Interpretation Introduction To determine: The order of the reaction, the value of rate constant, and the concentration of AB at 250. Explanation The reaction is as follows: AB ( g ) → A ( g ) +B ( g ) Data of the concentration of AB at various intervals is as follows: Time (s) [AB] (M) 0 0.950 50 0.459 100 0.302 150 0.225 200 0.180 250 0.149 300 0.128 350 0.112 400 0.0994 450 0.0894 500 0.0812 A straight line obtained from the plot of the inverse of the concentration of the reactants versus time. To find out the order of the reaction, draw the graph between ln [ A B ] and time and 1 [ A B ] and time. For the graph of ln [ A B ] versus time, data is shown below: Time (s) ln[AB] 0 −0.05129 50 −0.77871 100 −1.19733 150 −1.49165 200 −1.7148 250 −1.90381 300 −2.05573 350 −2.18926 400 −2.3086 450 −2.41463 500 −2.51084 Plot of the natural log of concentration of reactant (ln[AB]) versus time as follows: For the graph of 1 [ A B ] versus time, data is shown below: Time (s) 1/[AB] 0 1.0526 50 2.1486 100 3.3112 150 4.4444 200 5.5555 250 6.7114 300 7.8125 350 8.981 400 10.060 450 11.185 500 12.315 The graph is shown below: A straight line is obtained with the plot of 1 [ A B ] versus time

Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Principles Of Chemistry: A Molecular Approach

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ISBN: 9780133890686

Author: Tro

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Chapter 13, Problem 47E

Interpretation Introduction

To determine: The order of the reaction, the value of rate constant, and the concentration of AB at 250.

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Chapter 13, Problem 46E

Chapter 13, Problem 48E

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Masteringchemistry With Pearson Etext -- Valuepack Access Card -- For Principles Of Chemistry: A Molecular Approach

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