Concept explainers
Interpretation:
The freezing point, boiling point and osmotic pressure of glucose are to be calculated.
Concept introduction:
The freezing point is the temperature at which both the solid and liquid phases coexist in equilibrium. It is the temperature at which the vapor pressure of the substance in the liquid state becomes equal to the vapor pressure in a solid state.
The formula to calculate the change in freezing point is as follows:
Here,
The boiling point of the substance is the temperature at which the vapor pressure of the liquid becomes equal to the atmospheric pressure and the liquid changes into a vapor. Liquids can change into vapors at temperatures below the boiling point through evaporation. It is the process that occurs on the liquid surface due to which it changes into vapors. Both boiling and freezing points are colligative properties because these depend on the number of moles of solute particles that are present in the substance.
The formula to calculate the change in boiling point is as follows:
Here,
The osmotic pressure is defined as the measure of the tendency of a solution to take in pure solvent via osmosis. It is defined as the minimum pressure that is to be applied to the solution to prevent the inward flow of the pure solvent across the semipermeable membrane. Osmosis occurs when two solutions have different concentrations of solute and are separated by a semipermeable membrane.
The formula to calculate the osmotic pressure of the solution is as follows:
Here,
The conversion factor to convert

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Chapter 13 Solutions
CHEMISTRY/ALEKS AND CONNECT
- What is the pH at the cathode for the following cell written in line notation at 25.0 oC with a Ecell = -0.2749 V? Ni(s)|Ni+2(aq, 1.00 M)||H+1(aq, ?M)|H2(g, 1.00 atm)|Pt(s)arrow_forwardCalculate Ecell for a hydrogen fuel cell at 95.0 oC using the following half-reactions with PH2 = 25.0 atm and PO2 = 25.0 atm. O2(g) + 4H+1(aq) + 4e-1 → 2H2O(l) Eo = 1.229 V 2H2(g) → 4H+1(aq) + 4e-1 Eo = 0.00 Varrow_forwardCalculate Ecell at 25.0 oC using the following half-reactions with [Ag+1] = 0.0100 M and [Sn+2] = 0.0200 M. Ag+1(aq) + 1e-1 Ag(s) Sn+2(aq) + 2e-1 Sn(s)arrow_forward
- Done 18:19 www-awu.aleks.com Chapter 12 HW Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited .. LTE סוי 9 ✓ 20 ✓ 21 × 22 23 24 25 26 27 28 29 30 Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Classify each carbon atom as a 1º, 2º, 3º, or 4°. Highlight in red any 1° carbons, highlight in blue any 2° carbons. highlight in green any 3° carbons, and leave any 4° carbons unhighlighted. Skip Part Check Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use Privacy Center | Accessibility ☑ คarrow_forward< Done 19:22 www-awu.aleks.com Chapter 12 HW Question 4 of 39 (2 points) | Question Attempt: 5 of Unlimited : .. LTE סוי 1 ✓ 2 ✓ 3 = 4 ✓ 5 ✓ 6 ✓ 7 ✓ 8 ✓ 9 = 10 11 ✓ 12 Consider the molecule (CH3)2CHCH2CHCн for the following questions. Part 1 of 2 Which of the following molecules is/are constitutional isomer(s) to (CH3)2CHCH2CH2CH3? Check all that apply. Part 2 of 2 (CH3),C(CH2)2CH3 CH3 H,C-CH-CH-CH, CH 3 None of the above. ☑ Which of the following molecules is/are identical molecules to (CH3)2CHCH2CH2CH₁₂? Check all that apply. CH3 H,C-CH-CH₂-CH2-CH, CH3(CH2)2CH(CH3)2 CH2-CH2-CH3 HỌC-CH=CH, 乂 ☑ а None of the above Check Save For Later Submit Assignment © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accessibilityarrow_forward18:11 LTE ا... US$50 off hotels is waiting for you Book now, hotels in Nashville are going fast QUTSLIVII 25 61 69 points) | QuestIVIT ALLēm... now Give the IUPAC name for each compound. Part 1 of 3 Part 2 of 3 X ☑ Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS CT US ...vacy Center | Accessibilityarrow_forward
- Done 19:17 www-awu.aleks.com Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimited .III LTE סוי 27 28 = 29 30 31 32 = 33 34 35 Consider this structure. CH3CH2CH2 Part 1 of 3 3 CH2 CH2CH3 - C-CH2CH 3 H CH₂ Give the IUPAC name of this structure. 3-ethyl-3,4-dimethylheptane Part: 1/3 Part 2 of 3 Draw the skeletal structure. Skip Part < Check Click and drag to start drawing a structure. Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility Хarrow_forward18:57 .III LTE www-awu.aleks.com Chapter 12 HW Question 31 of 39 (8 points) | Question Attem... Give the IUPAC name of each compound. Part 1 of 4 Part 2 of 4 Х Х Check Save For Later Submit © 2025 McGraw Hill LLC. All Rights Reserved. TOMS OF US vacy Center | Accessibilityarrow_forwardWhat is the missing reactant in this organic reaction? CH3-C-CH2-NH2 + R - CH3 O: 0 CH3-N-CH2-C-NH-CH2-C-CH3 + H2O Specifically, in the drawing area below draw the condensed structure of R. If there is more than one reasonable answer, you can draw any one of them. If there is no reasonable answer, check the No answer box under the drawing area. Note for advanced students: you may assume no products other than those shown above are formed. Explanation Check Click anywhere to draw the first atom of your structure. C © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center Accesarrow_forward
- Done 18:17 • www-awu.aleks.com Chapter 12 HW Question 24 of 39 (4 points) | Question Attempt: 1 of Unlimited ▼ 20 ✓ 21 × 22 23 24 25 26 raw the structure corresponding to each IUPAC name. Part 1 of 2 .III LTE 22 27 28 סוי 29 29 3 A skeletal structure corresponding to the IUPAC name 3-ethyl-4-methylhexane. Part 2 of 2 Click and drag to start drawing a structure. A condensed structure corresponding to the IUPAC name 2,2,4- trimethylpentane. Click anywhere to draw the first atom of your structure. Check Save For Later Submit < Х ப: G © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility : Garrow_forwardDone 18:25 www-awu.aleks.com .III LTE Chapter 12 HW Question 29 of 39 (6 points) | Question Attempt: 1 of Unlimi... Oli 23 24 25 26 27 28 29 30 Consider this structure. CH2 CH2CH2 CH2CH2CH₂ C -C. -CH2CH3 H CH Part: 0 / 3 Part 1 of 3 Give the IUPAC name of this structure. Skip Part < Check ☑ Save For Later © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility ....................arrow_forwardCalculate Ecell at 25.0 oC using the following line notation. Zn(s)|Zn+2(aq, 0.900 M)||Cu+2(aq, 0.000200 M)|Cu(s)arrow_forward
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