Compute the value of each of the following.
a.
b.
c.
d.
e.

(a)
To calculate:
The value of
Answer to Problem 1E
Solution:
The value of
Explanation of Solution
The Fibonacci sequence is 1, 1, 2, 3, 5, 8, 13 and so on, (each term is the sum of the first two preceding terms).
The terms of the Fibonacci sequence are known as Fibonacci numbers. The
Given:
The given expression is
Formula used:
The recursive formula to calculate the
Here
Calculation:
The
Substitute 1 for
Substitute 1 for
Substitute 2 for
Similarly,
Substitute
Conclusion:
Thus, the

(b)
To calculate:
The value of
Answer to Problem 1E
Solution:
The value of
Explanation of Solution
The Fibonacci sequence is 1, 1, 2, 3, 5, 8, 13 and so on, (each term is the sum of the first two preceding terms).
The terms of the Fibonacci sequence are known as Fibonacci numbers. The
Given:
The given expression is
Formula used:
The recursive formula to calculate the
Here
Substitute 610 for
Conclusion:
Thus, the value of

(c)
To calculate:
The value of
Answer to Problem 1E
Solution:
The value of
Explanation of Solution
The Fibonacci sequence is 1, 1, 2, 3, 5, 8, 13 and so on, (each term is the sum of the first two preceding terms).
The terms of the Fibonacci sequence are known as Fibonacci numbers. The
Given:
The given expression is
Formula used:
The recursive formula to calculate the
Here
In the Fibonacci sequence
Substitute 89 for
Conclusion:
Thus, the value of

(d)
To calculate:
The value of
Answer to Problem 1E
Solution:
The value of
Explanation of Solution
The Fibonacci sequence is 1, 1, 2, 3, 5, 8, 13 and so on, (each term is the sum of the first two preceding terms).
The terms of the Fibonacci sequence are known as Fibonacci numbers. The
Given:
The given expression is
Formula used:
The recursive formula to calculate the
Here
Substitute 610 for
Conclusion:
Thus, the value of

