The temperatures between which the 68% of body temperatures fall.

Question

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Answer 1

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 13, Problem 1CS

Section 1

To determine

To find: The temperatures between which the 68% of body temperatures fall.

Section 1

Expert Solution

Answer to Problem 1CS

Solution: The 68% of body temperatures fall between 97.52∘F and 98.98∘F.

Explanation of Solution

Given: The distribution of body temperatures is normal and the mean and standard deviation of the distribution are 98.25∘F and 0.73∘F, respectively.

Calculation:

The 68−95−99.7 rule states that 68% of the data that has normal distribution falls within one standard deviation of the mean. The one standard deviation of the mean is defined as (μ−σ) and (μ+σ).

With the provided values of mean and standard deviation, the range of body temperatures can be obtained in which 68% values of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−σ=98.25−(1×0.73)=98.25−0.73=97.52

and

μ+σ=98.25+(1×0.73)=98.25+0.73=98.98

Therefore, the 68% of body temperatures will fall between 97.52∘F and 98.98∘F.

Section 2

To determine

To find: The temperatures between which the 95% of body temperatures fall.

Section 2

Expert Solution

Answer to Problem 1CS

Solution: The 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Explanation of Solution

Calculation:

The 68−95−99.7 rule states that middle 95% of the data that has normal distribution falls within two standard deviations of the mean. The two standard deviations of the mean are defined as (μ−2σ) and (μ+2σ).

With the given values of mean and standard deviation, the range of body temperatures can be obtained in which 95% value of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−2σ=98.25−(2×0.73)=98.25−1.46=96.79

and

μ+2σ=98.25+(2×0.73)=98.25+1.46=99.71

Therefore, the 95% of body temperatures fall between 96.79∘F and 99.71∘F.

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Answer 2

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 13, Problem 1CS

Section 1

To determine

To find: The temperatures between which the 68% of body temperatures fall.

Section 1

Expert Solution

Answer to Problem 1CS

Solution: The 68% of body temperatures fall between 97.52∘F and 98.98∘F.

Explanation of Solution

Given: The distribution of body temperatures is normal and the mean and standard deviation of the distribution are 98.25∘F and 0.73∘F, respectively.

Calculation:

The 68−95−99.7 rule states that 68% of the data that has normal distribution falls within one standard deviation of the mean. The one standard deviation of the mean is defined as (μ−σ) and (μ+σ).

With the provided values of mean and standard deviation, the range of body temperatures can be obtained in which 68% values of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−σ=98.25−(1×0.73)=98.25−0.73=97.52

and

μ+σ=98.25+(1×0.73)=98.25+0.73=98.98

Therefore, the 68% of body temperatures will fall between 97.52∘F and 98.98∘F.

Section 2

To determine

To find: The temperatures between which the 95% of body temperatures fall.

Section 2

Expert Solution

Answer to Problem 1CS

Solution: The 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Explanation of Solution

Calculation:

The 68−95−99.7 rule states that middle 95% of the data that has normal distribution falls within two standard deviations of the mean. The two standard deviations of the mean are defined as (μ−2σ) and (μ+2σ).

With the given values of mean and standard deviation, the range of body temperatures can be obtained in which 95% value of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−2σ=98.25−(2×0.73)=98.25−1.46=96.79

and

μ+2σ=98.25+(2×0.73)=98.25+1.46=99.71

Therefore, the 95% of body temperatures fall between 96.79∘F and 99.71∘F.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 13, Problem 1CS

Section 1

To determine

To find: The temperatures between which the 68% of body temperatures fall.

Section 1

Expert Solution

Answer to Problem 1CS

Solution: The 68% of body temperatures fall between 97.52∘F and 98.98∘F.

Explanation of Solution

Given: The distribution of body temperatures is normal and the mean and standard deviation of the distribution are 98.25∘F and 0.73∘F, respectively.

