Organic Chemistry
4th Edition
ISBN: 9780073402772
Author: Janice G. Smith
Publisher: MCG
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Chapter 13, Problem 13.50P
Reaction of 2-methylpropanoic acid
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Treatment of benzoic acid (C6H5CO2H) with NaOH followed by 1-iodo-3methylbutane forms H. H has a molecular ion at 192 and IR absorptions at 3064, 3035, 2960−2872, and 1721 cm−1. Propose a structure for H.
A solution of acetone [(CH3)2C = O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?
A solution of acetone [(CH3)2C=O] in ethanol (CH3CH2OH) in the presence of a trace of acid was allowed to stand for several days, and a new compound of molecular formula C7H16O2 was formed. The IR spectrum showed only one major peak in the functional group region around 3000 cm−1, and the 1H NMR spectrum is given here. What is the structure of the product?
Chapter 13 Solutions
Organic Chemistry
Ch. 13 - What is the mass of the molecular ion formed from...Ch. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - What molecular ions would you expect for the...Ch. 13 - The mass spectrum of 2,3-dimethylpentane also...Ch. 13 - The base peak in the mass spectrum of 2, 2,...Ch. 13 - (a) What mass spectral fragments are formed by ...Ch. 13 - What cations are formed in the mass spectrometer...Ch. 13 - The low-resolution mass spectrum of an unknown...Ch. 13 - Benzene, toluene, and p-xylene BTX are often added...
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - How do the IR spectra of the isomers cyclopentane...Ch. 13 - How do the three isomers of molecular formula...Ch. 13 - Problem 13.18 What functional groups are...Ch. 13 - Problem-13.19 What are the major IR absorptions in...Ch. 13 - Problem-13.20 What are the major IR absorptions in...Ch. 13 - Prob. 13.20PCh. 13 - Problem-13.22 Propose structures consistent with...Ch. 13 - 13.23 What major IR absorptions are present above ...Ch. 13 - Problem-13.24 The mass spectrum of the following...Ch. 13 - What molecular ion is expected for each compound?Ch. 13 - Which compound gives a molecular ion at m/z= 122,...Ch. 13 - Propose two molecular formulas for each molecular...Ch. 13 - Propose four possible structures for a hydrocarbon...Ch. 13 - Match each structure to its mass spectrum. a. b....Ch. 13 - 13.32 Propose two possible structures for a...Ch. 13 - 13.33 What cations are formed in the mass...Ch. 13 - 13.35 For each compound, assign likely...Ch. 13 - Prob. 13.32PCh. 13 - 13.37 Propose a structure consistent with each...Ch. 13 - 13.38 A low-resolution mass spectrum of the...Ch. 13 - Can the exact mass obtained in a high-resolution...Ch. 13 - 13.39 Primary alcohols often show a peak in their...Ch. 13 - 13.40 Like alcohols, ethers undergo α cleavage by...Ch. 13 - Which of the highlighted bonds absorbs at higher v...Ch. 13 - What major IR absorptions are present above...Ch. 13 - How would each of the following pairs of compounds...Ch. 13 - 13.44 Morphine, heroin, and oxycodone are three...Ch. 13 - Prob. 13.42PCh. 13 - 13.47 Match each compound to its IR spectrum
Ch. 13 - 13.48 Propose possible structures consistent with...Ch. 13 - A chiral hydrocarbon X exhibits a molecular ion at...Ch. 13 - 13.50 A chiral compound has a strong absorption...Ch. 13 - 13.51 Treatment of benzoic acid with followed by...Ch. 13 - 13.52 Treatment of benzaldehyde with in aqueous ...Ch. 13 - Prob. 13.49PCh. 13 - 13.54 Reaction of 2-methylpropanoic acid with ...Ch. 13 - 13.55 Reaction of pentanoyl chloride with lithium...Ch. 13 - Prob. 13.52PCh. 13 - 13.57 Treatment of anisole with and forms P,...Ch. 13 - 13.58 Reaction of with forms compound ,...Ch. 13 - Problem-13.59 The carbonyl absorption of an amide...Ch. 13 - Prob. 13.56PCh. 13 - Problem-13.61 Explain why a ketone carbonyl...Ch. 13 - 13.62 Oxidation of citronellol, a constituent of...
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- Nitriles, R–=C≡N, undergo a hydrolysis reaction when heated with aqueous acid. What is the structure of the compound produced by hydrolysis of propanenitrile, CH3CH2C≡N, if it has IR absorptions from 2500–3100 cm-1 and at 1710 cm-1, and has M+=74?arrow_forwardCompound I (C11H14O2) is insoluble in water, aqueous acid, and aqueous NaHCO3, but dissolves readily in 10% Na2CO3 and 10% NaOH. When these alkaline solutions are acidified with 10% HCl, compound I is recovered unchanged. Given this information and its 1H-NMR spectrum, deduce the structure of compound I.arrow_forwardThe following sequence of steps converts (R)-2-octanol to (S)-2-octanol. Propose structural formulas for intermediates A and B, specify the configuration of each, and account for the inversion of configuration in this sequence.arrow_forward
- Treatment of ketone A with ethynyllithium (HC≡CLi) followed by D3O+ afforded a compound B of molecular formula C12H13DO3, which gave an IR absorption at approximately 1715 cm−1. What is the structure of B and how is it formed?arrow_forwardTreatment of 2-methylpropanenitrile [(CH3)2CHCN] with CH3CH2CH2MgBr, followed by aqueous acid, affords compound V, which has molecular formula C7H14O. V has a strong absorption in its IR spectrum at 1713 cm−1, and gives the following 1H NMR data: 0.91 (triplet, 3 H), 1.09 (doublet, 6 H), 1.6 (multiplet, 2 H), 2.43 (triplet, 2 H), and 2.60 (septet, 1 H) ppm. What is the structure of V? We will learn about this reaction in Chapter 20.arrow_forward: Treatment of (CHa)CHCH(OH)CH,CH3 with TSOH affords two products (M and N) with molecular formula CgH12. The 'H NMR spectra of M and N are given below. Propose structures for M and N and draw a mechanism to explain their formation. 1H NMR of M 3H 1H NMR of N 3H 3H 3 H 1H 3 H 2 H 2H 2H 8 7 6 4 1 0 9 8. 2 1 ppm ppm 4.arrow_forward
- Reaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed by treatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is the structure of R? We will learn about this reaction in Chapter 18.arrow_forwardAs reaction of (CH3)2CO with LIC≡CH followed by H2O affords compound D, which has a molecular ion in its mass spectrum at 84 and prominent absorptions in its IR spectrum at 3600−3200, 3303, 2938, and 2120 cm−1. D shows the following 1H NMR spectral data: 1.53 (singlet, 6 H), 2.37 (singlet, 1 H), and 2.43 (singlet, 1 H) ppm. What is the structure of D?arrow_forwardIdentify the structures of isomers A and B, whose molecular formula is C10 H12 O2, from IR spectroscopic data and their H-NMR spectra.arrow_forward
- A hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?arrow_forwardReaction of (CH3)3CCHO with (C6H5)3P=C(CH3)OCH3, followed bytreatment with aqueous acid, affords R (C7H14O). R has a strong absorption in its IR spectrum at 1717 cm−1 and three singlets in its 1H NMR spectrum at 1.02 (9 H), 2.13 (3 H), and 2.33 (2 H) ppm. What is thestructure of R?arrow_forwardThymol (molecular formula C10H14O) is the major component of the oil ofthyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose apossible structure for thymol.arrow_forward
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