Statistics for the Behavioral Sciences
3rd Edition
ISBN: 9781506386256
Author: Gregory J. Privitera
Publisher: SAGE Publications, Inc
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Chapter 13, Problem 32PR
To determine
Explain the reason for partial eta-squared is an appropriate estimate of effect size for the study.
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Callahan (2009) conducted a study to evaluate the effectiveness of physical exercise programs for individuals with chronic arthritis. Participants with doctor-diagnosed arthritis either received a Tai Chi course immediately or were placed in a control group to begin the course 8 weeks later. At the end of the 8-week period, self-reports of pain were obtained for both groups. Data similar to the results obtained in the study are shown in the following table.
Self-Reported Level of Pain Mean
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Tai Chi course 3.7 1.2
No Tai Chi course 7.6 1.7
Construct a bar graph that…
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(y) and the number of cigarettes smoked per day in the child's home (x).
a. For the 18 girls, the coefficient of correlation between y and x was reported as r = –.50. Interpret
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this result.
b. Refer to part a. The p-value for testing Ho: p = 0 against H;: p # 0 was reported as p = .03.
n Interpret this result.
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this result.
d. Refer to part c. The p-value for testing Ho: p = 0 against Ha: p #…
Patients suffering from rheumatic diseases or osteoporosis often suffer critical losses in bone mineral density (BMD). Alendronate is one medication prescribed to build or prevent further loss of BMD. Holcomb and Rothenberg (A-3) looked at 96 women taking alendronate to determine if a difference existed in the mean percent change in BMD among five different primary diagnosis classifications. Group 1 patients were diagnosed with rheumatoid arthritis (RA). Group 2 patients were a mixed collection of patients with diseases including lupus, Wegener’s granulomatosis and polyarteritis, and other vasculitic diseases (LUPUS). Group 3 patients had polymyalgia rheumatica or temporal arthritis (PMRTA). Group 4 patients had osteoarthritis (OA) and group 5 patients had osteoporosis (O) with no other rheumatic diseases identified in the medical record. Changes in BMD are shown in the following table.
Discuss the Alendronate medication data in terms of variability. To determine if a difference…
Chapter 13 Solutions
Statistics for the Behavioral Sciences
Ch. 13.3 - Prob. 1.1LCCh. 13.3 - Prob. 1.2LCCh. 13.3 - Prob. 1.3LCCh. 13.3 - Prob. 1.4LCCh. 13.4 - Prob. 2.1LCCh. 13.4 - Prob. 2.2LCCh. 13.4 - Prob. 2.3LCCh. 13.4 - Prob. 2.4LCCh. 13.5 - Prob. 3.1LCCh. 13.5 - Prob. 3.2LC
Ch. 13.5 - Prob. 3.3LCCh. 13.7 - Prob. 4.1LCCh. 13.7 - Prob. 4.2LCCh. 13.8 - Prob. 5.1LCCh. 13.8 - Prob. 5.2LCCh. 13 - Prob. 1FPCh. 13 - Prob. 2FPCh. 13 - Prob. 3FPCh. 13 - Prob. 4FPCh. 13 - Prob. 5FPCh. 13 - Prob. 6FPCh. 13 - Prob. 7FPCh. 13 - Prob. 8FPCh. 13 - Prob. 9FPCh. 13 - Prob. 10FPCh. 13 - Prob. 11FPCh. 13 - Prob. 12FPCh. 13 - Prob. 13CAPCh. 13 - Prob. 14CAPCh. 13 - Prob. 15CAPCh. 13 - Prob. 16CAPCh. 13 - Prob. 17CAPCh. 13 - Prob. 18CAPCh. 13 - Prob. 19CAPCh. 13 - Prob. 20CAPCh. 13 - Prob. 21CAPCh. 13 - Prob. 22CAPCh. 13 - Prob. 23CAPCh. 13 - Prob. 24CAPCh. 13 - Prob. 25CAPCh. 13 - Prob. 26CAPCh. 13 - Prob. 27CAPCh. 13 - Prob. 28PRCh. 13 - Prob. 29PRCh. 13 - Prob. 30PRCh. 13 - Prob. 31PRCh. 13 - Prob. 32PR
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- Patients suffering from rheumatic diseases or osteoporosis often suffer critical losses in bone mineral density (BMD). Alendronate is one medication prescribed to build or prevent further loss of BMD. Holcomb and Rothenberg (A-3) looked at 96 women taking alendronate to determine if a difference existed in the mean percent change in BMD among five different primary diagnosis classifications. Group 1 patients were diagnosed with rheumatoid arthritis (RA). Group 2 patients were a mixed collection of patients with diseases including lupus, Wegener’s granulomatosis and polyarteritis, and other vasculitic diseases (LUPUS). Group 3 patients had polymyalgia rheumatica or temporal arthritis (PMRTA). Group 4 patients had osteoarthritis (OA) and group 5 patients had osteoporosis (O) with no other rheumatic diseases identified in the medical record. Changes in BMD are shown in the following table. (TABLE IS IN THE IMAGES) a. Formulate research question b. State the null hypothesis in narrative…arrow_forwardA group of disabled women ages 65 and older were followed for several years. It was found that those who had a vitamin B12 deficiency were twice as likely to suffer from severe depressions than those who did not.a. Describe the type of study being performed.b. Describe the explanatory variable(s) and response variable(s).arrow_forwardA biologist wished to study the effects of ethanol on sleep time. A sample of 80 rats, matched for age and other characteristics, was selected, and each rat was given an oral injection having a particular concentration of ethanol per body weight. The rapid eye movement (REM) sleep time for each rat was then recorded for a 24-hour period. The results are summarized in the side-by-side boxplots below. How is the amount of ethanol given related to the median REM sleep time? Does the amount of ethanol given affect the variability of REM sleep time? What amount of ethanol given leads to the most skewed distribution of sleep times? Is the distribution of REM sleep times for the rats given 2 g/kg ethanol symmetric, skewed left, or skewed right?arrow_forward
