Engineering Electromagnetics
9th Edition
ISBN: 9781260029963
Author: Hayt
Publisher: MCG
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Textbook Question
Chapter 13, Problem 13.30P
A step index optical fiber is known to be single mode at wave-lengths
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A single mode fibre is to be dimensioned. The normalised frequency is 80 % of the maximum allowed for single mode condition. The relative
refractive index difference is 0.005 and the refractive index of the core is 1.5. The wavelength is 1.5 µm.
A. Determine the radius of the core.
B. If the number of modes supported by this fiber is 5. Determine the radius of the core.
3.9 Explain what is meant by the critical bending radius for an optical fiber. A
multimode graded index fiber has a refractive index at the core axis of 1.46 with a
cladding refractive index of 1.45. The critical radius of curvature which allows large
bending losses to occur is 84 um when the fiber is transmitting light of a particular
wavelength. Determine the wavelength of the transmitted light.
Ans: 0.86 µm
2.27 Calculate the number of modes at 820 nm
and 1.3 µm in a graded-index fiber having a
parabolic-index profile (a= 2), a 25-µm core
radius, n = 1.48, and nɔ = 1.46. How does this
compare to a step-index fiber?
Chapter 13 Solutions
Engineering Electromagnetics
Ch. 13 - The conductors of a coaxial transmission line are...Ch. 13 - Prob. 13.2PCh. 13 - Prob. 13.3PCh. 13 - Find R, L, C, and G for a two-wire transmission...Ch. 13 - Prob. 13.5PCh. 13 - Consider an air-filled coaxial transmission line...Ch. 13 - Pertinent dimensions for the transmission line...Ch. 13 - A transmission line constructed from perfect...Ch. 13 - Prob. 13.9PCh. 13 - Two microstrip lines are fabricated end-to-end on...
Ch. 13 - Prob. 13.11PCh. 13 - Prob. 13.12PCh. 13 - Prob. 13.13PCh. 13 - Prob. 13.14PCh. 13 - For the guide of Problem 13.14, and at the 32 GHz...Ch. 13 - Prob. 13.16PCh. 13 - A parallel-plate guide is partially filled with...Ch. 13 - Prob. 13.18PCh. 13 - Prob. 13.19PCh. 13 - Two rectangular waveguides are joined end-to-end....Ch. 13 - Prob. 13.21PCh. 13 - Consider the TE11 mode in a rectangular guide...Ch. 13 - Prob. 13.23PCh. 13 - Prob. 13.24PCh. 13 - Prob. 13.25PCh. 13 - Prob. 13.26PCh. 13 - Prob. 13.27PCh. 13 - Prob. 13.28PCh. 13 - An asymmetric slab waveguide is shown in Figure...Ch. 13 - A step index optical fiber is known to be single...Ch. 13 - Prob. 13.31PCh. 13 - Prob. 13.32P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, electrical-engineering and related others by exploring similar questions and additional content below.Similar questions
- Q3: An SI MM fiber has a core of 59.5 um diameter and a ncore = neladding = 1.29. find The number of modes that would occur using a light of wavelength of 880 nm? 1.324 andarrow_forwardFor multimode step-index fiber with core index of 1.68 and radius of 35 um. The index difference is 3.75%. For a wavelength of 1150 nm, the optical power propagating in cladding is what percentage of total power? (a) 2.1% (b) 2.5% (c) 1.8% (d) 1.4%arrow_forwardA cross-sectional view of an optical fiber is shown in the figure. The optical fiber has core and cladding refractive indices of ncore and neladding, and critical angle Oic. Which of the following conditions must be satisfied in order to have total internal reflection in the optical fiber? a ncore > Ncladding Oi > Oịc cladding (b) ncore > Ncladding O; Oịc (e) None of the abovearrow_forward
- c) Evaluate the light collecting capacity of a silica fibre with its core refractiveindex (n1) of 1.48 and cladding refractive index of 1.46. Evaluate the newvalue of “n1” in order to change the light collecting capacity to 0.23.arrow_forwardFigure: structure of a thin film silicon solar cell. Glass Front ITO i (aSi:H) back ZnO:AI 1-D PC The figure above shows a schematic overview of an thin film single junction solar cell. Upon what principle is the back reflector of this solar cell based? The principle of the back reflector is based on refractive scattering. ) The principle of the back reflector is based on diffractive scattering. ) The principle of the back reflector is based on constructive/destructive interference. The principle of the back reflector is based on plasmonic scatteringarrow_forwardPls Help!arrow_forward
- qarrow_forwardP 2.7a What will be the cutoff wavelength for dominant mode in rectangular waveguide whose length is 10 cm? (2)arrow_forwardDetermine the cutoff wavelength for a step-index fiber to exhibit single-mode operation when the core refractive index is 1.46 and the core radius is 4.5 um, with the relative index difference of 0.25 %.arrow_forward
- Solve the 1st part of the question , by finding the optical loss . This is the solution you provided , but please solve 3a . You told we need to consider 3.5 and 1.48 and solve . Please solve the 1st part ONLY .arrow_forwardshow complete solution Derive the expressions for the Ex, Ey, Bx, By in Waveguides.arrow_forwardd = mλ 2 cos 0' 1.3 Using the above formula for the conventional Bragg condition, show that each pair in a multilayer reflector should be 6.8 nm thick to produce peak reflectivity at a wavelength of 13.5 nm when the incident light is 6° from normal. (Assume that m = 1.) Show that a change in the film-pair thickness of 1 Å changes the peak wavelength by 0.2 nm.arrow_forward
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