The critical value for α = 0.05 , ν = 16 , k = 7 .

Question

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Answer 1

Question

Chapter 13, Problem 1RE

(a)

To determine

The critical value for α=0.05,ν=16,k=7.

(a)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.741.

Explanation of Solution

Given: The significance level is 0.05. The total number of treatments is k=7 and the error degrees of freedom are ν=16.

The tabulated value is obtained from Table X in the appendix of the textbook. The row entries correspond to ν and the column entries correspond to k. The value at the intersection of (16,7) is 4.741, which is the required critical value.

(b)

To determine

The critical value for α=0.05,ν=30,k=6.

(b)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.302.

Explanation of Solution

Given: The total number of treatments is k=6 and the error degrees of freedom are ν=30. The significance level is α=0.05.

The value corresponding to row 30 and column 6 in Table X of the textbook is 4.302. The rows contain the values of error degrees of freedom and the column represents the values for the number of treatments.

(c)

To determine

The critical value for α=0.01,ν=42,k=4.

(c)

Expert Solution

Answer to Problem 1RE

Solution: The value is 4.696.

Explanation of Solution

Given: There are a total of four treatments with the provided error degrees of freedom as 42. The confidence level is 1%.

The table for the critical values of Tukey’s test for 99% confidence level is provided in the appendix of the textbook. The critical value corresponding to row 42 and column 4 is 4.696, which is the required critical value.

(d)

To determine

The critical value for H0:μ1=μ2=μ3=μ4=μ5=μ6, with n=46,α=0.05.

(d)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.232.

Explanation of Solution

Given: It is provided that a total of six treatment means are to be compared for a sample of size 46 at 5% level of significance.

According to the provided information, k=6 and n=46. The error degrees of freedom are calculated as follows:

ν=n−k=46−6=40

The required critical value is the value corresponding to row 40 and column 6, and 4.232 is the required value.

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Answer 2

Question

Chapter 13, Problem 1RE

(a)

To determine

The critical value for α=0.05,ν=16,k=7.

(a)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.741.

Explanation of Solution

Given: The significance level is 0.05. The total number of treatments is k=7 and the error degrees of freedom are ν=16.

The tabulated value is obtained from Table X in the appendix of the textbook. The row entries correspond to ν and the column entries correspond to k. The value at the intersection of (16,7) is 4.741, which is the required critical value.

(b)

To determine

The critical value for α=0.05,ν=30,k=6.

(b)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.302.

Explanation of Solution

Given: The total number of treatments is k=6 and the error degrees of freedom are ν=30. The significance level is α=0.05.

The value corresponding to row 30 and column 6 in Table X of the textbook is 4.302. The rows contain the values of error degrees of freedom and the column represents the values for the number of treatments.

(c)

To determine

The critical value for α=0.01,ν=42,k=4.

(c)

Expert Solution

Answer to Problem 1RE

Solution: The value is 4.696.

Explanation of Solution

Given: There are a total of four treatments with the provided error degrees of freedom as 42. The confidence level is 1%.

The table for the critical values of Tukey’s test for 99% confidence level is provided in the appendix of the textbook. The critical value corresponding to row 42 and column 4 is 4.696, which is the required critical value.

(d)

To determine

The critical value for H0:μ1=μ2=μ3=μ4=μ5=μ6, with n=46,α=0.05.

(d)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.232.

Explanation of Solution

Given: It is provided that a total of six treatment means are to be compared for a sample of size 46 at 5% level of significance.

According to the provided information, k=6 and n=46. The error degrees of freedom are calculated as follows:

ν=n−k=46−6=40

The required critical value is the value corresponding to row 40 and column 6, and 4.232 is the required value.

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Answer 3

Question

Chapter 13, Problem 1RE

(a)

To determine

The critical value for α=0.05,ν=16,k=7.

(a)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.741.

Explanation of Solution

Given: The significance level is 0.05. The total number of treatments is k=7 and the error degrees of freedom are ν=16.

The tabulated value is obtained from Table X in the appendix of the textbook. The row entries correspond to ν and the column entries correspond to k. The value at the intersection of (16,7) is 4.741, which is the required critical value.

(b)

To determine

The critical value for α=0.05,ν=30,k=6.

(b)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.302.

Explanation of Solution

Given: The total number of treatments is k=6 and the error degrees of freedom are ν=30. The significance level is α=0.05.

The value corresponding to row 30 and column 6 in Table X of the textbook is 4.302. The rows contain the values of error degrees of freedom and the column represents the values for the number of treatments.

(c)

To determine

The critical value for α=0.01,ν=42,k=4.

(c)

Expert Solution

Answer to Problem 1RE

Solution: The value is 4.696.