Calculation:

The 68−95−99.7 rule states that 68% of the data that has normal distribution falls within one standard deviation of the mean. The one standard deviation of the mean is defined as (μ−σ) and (μ+σ).

With the provided values of mean and standard deviation, the range of body temperatures can be obtained in which 68% values of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−σ=98.25−(1×0.73)=98.25−0.73=97.52

and

μ+σ=98.25+(1×0.73)=98.25+0.73=98.98

Therefore, the 68% of body temperatures will fall between 97.52∘F and 98.98∘F.

Section 2

To determine

To find: The temperatures between which the 95% of body temperatures fall.

Section 2

Expert Solution

Answer to Problem 1CS

Solution: The 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Explanation of Solution

Calculation:

The 68−95−99.7 rule states that middle 95% of the data that has normal distribution falls within two standard deviations of the mean. The two standard deviations of the mean are defined as (μ−2σ) and (μ+2σ).

With the given values of mean and standard deviation, the range of body temperatures can be obtained in which 95% value of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−2σ=98.25−(2×0.73)=98.25−1.46=96.79

and

μ+2σ=98.25+(2×0.73)=98.25+1.46=99.71

Therefore, the 95% of body temperatures fall between 96.79∘F and 99.71∘F.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 13, Problem 1CS

Section 1

To determine

To find: The temperatures between which the 68% of body temperatures fall.

Section 1

Expert Solution

Answer to Problem 1CS

Solution: The 68% of body temperatures fall between 97.52∘F and 98.98∘F.

Explanation of Solution

Given: The distribution of body temperatures is normal and the mean and standard deviation of the distribution are 98.25∘F and 0.73∘F, respectively.

Calculation:

The 68−95−99.7 rule states that 68% of the data that has normal distribution falls within one standard deviation of the mean. The one standard deviation of the mean is defined as (μ−σ) and (μ+σ).

With the provided values of mean and standard deviation, the range of body temperatures can be obtained in which 68% values of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−σ=98.25−(1×0.73)=98.25−0.73=97.52

and

μ+σ=98.25+(1×0.73)=98.25+0.73=98.98

Therefore, the 68% of body temperatures will fall between 97.52∘F and 98.98∘F.

Section 2

To determine

To find: The temperatures between which the 95% of body temperatures fall.

Section 2

Expert Solution

Answer to Problem 1CS

Solution: The 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Explanation of Solution

Calculation:

The 68−95−99.7 rule states that middle 95% of the data that has normal distribution falls within two standard deviations of the mean. The two standard deviations of the mean are defined as (μ−2σ) and (μ+2σ).

With the given values of mean and standard deviation, the range of body temperatures can be obtained in which 95% value of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−2σ=98.25−(2×0.73)=98.25−1.46=96.79

and

μ+2σ=98.25+(2×0.73)=98.25+1.46=99.71

Therefore, the 95% of body temperatures fall between 96.79∘F and 99.71∘F.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 13, Problem 1CS

Section 1

To determine

To find: The temperatures between which the 68% of body temperatures fall.

Section 1

Expert Solution

Answer to Problem 1CS

Solution: The 68% of body temperatures fall between 97.52∘F and 98.98∘F.

Explanation of Solution

Given: The distribution of body temperatures is normal and the mean and standard deviation of the distribution are 98.25∘F and 0.73∘F, respectively.

Calculation:

The 68−95−99.7 rule states that 68% of the data that has normal distribution falls within one standard deviation of the mean. The one standard deviation of the mean is defined as (μ−σ) and (μ+σ).

With the provided values of mean and standard deviation, the range of body temperatures can be obtained in which 68% values of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−σ=98.25−(1×0.73)=98.25−0.73=97.52

and

μ+σ=98.25+(1×0.73)=98.25+0.73=98.98

Therefore, the 68% of body temperatures will fall between 97.52∘F and 98.98∘F.

Section 2

To determine

To find: The temperatures between which the 95% of body temperatures fall.

