Explanation Given data: Mass of the car is 980 kg and the pressure in the tires is 3.0 × 10 5 N/m 2 . Formula used: The expression for pressure is: P = F A Here, P is the pressure, F is the force and A is the area of the cross-section. The expression for the weight of the object is: W = m g Here, m is the mass of the object and g is the acceleration due to gravity. The value of acceleration due to gravity is 9.81 m/s 2 . Explanation: Assuming the car has 4 tires. Recall the expression for the weight of the car, W = m g Substitute 980 kg for m and 9.81 m/s 2 for g in the above expression. W = ( 980 kg ) ( 9.81 m/s 2 ) = 9613.8 N Since, the car has 4 tires, the load on each tire is: W each = W 4 Substitute 9613.8 N for W , W each = ( 9613.8 N ) 4 = 2403.45 N Recall the expression for the pressure in the tyres of the car, P = F A Rearrange the above expression for F , F = P A Substitute 3

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Chapter 13, Problem 15P

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The average area of contact of each tire with the road if the air pressure in the tires of a 980 kg car is 3.0×105 N/m2. Also, indicate the assumptions.

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Chapter 13 Solutions

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The average area of contact of each tire with the road if the air pressure in the tires of a 980 kg car is 3.0 × 10 5 N/m 2 . Also, indicate the assumptions.

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The average area of contact of each tire with the road if the air pressure in the tires of a 980 kg car is 3.0×105 N/m2. Also, indicate the assumptions.

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Chapter 13 Solutions