BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD)
BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD)
8th Edition
ISBN: 9781337687539
Author: Brown/Iverson/Anslyn/ Foote
Publisher: CENGAGE C
bartleby

Videos

Textbook Question
Book Icon
Chapter 13, Problem 13.24P

Write structural formulas for the following compounds.

  1. (a) C2H4Br2:    δ 2.5 (d, 3H) and 5.9 (q, 1H)
  2. (b) C4HgCl2:    δ 1.60 (d, 3H), 2.15 (m, 2H), 3.72 (t, 2H), and 4.27 (m, 1H)
  3. (c) C5H8Br4:    δ 3.6 (s, 8H)
  4. (d) C4H8O:    δ 1.0 (t, 3H), 2.1 (s, 3H), and 2.4 (quartet, 2H)
  5. (e) C4H8O2:    δ 1.2 (t, 3H), 2.1 (s, 3H), and 4.1 (quartet, 2H); contains an ester
  6. (f) C4H8O2:    δ 1.2 (t, 3H), 2.3 (quartet, 2H), and 3.6 (s, 3H); contains an ester
  7. (g) C4H9Br:    δ 1.1 (d, 6H), 1.9 (m, 1H), and 3.4 (d, 2H)
  8. (h) C6H12O2:    δ 1.5 (s, 9H) and 2.0 (s, 3H)
  9. (i) C7H14O:    δ 0.9 (t, 6H), 1.6 (sextet, 4H), and 2.4 (t, 4H)
  10. (j) C5H10O2:    δ 1.2 (d, 6H), 2.0 (s, 3H), and 5.0 (septet, 1H)
  11. (k) C5H11Br:    δ 1.1 (s, 9H) and 3.2 (s, 2H)
  12. (l) C7H15Cl    δ 1.1 (s, 9H) and 1.6 (s, 6H)

(a)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (a) is C2H4Br2.

There are 2 peaks observed in the given 1H NMR data’s thus 2 sets of non-equivalent protons are present in the molecule.

A doublet is observed for 3 hydrogens at around δ2.5 ppm that indicate the presence of methyl (-CH3) group.

Another quartet peak for 1 hydrogen at around 5.9 ppm is observed that corresponds to the (-CH) group it is attached with halogen group.

Based on the above 1H NMR spectral details, the structural formula for compound (a) is:

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  1

(b)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (b) is C4H8Cl2.

A doublet is observed for 3 hydrogens at around δ1.60 ppm that indicate the presence of methyl (-CH3) group.

A multiplet is observed for 2 hydrogens at around 2.15 ppm that indicates that has the adjacent groups (CH2) containing a total of two hydrogens.

One triplet peak is observed for 2 hydrogens at around 3.72 ppm that indicates the presence (CH2) group adjacent to it as per the (N+1) rule.

Another multiplet is observed for 1 hydrogen at around 4.27 ppm that indicates that has the adjacent groups (CH) containing a total of one hydrogen.

Thus, the structure of the compound (b) is 1,3-dichlorobutane:

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  2

(c)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (c) is C4H8Br2.

This molecule only one singlet is observed for 8 hydrogens at around δ3.6 ppm that indicate the presence of (CH2Br) groups it is containing a total of eight hydrogens.

Therefore, the structure of the compound (c) is given below and this molecule symmetrical.

  BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  3

(d)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (d) is C4H8O.

A triplet is observed for 3 hydrogens at around δ1.0 ppm that indicate the presence of methyl (-CH3) group.

One singlet is observed for 3 hydrogens at around δ2.1 ppm that indicate the presence of another one methyl (-CH3) group.

Another quartet is observed for 2 hydrogens at around 2.40ppm that indicates that has the adjacent groups (CH2) containing a total of two hydrogens.

Thus, the structure of the compound (d) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  4

(e)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (e) is C4H8O2.

A triplet is observed for 3 hydrogens at around δ1.2 ppm that indicate the presence of methyl (-CH3) group.

One singlet is observed for 3 hydrogens at around δ2.1 ppm that indicate the presence of another one ester methyl (-CH3) group.

Another quartet is observed for 2 hydrogens at around 2.40ppm that indicates that has the ester (CH2) groups it is containing a total of two hydrogens.

Thus, the structure of the compound (e) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  5

(f)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (f) is C4H8O2.

A triplet is observed for 3 hydrogens at around δ1.2 ppm that indicate the presence of methyl (-CH3) group.

One singlet is observed for 3 hydrogens at around δ4.1 ppm that indicate the presence of ester methyl (-O-CH3) group.

Another quartet is observed for 2 hydrogens at around 2.3ppm that indicates that has the (CH2) groups it is containing a total of two hydrogens.

Thus, the structure of the compound (f) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  6

(g)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (g) is C4H9Br.

A doublet is observed for 6 hydrogens at around δ1.1 ppm that indicate the presence of two methyl (-CH3) groups.

