HORIZONS (LL) W/WEBASSIGN ACCESS CARD
14th Edition
ISBN: 9780357537565
Author: Seeds
Publisher: CENGAGE L
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Chapter 13, Problem 1RQ
To determine
For what reason can't the advancement of galaxies go from elliptical to spiral? From spiral to elliptical?
Expert Solution & Answer
Explanation of Solution
Galaxies come in three basic classifications, elliptical, spiral, and irregular. Elliptical galaxies are in elliptical shape or round shape, contain no visible gas and dust, and lack hot, bright stars. Spiral galaxies contain spiral arms and a disk. These galaxies contain gas and dust and hot, bright O and B type stars. Finally, irregular galaxies are composed of a chaotic mix of gas and dust, but do not have an obvious central bulge or spiral arms.
The reason that the evolution of galaxies can`t go from elliptical to spiral(or spiral to elliptical) is due to the fact that basic components of these two galaxy types is so different. Elliptical galaxies contain no visible gas and dust, and lack hot, bright stars while spiral galaxies contain gas and dust and hot, bright O and B type stars. So, it`s not possible for one of these types of galaxies to evolve to become the other type, whose constituents are very different.
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CH
57. A 190-g block is launched by compressing a spring of constant
k = = 200 N/m by 15 cm. The spring is mounted horizontally,
and the surface directly under it is frictionless. But beyond the
equilibrium position of the spring end, the surface has frictional
coefficient μ = 0.27. This frictional surface extends 85 cm, fol-
lowed by a frictionless curved rise, as shown in Fig. 7.21. After
it's launched, where does the block finally come to rest? Measure
from the left end of the frictional zone.
Frictionless
μ = 0.27 Frictionless
FIGURE 7.21 Problem 57
3. (a) Show that the CM of a uniform thin rod
of length L and mass M is at its center
(b) Determine the CM of the rod assuming its linear
mass density 1 (its mass per unit length) varies
linearly from λ = λ at the left end to double that
0
value, λ = 2λ, at the right end.
y
0
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dx
dm=λdx
x
+
Shrinking Loop. A circular loop of flexible iron wire has an initial circumference of 161 cm , but its circumference is decreasing at a constant rate of 15.0 cm/s due to a tangential pull on the wire. The loop is in a constant uniform magnetic field of magnitude 1.00 T , which is oriented perpendicular to the plane of the loop. Assume that you are facing the loop and that the magnetic field points into the loop. Find the magnitude of the emf E induced in the loop after exactly time 9.00 s has passed since the circumference of the loop started to decrease. please show all steps
Chapter 13 Solutions
HORIZONS (LL) W/WEBASSIGN ACCESS CARD
Ch. 13 - Prob. 1RQCh. 13 - Prob. 2RQCh. 13 - Prob. 3RQCh. 13 - Prob. 4RQCh. 13 - Prob. 5RQCh. 13 - Prob. 6RQCh. 13 - Prob. 7RQCh. 13 - Prob. 8RQCh. 13 - Prob. 9RQCh. 13 - Prob. 10RQ
Ch. 13 - Prob. 11RQCh. 13 - Prob. 12RQCh. 13 - Prob. 13RQCh. 13 - From what you know about star formation and the...Ch. 13 - Prob. 2DQCh. 13 - Prob. 3DQCh. 13 - Prob. 1PCh. 13 - Prob. 2PCh. 13 - Prob. 3PCh. 13 - Prob. 4PCh. 13 - Prob. 5PCh. 13 - Prob. 6PCh. 13 - Prob. 7PCh. 13 - Prob. 8PCh. 13 - Prob. 9PCh. 13 - Prob. 10PCh. 13 - Prob. 1LTLCh. 13 - Prob. 2LTLCh. 13 - Prob. 3LTLCh. 13 - Prob. 4LTL
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