Interpretation: The expected boiling point and freezing point of sugar solution are to be calculated, the deviation of boiling point of syrup and boiling point of pure water is to be explained and also the freezing of syrup at
Concept Introduction: Colligative properties of a solution depend upon the amount of solute present in the solution irrespective of its nature.
They are of 4 types, freezing point depression, boiling point elevation, lowering of vapor pressure and osmotic pressure.
On addition of a non-volatile solute, the physical properties of a pure solvent get altered and extends the temperature range over which it can remain a liquid.
The molality of any solution can be given as:
The freezing point depression of a solution is given by the expression:
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Introductory Chemistry (6th Edition)
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- 1.) Using the graph below (including the line equation of y = -1.823x - 0.0162) What is the numerical value for the slope shown? 2.) What are the Unit(s) associated with the slope of the line shown? for we all remember that numerical data always has units. 3.) What would be a good title for this graph and explain your choice. 0.00 0.0 02 0.4 10.6 08 10 12 -0.20 -0.40 -0.60 -0.80 Temp, freezing, in degrees Celcius 5-1.00 -1.20 -1.40 -1:60 y=-1.823x-0.0162 -180 -2.00 Concentration of Sucrose (m)arrow_forwardDon't used Ai solutionarrow_forwardIdentify the Functional Groups (FG) in the following molecules. Classify C atoms as tertiary, 30, or quaternary 40. Identify secondary 20 and tertiary, 30 hydrogen atoms. Please provide steps to undertand each labeling. Please label in the image, so it fits explanation. I am still very unsure I undertand this.arrow_forward
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