Explanation of Solution

Given: There are a total of four treatments with the provided error degrees of freedom as 42. The confidence level is 1%.

The table for the critical values of Tukey’s test for 99% confidence level is provided in the appendix of the textbook. The critical value corresponding to row 42 and column 4 is 4.696, which is the required critical value.

(d)

To determine

The critical value for H0:μ1=μ2=μ3=μ4=μ5=μ6, with n=46,α=0.05.

(d)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.232.

Explanation of Solution

Given: It is provided that a total of six treatment means are to be compared for a sample of size 46 at 5% level of significance.

According to the provided information, k=6 and n=46. The error degrees of freedom are calculated as follows:

ν=n−k=46−6=40

The required critical value is the value corresponding to row 40 and column 6, and 4.232 is the required value.

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Answer 4

Question

Chapter 13, Problem 1RE

(a)

To determine

The critical value for α=0.05,ν=16,k=7.

(a)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.741.

Explanation of Solution

Given: The significance level is 0.05. The total number of treatments is k=7 and the error degrees of freedom are ν=16.

The tabulated value is obtained from Table X in the appendix of the textbook. The row entries correspond to ν and the column entries correspond to k. The value at the intersection of (16,7) is 4.741, which is the required critical value.

(b)

To determine

The critical value for α=0.05,ν=30,k=6.

(b)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.302.

Explanation of Solution

Given: The total number of treatments is k=6 and the error degrees of freedom are ν=30. The significance level is α=0.05.

The value corresponding to row 30 and column 6 in Table X of the textbook is 4.302. The rows contain the values of error degrees of freedom and the column represents the values for the number of treatments.

(c)

To determine

The critical value for α=0.01,ν=42,k=4.

(c)

Expert Solution

Answer to Problem 1RE

Solution: The value is 4.696.

Explanation of Solution

Given: There are a total of four treatments with the provided error degrees of freedom as 42. The confidence level is 1%.

The table for the critical values of Tukey’s test for 99% confidence level is provided in the appendix of the textbook. The critical value corresponding to row 42 and column 4 is 4.696, which is the required critical value.

(d)

To determine

The critical value for H0:μ1=μ2=μ3=μ4=μ5=μ6, with n=46,α=0.05.

(d)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.232.

Explanation of Solution

Given: It is provided that a total of six treatment means are to be compared for a sample of size 46 at 5% level of significance.

According to the provided information, k=6 and n=46. The error degrees of freedom are calculated as follows:

ν=n−k=46−6=40

The required critical value is the value corresponding to row 40 and column 6, and 4.232 is the required value.

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Answer 5

Chapter 13, Problem 1RE

(a)

To determine

The critical value for α=0.05,ν=16,k=7.

(a)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.741.

Explanation of Solution

Given: The significance level is 0.05. The total number of treatments is k=7 and the error degrees of freedom are ν=16.

The tabulated value is obtained from Table X in the appendix of the textbook. The row entries correspond to ν and the column entries correspond to k. The value at the intersection of (16,7) is 4.741, which is the required critical value.

(b)

To determine

The critical value for α=0.05,ν=30,k=6.

(b)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.302.

Explanation of Solution

Given: The total number of treatments is k=6 and the error degrees of freedom are ν=30. The significance level is α=0.05.

The value corresponding to row 30 and column 6 in Table X of the textbook is 4.302. The rows contain the values of error degrees of freedom and the column represents the values for the number of treatments.

(c)

To determine

The critical value for α=0.01,ν=42,k=4.

(c)

Expert Solution

Answer to Problem 1RE

Solution: The value is 4.696.

Explanation of Solution

Given: There are a total of four treatments with the provided error degrees of freedom as 42. The confidence level is 1%.

The table for the critical values of Tukey’s test for 99% confidence level is provided in the appendix of the textbook. The critical value corresponding to row 42 and column 4 is 4.696, which is the required critical value.

(d)

To determine

The critical value for H0:μ1=μ2=μ3=μ4=μ5=μ6, with n=46,α=0.05.

(d)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.232.

Explanation of Solution

Given: It is provided that a total of six treatment means are to be compared for a sample of size 46 at 5% level of significance.

According to the provided information, k=6 and n=46. The error degrees of freedom are calculated as follows:

ν=n−k=46−6=40

The required critical value is the value corresponding to row 40 and column 6, and 4.232 is the required value.

Answer 6

Chapter 13, Problem 1RE

(a)

To determine

The critical value for α=0.05,ν=16,k=7.

(a)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.741.

Explanation of Solution

Given: The significance level is 0.05. The total number of treatments is k=7 and the error degrees of freedom are ν=16.

