Modern Physics, 3rd Edition
Modern Physics, 3rd Edition
3rd Edition
ISBN: 9780534493394
Author: Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher: Cengage Learning
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Chapter 13, Problem 33P

(a)

To determine

The number of decays per minute.

(b)

To determine

The reason for the age of charcoal piece is closer to the limit of dating using the technique mentioned.

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In the accompanying figure, the rails, connecting end pieces, and rod all have a resistance per unit length of 4.52/cm. The rod moves to the left at v = 5 m/s. If B = 0.3 T everywhere in the region, what is the current in the circuit (a) when a = 6.5 cm? (b) when a = 4 cm?
Problem Twelve. An object consists of four particles: m₁ =1.0kg, m₂ = 2.0kg, m3 = 3.0kg, ma = 4.0kg. They are connected by rigid massless rods to form a rectangle of edge lengths 2a and 2b, where a 7.0 m and b = 8.0 m. The system rotates about the x-axis through the center as shown. = Find the (x, y) coordinate of the center of gravity of the object (in meters). Use the geometrical center of the object as the origin. 2a 13 2b m M2 Axis of rotation 20.) (A) (-3.2, -1.4) (B) (-3.2, 1.4) (C) (5.2, -1.4) (D) (-1.8,-1.4) (E) (3.2,-5.2) Find the moment of inertia of the object about the x-axis and y-axis that run through the geometrical center of the object. Give an answer as (Ix, ly, I) in units of 10² kg-m². 21.) (A) (6.4, 4.9, 11) (D) (9.8, 11, 12.8) (B) (4.9, 6.4, 11) (C) (11, 12.8, 9.8) (E) (2.5, 10, 11) anul babogaus al bos ano 002 maldor If the object is spinning with angular velocity of 30 rpm around the axis of rotation shown in the diagram, find the rotational kinetic energy. Give…
Problem Eleven. A hollow sphere with rotational inertia 1 = (2/3)MR2 is moving with speed v down an incline of angle 0 toward a spring with spring constant k. After traveling a distance d down the incline with no slipping, the sphere makes contact with the spring and compresses it a distance x before it comes momentarily to rest. Find the distance d in terms of the other quantities given. (21) 19.) (A) d=- 2Mg sin kx²-Mv² +x (B) d= 2Mg sin kx²+Mv² +x kx²-Mv² (C) d=- -x (D) d= 2Mg sin 2Mg cos kx²-Mv² 2Mg sin -x (E) d= kx²-Mv²

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Modern Physics, 3rd Edition

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