(e)
To calculate:
The value of
Answer to Problem 1E
Solution:
The value of
Explanation of Solution
The Fibonacci sequence is 1, 1, 2, 3, 5, 8, 13 and so on, (each term is the sum of the first two preceding terms).
The terms of the Fibonacci sequence are known as Fibonacci numbers. The
Given:
The given expression is
Formula used:
The recursive formula to calculate the
Here
The number
Conclusion:
Thus, the value of
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Chapter 13 Solutions
EXCURSIONS IN MODERN MATH
- 3. Suppose that A is 5 x 5 and rank(A)=4. Use this information to answer the following. a. Give a geometric description of nullspace(A). Justify. b. Is A invertible? Justify. c. Give a geometric description of the span of the column vectors of A. What space are the column vectors of A in? Justify. d. What is determinant of A? Justify.arrow_forward2. Consider the matrix: A || 1 1 -3 14 2 1 01 4 1 2 2 -26 1 -3 1 5] a) What is rank(A)? b) Is A invertible? Justify. c) Find the nullspace(A). Justify. d) Is the trivial solution the only solution to Ax=0? Justify. e) What is the span of the column vectors of A? Justify.arrow_forwardE 5. Suppose that S={v € R²: v = [2x² - 3]}. Is S a subspace of R²? Prove or disprovearrow_forward
- 6. Suppose that V1, V2 ER", show that span{v1, v2} is a subspace of Rn.arrow_forwardRa X 2) slots per pole per phase 3/31 180 Ko Sin (1) Kdl 1 sin (4) sin(3) Sin (30) اذا مرید شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120 Fo lasa! G s.1000-950 20:05 1000 Capper losses: 5kw Rotor input lookw 0.05 ined sove in peaper I need a detailed solution on paper please 6) 1 ۳/۱ وه اذا ميريد شرح الكتب فقط look DC 7) rotov Find the general solution of the following equations: +4y=tan2x 3 7357 Find the general solution of the following equations: - Qll y + y (³) = 0. 101arrow_forwardNC Current Students - North Ce X | NC Canvas Login Links - North ( X Final Exam Comprehensive x Cengage Learning x WASTAT - Final Exam - STAT → C webassign.net/web/Student/Assignment-Responses/submit?dep=36055360&tags=autosave#question3659890_9 Part (b) Draw a scatter plot of the ordered pairs. N Life Expectancy Life Expectancy 80 70 600 50 40 30 20 10 Year of 1950 1970 1990 2010 Birth O Life Expectancy Part (c) 800 70 60 50 40 30 20 10 1950 1970 1990 W ALT 林 $ # 4 R J7 Year of 2010 Birth F6 4+ 80 70 60 50 40 30 20 10 Year of 1950 1970 1990 2010 Birth Life Expectancy Ox 800 70 60 50 40 30 20 10 Year of 1950 1970 1990 2010 Birth hp P.B. KA & 7 80 % 5 H A B F10 711 N M K 744 PRT SC ALT CTRLarrow_forward
- B: 18060 msl Kd Ka, Sin (n) I sin () sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120 x 50 G 5005 1000 s = 1000-950 Copper bosses 5kW /0001 Rotor input 5 : loo kw 0.05 6) 1 اذا ميريد شرح الكتب فقط ١٥٠ 7) rotov DC ined sove in Deaper I need a detailed solution on paper please dy x+2y-4 = dx 2x-y-3 Find the general solution of the following equations: 02//yl-4y+13y=esinarrow_forward1) R₂ = X2 2) slots per pole per phase = 3/31 B msl kd 180 60 Kal Sin (1) I sin () sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120 x 50 G 5005 1000 s = 1000-950 Copper bosses 5kW Rotor input: 5 0.05 loo kw 6) 1 /0001 اذا ميريد شرح الكتب فقط look 7) rotov DC ined sove in peaper I need a detailed solution on paper please Q1// Find the solution of: 'y' = x² +376 x4+316 xyo Q2 Find the solution of the initial-valued problems: ex-y y' +exarrow_forwardR₂ = X2 2) slots per pole per phase = 3/31 B-18060 msl kd Kasi Sin (1) I sin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed s = 1000-950 1000 Copper losses: 5kw Rotor input 5 0.05 6) 1 120 x 50 G loo kw ined sove in peaper I need a detailed solution on paper please Q3// x²y// +xy/ + (x² - ½) y = x³/². اذا ميريد شرح الكتب فقط look 7) rotor DC Q4// x²y// - (2x+x²)y/ + (2 + x)y = x³. dy 2x+2y+4 = dx 2x-y-3arrow_forward
- ۳/۱ R2X2 2) slots per pole per phase = 3/31 B, 18060 msl Kas Sin() 1sin() sin(30) Sin (30) kd اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speeds S = 1000-950 1000 Copper bosses 5kw 120*50 loca G Rotor input 5 loo kw 6) 1 0.05 اذا ميريد شرح الكتب فقط lookw 7) rotor DC ined sove in peaper I need a detailed solution on paper please 064 Q1// Find the solution of QI/Find the solution of Inxy= 7357 x+2y³ y' = xy3arrow_forwardR₂ = X2 2) slots per pole per phase 3/31 msl 180 60 Kd Ka Sin (1) Isin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed, 120*50 1000 6 S = 1000-950 1000 Copper bosses: 5kw Rotor input 5 0.05 : loo kw 6) 1 اذا ميريد شرح الكتب فقط 100 7) rotor DC ined sove in peaper I need a detailed solution on paper please Find the general solution of the following equations: Q2lyl-4y+13y=esinx. Find the general solution of the following equations: " Qly (49) - 16y= 0. 151arrow_forward۳/۱ R₂ = X2 2) slots per pole per phase = 3/31 B-18060 msl kd Kasi Sin (1) I sin (6) sin(30) Sin (30) اذا ميريد شرح الكتب بس 0 بالفراغ 3) Cos (30) 0.866 4) Rotating 5) Synchronous speed s = 1000-950 1000 Copper losses: 5kw Rotor input 5 0.05 6) 1 120 x 50 G loo kw اذا میرید شرح الكتب فقط look 7) rotor DC ined sove in peaper I need a detailed solution on paper dy please 04 12=-cosx.y + 2cosx with y(x) = 1 か 'Oy + xlny + xe")dx + (xsiny + xlnx +*dy=0. 01arrow_forward
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