- An ANOVA provides the following data: Group A's mean is 17.59; group B's mean is 15.74; group C's mean is 14.91; HSD is 2.77 What are the significant differences between these conditions? O There are no significant differences among these group means. Group A has a significantly higher mean than group B and group C; group B has a significantly higher mean than group C. O Group A has a significantly higher mean than group B and group C; there is no significant difference between group B's and C's means. O Groups A and B do not significantly differ, but they are both significantly higher than group C.arrow_forwardFemale college student participation in athletics has increased dramatically over the past few decades. Sports medicine providers are aware of some unique health concerns of athletic women, including disordered eating. A study compared disordered-eating symptoms and their causes for collegiate female athletes (in lean and non lean sports) and nonathletes. The sample mean of the body dissatisfaction assessment score was 13.4 (s=7.9) for 15 lean sports athletes (those sports that place value on leanness, including distance running, swimming, and gymnastics) and 7.4 (s=5.8) for the 67 non-lean athletes. Assume equal population standard deviations. Find the standard error for comparing the means. Construct a 95% confidence interval for the difference between the mean body dissatisfaction for lean sport athletes and non lean sport athletes. Interpret.arrow_forwardBinge-watching a television show might not be the best way to enjoy a television series (Horvath et al., 2017). Participants in an experiment were in a group that either watched an entire t.v. series during daily one-hour sessions or watched all the episodes during a single binge session. Participants were asked to rate their enjoyment of the t.v. series on a scale of 0-100. Data like those observed by the author are listed below. Binge-watched Daily-watched 87 84 71 100 73 87 86 97 78 92 Is there a difference in the level of enjoyment based on whether the series was binge-watched or watched on a daily basis? Use a two-tailed test at the α = 0.05 level of significance?arrow_forward
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- 8.88 Is honey a cough remedy? Refer to the Archives of Pediatrics and Adolescent Medicine (Dec. 2007) study of HCOUGH honey as a children's cough remedy, Exercise 8.23 (p. 446). The data (cough improvement scores) for the 33 chil- dren in the DM dosage group and the 35 children in the honey dosage group are reproduced in the table below. In Exercise 8.23, you used a comparison of two means to de- termine whether “honey may be a preferable treatment for the cough and sleep difficulty associated with childhood upper respiratory tract infection." The researchers also want to know if the variability in coughing improvement scores differs for the two groups. Conduct the appropriate analysis, using = .10. Honey Dosage: 12 12 6. 12 11 15 11 11 15 10 10 13 10 9. 13 4 15 8 12 16 10 9. 14 8. 10 9. 5 10 11 8 12 12 15 8 DM Dosage: 4 13 9 4 13 7 7 7 9 4 10 12 10 11 3 9 4 12 8 12 12 12 4 7 10 15 6. Source: I. M. Paul et al., "Effect of Honey, Dextromethorphan, and No Treatment on Nocturnal Cough and…arrow_forwardSocial Media Use and ADHD. Exercise 2.23 introduces a study examining whether frequent use of digital social media by teens is associated with subsequent development of ADHD symptoms. Researchers rated the frequency of social media use as High or Low for each teen. Two years later, they recorded whether or not ADHD symptoms had been diagnosed. The results are shown in the table below. Use StatKey or other technology to test whether the proportion of teens being diagnosed with ADHD is higher for teens with a high frequency of social media use than for those with a low frequency. Show all details of the test. Let Group 1 represent the teens with high social media use and Group 2 represent those with low social media use. State the null and alternative hypotheses. Give notation of the sample statistic. Give value of the sample statistic accurate to three decimal places. Use a randomization distribution to find the p-value. Give your answer accurate to three decimal places. Social…arrow_forwardA study of the differences in cognitive function between normal individuals and patients diagnosed with schizophrenia was published in the American Journal of Psychiatry (Apr. 2010). The total time (in minutes) a subject spent on the Trail Making Test (a standard psychological test) was used as a measure of cognitive function. The researchers theorize that the mean time on the Trail Making Test for schizophrenics will be larger than the corresponding mean for normal subjects. The data for independent random samples of 41 schizophrenics and 49 normal individuals yielded the following results: ***PHOTO Does the data provide significant evidence, at the 4.6% level, that the population mean time for patients diagnosed with schizophrenia exceeds the population mean time for normal individuals by more than 20 points?arrow_forward
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