One multiplet is observed for 1 hydrogen at around δ1.9 ppm that indicate the presence of (-CH-) group.

Another multiplet is observed for 2 hydrogens at around 3.4ppm that indicates that has the (CH2) groups it is containing a total of two hydrogens.

Thus, the structure of the compound (g) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  7

(h)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (h) is C6H12O2.

A singlet is observed for 9 hydrogens at around δ1.5 ppm that indicate the presence of tertiary (-CH3) groups.

Another one singlet is observed for 3 hydrogens at around δ2.0 ppm that indicate the presence of (-CH3) group.

Thus, the structure of the compound (h) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  8

(i)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (i) is C7H14O.

A singlet is observed for 6 hydrogens at around δ0.9 ppm that indicate the presence of two (-CH3) groups.

One sextet is observed for 4 hydrogens at around δ1.6 ppm that indicate the presence of (-CH2) group.

Another triplet peak for 4 hydrogens at around 2.4 ppm is observed that corresponds to the (CH2) group.  A triplet is observed because the group (CH2) must have been adjacent to the methyl group.

Thus, the structure of the compound (i) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  9

(j)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (J) is C5H10O2.

A doublet is observed for 6 hydrogens at around δ1.2 ppm that indicate the presence of two (-CH3) groups.

One septet is observed for 1 hydrogen at around δ2.0 ppm that indicate the presence of (-CH) group.

Another singlet peak for 3 hydrogens at around 2.0 ppm is observed that corresponds to the (CH3) group.  A triplet is observed because the group (-C=O) must have been adjacent to the methyl group.

Thus, the structure of the compound (J) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  10

(k)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (K) is C5H10Br.

A singlet is observed for 9 hydrogens at around δ1.1 ppm that indicate the presence of three (-CH3) groups.

One singlet is observed for 2 hydrogens at around δ3.2 ppm that indicate the presence of (-CH2) group.

Thus, the structure of the compound (K) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  11

(l)

Expert Solution
Check Mark
Interpretation Introduction

Interpretation:

The structural formula of the given compound has to be proposed with the help of given molecular formula and  its 1H NMR spectral data.

Concept introduction:

The 1H NMR spectrum of a compound provides some vital information that is required to predict the structure of the compound.  The chemical shift values can predict the groups that are present in the molecule.  The splitting of signals as per the (N+1) rule predicts the number of hydrogens or protons attached to the adjacent carbon in a carbon chain of a compound.  With this information, the structure of the compound can be predicted.

Chemical shift: The NMR spectrum of any compound is taken with reference to a standard compound called reference compound.  Generally, tetramethylsilane (TMS) is taken as the reference compound.  The methyl protons of TMS are equivalent and produces only one sharp peak at the rightmost end of the scale.

The distance between the TMS signal and the signals produced by the compound is called the chemical shift.  Chemical shift basically measures the shift in the signal position of the compound with respect to the reference signal.

Chemical shift in delta scale is given as,

chemical shift,δ(ppm)=distance from the TMS signal(Hz)operating frequency of the spectrometer (MHz)

Explanation of Solution

The given molecular formula (L) is C5H10Cl.

A singlet is observed for 9 hydrogens at around δ1.1 ppm that indicate the presence of three (-CH3) groups.

One singlet is observed for 6 hydrogens at around δ1.6 ppm that indicate the presence of (-CH3) group.

Thus, the structure of the compound (L) is,

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD), Chapter 13, Problem 13.24P , additional homework tip  12

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Which of the following matches the given data?    13C: δ 73, 68, 65, 62, 58, 55, 53, 50   1H: δ 3.74 (s, 1H, broad), 2.11 (q, 2H), 2.09 (s, 2H), 1.43 (t, 2H), 1.31 (t, 2H), 1.00 (s, 6H)
Calculate AHrxn for the following reaction: 5C(s) + 6H2 (g) > С;Н12 (1) Use the following reactions and given AH values: C; H12 (1) + 802 (g) → 5CO2 (g) + 6H2O(g), C(s) + O2 (g) → CO2(g), 2H2 (в) + О-(g) — 2H20(g), ΔΗ -3244.8 kJ ΔΗ -393.5 kJ ΔΗ -483.5 kJ Express your answer to four significant figures in kilojoules.
Given the following reactions and their enthalpies: ΔΗ (k/mol) H2(g) O2(g) 2H(g) 20(g) +436 +495 1 H>(g) + 02(g) → H;O(g) -242 (a) Devise a way to calculate AH for the reaction H,O(g) 2H(g) + O(g) (b) From this, estimate the H -0 bond energy.

Chapter 13 Solutions

BNDL: ACP ORGANIC CHEMISTRY:CH EM 231(W/ACCESS CARD)

Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax
Text book image
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Group Theory - Learn like Expert with 3D animation | Introduction for Beginners | ONE Chemistry; Author: One Chemistry;https://www.youtube.com/watch?v=Lz2ih8fkgDs;License: Standard YouTube License, CC-BY