Introduction To Chemistry 5th Edition
Introduction To Chemistry 5th Edition
5th Edition
ISBN: 9781260162097
Author: BAUER
Publisher: MCG
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Chapter 13, Problem 45QP
Interpretation Introduction

Interpretation:

The reason for the statement: “Hydrosulphuric acid has two ionization constant values�, is to be explained. The equations that correspond to its Ka values are to be written as well.

Concept Introduction:

An acid that loses more than one proton in a solution is called polyprotic acid.

Different types of acids come under the category of polyprotic acids. For example- diprotic acids, triprotic acids, etc.

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Answers to the remaining 6 questions will be hand-drawn on paper and submitted as a single file upload below: Review of this week's reaction: H₂NCN (cyanamide) + CH3NHCH2COOH (sarcosine) + NaCl, NH4OH, H₂O ---> H₂NC(=NH)N(CH3)CH2COOH (creatine) Q7. Draw by hand the reaction of creatine synthesis listed above using line structures without showing the Cs and some of the Hs, but include the lone pairs of electrons wherever they apply. (4 pts) Q8. Considering the Zwitterion form of an amino acid, draw the Zwitterion form of Creatine. (2 pts) Q9. Explain with drawing why the C-N bond shown in creatine structure below can or cannot rotate. (3 pts) NH2(C=NH)-N(CH)CH2COOH This bond Q10. Draw two tautomers of creatine using line structures. (Note: this question is valid because problem Q9 is valid). (4 pts) Q11. Mechanism. After seeing and understanding the mechanism of creatine synthesis, students should be ready to understand the first half of one of the Grignard reactions presented in a past…
Propose a synthesis pathway for the following transformations. b) c) d)

Chapter 13 Solutions

Introduction To Chemistry 5th Edition

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