old practice exam, the answer is Ax = -4, Ay = -12,Az = 32.5, Bx= 34, Bz = 5, By = 0 but how?

This is an old practice exam, the answer is Ax = Az = 0, Ay = 2000, TDE = 4750, Cx = 2000, Cy = 2000, Cz = -800 but how?

this is an old practice exam, the answer is Fmin = 290.5lb but how

Chapter 13 Solutions

Statics and Mechanics of Materials (5th Edition)

Ch. 13.1 - A spherical gas tank has an inner radius of r =...Ch. 13.1 - A pressurized spherical tank is made of...Ch. 13.1 - The thin-walled cylinder can be supported in one...Ch. 13.1 - Prob. 4P Ch. 13.1 - Prob. 5P Ch. 13.1 - Determine the maximum force P that can be exerted...Ch. 13.1 - Prob. 7P Ch. 13.1 - The steel water pipe has an inner diameter of 12...Ch. 13.1 - The steel water pipe has an inner diameter of 12...Ch. 13.1 - The A-36-steel band is 2 in. wide and is secured...

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.

Find the largest tensile stress developed in region AB and in region DC.

Solution Summary: The author determines the largest tensile stress developed in region AB and region DC. The cross sectional area of the suspended arm is 1.5 in.

Concept explainers

Videos

Find the largest tensile stress developed in region AB and in region DC.

Want to see the full answer?

Chapter 13 Solutions