The tabulated value is obtained from Table X in the appendix of the textbook. The row entries correspond to ν and the column entries correspond to k. The value at the intersection of (16,7) is 4.741, which is the required critical value.

Answer 7

Chapter 13, Problem 1RE

(a)

To determine

The critical value for α=0.05,ν=16,k=7.

Answer 8

(a)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.741.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given: The significance level is 0.05. The total number of treatments is k=7 and the error degrees of freedom are ν=16.

The tabulated value is obtained from Table X in the appendix of the textbook. The row entries correspond to ν and the column entries correspond to k. The value at the intersection of (16,7) is 4.741, which is the required critical value.

Answer 13

(b)

To determine

The critical value for α=0.05,ν=30,k=6.

(b)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.302.

Explanation of Solution

Given: The total number of treatments is k=6 and the error degrees of freedom are ν=30. The significance level is α=0.05.

The value corresponding to row 30 and column 6 in Table X of the textbook is 4.302. The rows contain the values of error degrees of freedom and the column represents the values for the number of treatments.

Answer 14

(b)

To determine

The critical value for α=0.05,ν=30,k=6.

Answer 15

(b)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.302.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given: The total number of treatments is k=6 and the error degrees of freedom are ν=30. The significance level is α=0.05.

The value corresponding to row 30 and column 6 in Table X of the textbook is 4.302. The rows contain the values of error degrees of freedom and the column represents the values for the number of treatments.

Answer 20

(c)

To determine

The critical value for α=0.01,ν=42,k=4.

(c)

Expert Solution

Answer to Problem 1RE

Solution: The value is 4.696.

Explanation of Solution

Given: There are a total of four treatments with the provided error degrees of freedom as 42. The confidence level is 1%.

The table for the critical values of Tukey’s test for 99% confidence level is provided in the appendix of the textbook. The critical value corresponding to row 42 and column 4 is 4.696, which is the required critical value.

Answer 21

(c)

To determine

The critical value for α=0.01,ν=42,k=4.

Answer 22

(c)

Expert Solution

Answer to Problem 1RE

Solution: The value is 4.696.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given: There are a total of four treatments with the provided error degrees of freedom as 42. The confidence level is 1%.

The table for the critical values of Tukey’s test for 99% confidence level is provided in the appendix of the textbook. The critical value corresponding to row 42 and column 4 is 4.696, which is the required critical value.

Answer 27

(d)

To determine

The critical value for H0:μ1=μ2=μ3=μ4=μ5=μ6, with n=46,α=0.05.

(d)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.232.

Explanation of Solution

Given: It is provided that a total of six treatment means are to be compared for a sample of size 46 at 5% level of significance.

According to the provided information, k=6 and n=46. The error degrees of freedom are calculated as follows:

ν=n−k=46−6=40

The required critical value is the value corresponding to row 40 and column 6, and 4.232 is the required value.

Answer 28

(d)

To determine

The critical value for H0:μ1=μ2=μ3=μ4=μ5=μ6, with n=46,α=0.05.

Answer 29

(d)

Expert Solution

Answer to Problem 1RE

Solution: The required value is 4.232.

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Given: It is provided that a total of six treatment means are to be compared for a sample of size 46 at 5% level of significance.

According to the provided information, k=6 and n=46. The error degrees of freedom are calculated as follows:

ν=n−k=46−6=40

The required critical value is the value corresponding to row 40 and column 6, and 4.232 is the required value.

Answer 34

Ch. 13.1 - 1. The acronym ANOVA stands for ____ ___ ______. Ch. 13.1 - 2. True or False: To perform a one-way ANOVA, the...Ch. 13.1 - Prob. 3AYU Ch. 13.1 - 4. The variability among the sample means is...Ch. 13.1 - Prob. 5AYU Ch. 13.1 - 6. True or False: The F-test statistic is F0 = . Ch. 13.1 - Prob. 7AYU Ch. 13.1 - In Problems 7 and 8, fill in the ANOVA...Ch. 13.1 - In Problems 9 and 10, determine the F-test...Ch. 13.1 - In Problems 9 and 10, determine the F-test...

The critical value for α = 0.05 , ν = 16 , k = 7 .

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The critical value for α=0.05,ν=16,k=7.

Answer to Problem 1RE

Explanation of Solution

The critical value for α=0.05,ν=30,k=6.

Answer to Problem 1RE

Explanation of Solution

The critical value for α=0.01,ν=42,k=4.

Answer to Problem 1RE

Explanation of Solution

The critical value for H0:μ1=μ2=μ3=μ4=μ5=μ6, with n=46,α=0.05.

Answer to Problem 1RE

Explanation of Solution

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