When a protease enzyme acts on a peptide bond the enzyme increases the rate of the peptide bond breaking reaction. Concept introduction: Proteolysis is the breakdown of proteins into smaller polypeptides or amino acids. Uncatalysed, the hydrolysisof peptide bondsis extremely slow and takes even hundreds of years. Proteolysis is typically catalyzed by cellular enzymes called proteases, but may also occur by intra-molecular digestion. Low pH or high temperatures can also called proteolysis non-enzymatically. The time is taken for half of the reaction to complete for a first-order reaction is independent of the initial concentration. To determine: By what factor the enzyme increases the rate of the peptide bond breaking reactionif these half-lives correspond to first order reactions.

Question

Want to see the full answer?

Answer 1

Question

Chapter 13, Problem 13.141CP

Interpretation Introduction

Interpretation:

When a protease enzyme acts on a peptide bond the enzyme increases the rate of the peptide bond breaking reaction.

Concept introduction:

Proteolysis is the breakdown of proteins into smaller polypeptides or amino acids. Uncatalysed, the hydrolysisof peptide bondsis extremely slow and takes even hundreds of years.

Proteolysis is typically catalyzed by cellular enzymes called proteases, but may also occur by intra-molecular digestion. Low pH or high temperatures can also called proteolysis non-enzymatically.

The time is taken for half of the reaction to complete for a first-order reaction is independent of the initial concentration.

To determine:

By what factor the enzyme increases the rate of the peptide bond breaking reactionif these half-lives correspond to first order reactions.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

A solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol). a) Write a balanced net reaction that can occur between species in this solution. b) Calculate deltaG0 and K for the reaction. c) Calculate E and deltaG for the conditions given. Ce4+ + e- = Ce3+ E0= 1.70 V MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 V

1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in the following reaction. Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is a weak base used to neutralize strong acid (pKa < 0) produced by the reaction. Redraw the product to show the configuration(s) that form at C-2 and C-4. Br2 OH CH2Cl2 Na* HCO3 Br HO OH + Na Br +

2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each reagent set. If a reaction cannot be carried out with reagents (sets) class, write NP (not possible) in the solvent box for reagent set #1. Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s). Solvents: CH2Cl2 (A); H₂O (B); Reagents: HBr (1); R₂BH (6); H2SO4 (2); CH3OH (C); Br₂ (3); CH3CO₂H (D) NaHCO3 (4); Hg(OAc)2 (5); H₂O2/HO (7); NaBH4 (8) Reagent Set #1 Reagent Set #2 FGI + enant OH Solvent Reagent(s) Solvent Reagent(s)