Section 2

Expert Solution

Answer to Problem 1CS

Solution: The 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Explanation of Solution

Calculation:

The 68−95−99.7 rule states that middle 95% of the data that has normal distribution falls within two standard deviations of the mean. The two standard deviations of the mean are defined as (μ−2σ) and (μ+2σ).

With the given values of mean and standard deviation, the range of body temperatures can be obtained in which 95% value of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−2σ=98.25−(2×0.73)=98.25−1.46=96.79

and

μ+2σ=98.25+(2×0.73)=98.25+1.46=99.71

Therefore, the 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Answer 6

Chapter 13, Problem 1CS

Section 1

To determine

To find: The temperatures between which the 68% of body temperatures fall.

Section 1

Expert Solution

Answer to Problem 1CS

Solution: The 68% of body temperatures fall between 97.52∘F and 98.98∘F.

Explanation of Solution

Given: The distribution of body temperatures is normal and the mean and standard deviation of the distribution are 98.25∘F and 0.73∘F, respectively.

Calculation:

The 68−95−99.7 rule states that 68% of the data that has normal distribution falls within one standard deviation of the mean. The one standard deviation of the mean is defined as (μ−σ) and (μ+σ).

With the provided values of mean and standard deviation, the range of body temperatures can be obtained in which 68% values of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−σ=98.25−(1×0.73)=98.25−0.73=97.52

and

μ+σ=98.25+(1×0.73)=98.25+0.73=98.98

Therefore, the 68% of body temperatures will fall between 97.52∘F and 98.98∘F.

Answer 7

Chapter 13, Problem 1CS

Section 1

To determine

To find: The temperatures between which the 68% of body temperatures fall.

Answer 8

Section 1

Expert Solution

Answer to Problem 1CS

Solution: The 68% of body temperatures fall between 97.52∘F and 98.98∘F.

Answer 9

Section 1

Expert Solution

Answer 10

Section 1

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given: The distribution of body temperatures is normal and the mean and standard deviation of the distribution are 98.25∘F and 0.73∘F, respectively.

Calculation:

The 68−95−99.7 rule states that 68% of the data that has normal distribution falls within one standard deviation of the mean. The one standard deviation of the mean is defined as (μ−σ) and (μ+σ).

With the provided values of mean and standard deviation, the range of body temperatures can be obtained in which 68% values of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−σ=98.25−(1×0.73)=98.25−0.73=97.52

and

μ+σ=98.25+(1×0.73)=98.25+0.73=98.98

Therefore, the 68% of body temperatures will fall between 97.52∘F and 98.98∘F.

Answer 13

Section 2

To determine

To find: The temperatures between which the 95% of body temperatures fall.

Section 2

Expert Solution

Answer to Problem 1CS

Solution: The 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Explanation of Solution

Calculation:

The 68−95−99.7 rule states that middle 95% of the data that has normal distribution falls within two standard deviations of the mean. The two standard deviations of the mean are defined as (μ−2σ) and (μ+2σ).

With the given values of mean and standard deviation, the range of body temperatures can be obtained in which 95% value of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−2σ=98.25−(2×0.73)=98.25−1.46=96.79

and

μ+2σ=98.25+(2×0.73)=98.25+1.46=99.71

Therefore, the 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Answer 14

Section 2

To determine

To find: The temperatures between which the 95% of body temperatures fall.

Answer 15

Section 2

Expert Solution

Answer to Problem 1CS

Solution: The 95% of body temperatures fall between 96.79∘F and 99.71∘F.

Answer 16

Section 2

Expert Solution

Answer 17

Section 2

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Calculation:

The 68−95−99.7 rule states that middle 95% of the data that has normal distribution falls within two standard deviations of the mean. The two standard deviations of the mean are defined as (μ−2σ) and (μ+2σ).

With the given values of mean and standard deviation, the range of body temperatures can be obtained in which 95% value of the body temperatures will fall.

The range of the body temperatures will be calculated as

μ−2σ=98.25−(2×0.73)=98.25−1.46=96.79