A series RLC circuit can have a higher voltage than the source voltage across the resistor.
Whether the given statement is true or false.
Answer to Problem 1TFQ
False.
Explanation of Solution
Given:
The given statement is:
The voltage across the resistor in a series RLC circuit is higher than the source voltage.
Calculation:
In case of a series resonant circuit, the capacitive reactance and the inductive reactance are equal and opposite to each other. Therefore, they cancel out each other’s effect. That is, the remaining circuit behaves like a resistive circuit. Hence, the voltage across the resistor is equal to the source voltage. This means that for the current brought up through any one branch, the other branch needs to return it to the ground at the same rate. That is, the currents through those branches must cancel out each other to zero.That is why, the value of total current in the L and C branches of a parallel circuit at resonance will be zero.
When the frequency is less than the resonant frequency, the value of inductive reactance is less than the capacitive reactance. In case of the parallel circuits, the current in the branch having more reactance will be less than the branch having less reactance. This concludes that the current flowing through the inductor is more and hence, the circuit is an inductive circuit. Current lags the voltage in case of inductive circuits.
In case of a parallel resonant circuit, the capacitive reactance and the inductive reactance are equal and opposite to each other. Therefore, they cancel out each other’s effect. That is, the current in the capacitive branch and the inductive branch are always 180 degrees out of phase to each other. Therefore, the capacitive and the inductive current subtract from each other.That is, the remaining circuit behaves like a resistive circuit. Hence, the voltage across the resistor is equal to the source voltage. The total current in the circuit will be equal to the resistance current.
Therefore, the given statement is False.
Want to see more full solutions like this?
Chapter 13 Solutions
Electronics Fundamentals: Circuits, Devices & Applications
- Not use ai pleasearrow_forward49. For the circuit below, what is the best connection of the capacitor to filte voltage? ბი DO A O BO wwwww wwwww M m H E LOADarrow_forward5.25. Determine the corner frequency resulting from Cin in Fig. 5.47(d). For simplicity, assume C₁ is a short circuit. TVDD C₁ M2 RF Vin H w - Vout Cin M₁arrow_forward
- In the below circuit, find out the value of equivalent Thevenin's voltage and Thevenin's resistance at the terminal. 2000 0.25 A 400 2 800 2 0.1 Aarrow_forwardQ1: For the circuit shown in Figure-1, (a) Calculate the equivalent resistance of the circuit, RAB at the terminals A and B. [10] (b) When 50V dc source is switched at terminals A-B, solve for the voltage V₁ at the location shown. [10] 50V www 12Ω 10Ω 5Ω www www A + B 200 Figure-1 www 10Ω ww 25Ω 100arrow_forwarda. Write a PLC ladder diagram that allows the teacher to teach AND, OR, and XOR logic gates through using three PLC's digital input points and only one digital output point.arrow_forward
- rately by PRACTICE 4.2 For the circuit of Fig. 4.5, compute the voltage across each curren source. 202 ww 3A 30 ww 4Ω S 50 www Reference node FIGURE 4.5 Ans: V3A =5.235 V; 7A = 11.47 V. 7 Aarrow_forwardQ2) a) design and show me your steps to convert the following signal from continuous form to digital form: s(t)=3sin(3πt) -1 373 Colesarrow_forwardA sequence is defined by the relationship r[n] = [h[m]h[n+m]=hn*h-n where h[n] is a minimum-phase sequence and r[n]= 4 4 (u[n]+ 12" [n-1] 3 (a) Find R(z) and sketch the pole-zero diagram. (b) Determine the minimum-phase sequence h[n] to within a scale factor of ±1. Also, determine the z-transform H(z) of h[n].arrow_forward
- usıng j-k and D flipflop design a counter that counts 0,2,1 again as shown below ın the tablearrow_forwardfind the minterms of the followıng boolean expressıon desıgn F's cırcuit using one of the approciate decoders given below and a NOR gateF(A,B,C,D)=(A+'BC)(B 'C+'A 'D + CD)arrow_forward64) answer just two from three the following terms: A) Design ADC using the successive method if the Vmax=(3) volt, Vmin=(-2) volt, demonstrate the designing system for vin-1.2 volt. Successive Approximation ADC Input Voltage-1.1 V -4-3.5-3 -2.5 -2 -1.5 +1 -0.5 0 0.5 1 1.5 2 2.5 3 3.5 1 T -8 -7 -6 -5 -3 +2 -1 0 1 2 3 4 5 6 7 X=1??? 1st guess: -0.25 V (too high) X=11?? 2nd guess: -2.25 V (too low) 3rd guess: -1.25 V (too low) X=1110 X=111? 4th guess: -0.75 V (too high) Make successive guesses and use a comparator to tell whether your guess is too high or too low. Each guess determines one bit of the answer and cuts the number of remaining possibilities in half.arrow_forward
- Delmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage Learning