The pressure at which 95 % of the Oxygen molecules dissociate is to be calculated. Concept introduction: The equilibrium constant K describes the ratio of the reactant to the product on the equilibrium conditions in terms of molar concentration. The equilibrium constant depends upon temperature. Law of mass action is applicable on the equilibrium reactions. The Le Chatelier’s principle states that the addition of the reactants shifts the equilibrium to the right while the addition of product shifts the equilibrium to the left at constant temperature. The dissociation of the species is denotes by the symbol α . To determine: The pressure at which 95 % of the Oxygen molecules dissociate at the constant temperature.
The pressure at which 95 % of the Oxygen molecules dissociate is to be calculated. Concept introduction: The equilibrium constant K describes the ratio of the reactant to the product on the equilibrium conditions in terms of molar concentration. The equilibrium constant depends upon temperature. Law of mass action is applicable on the equilibrium reactions. The Le Chatelier’s principle states that the addition of the reactants shifts the equilibrium to the right while the addition of product shifts the equilibrium to the left at constant temperature. The dissociation of the species is denotes by the symbol α . To determine: The pressure at which 95 % of the Oxygen molecules dissociate at the constant temperature.
Solution Summary: The author explains that the equilibrium constant K describes the ratio of the reactant to the product on equilibrium conditions in terms of molar concentration.
Interpretation: The pressure at which
95% of the Oxygen molecules dissociate is to be calculated.
Concept introduction: The equilibrium constant
K describes the ratio of the reactant to the product on the equilibrium conditions in terms of molar concentration.
The equilibrium constant depends upon temperature.
Law of mass action is applicable on the equilibrium reactions.
The Le Chatelier’s principle states that the addition of the reactants shifts the equilibrium to the right while the addition of product shifts the equilibrium to the left at constant temperature.
The dissociation of the species is denotes by the symbol
α.
To determine: The pressure at which
95% of the Oxygen molecules dissociate at the constant temperature.
Unshared, or lone, electron pairs play an important role in determining the chemical and physical properties of organic compounds.
Thus, it is important to know which atoms carry unshared pairs.
Use the structural formulas below to determine the number of unshared pairs at each designated atom.
Be sure your answers are consistent with the formal charges on the formulas.
CH.
H₂
fo
H2
H
The number of unshared pairs at atom a is
The number of unshared pairs at atom b is
The number of unshared pairs at atom c is
HC
HC
HC
CH
The number of unshared pairs at atom a is
The number of unshared pairs at atom b is
The number of unshared pairs at atom c is
Draw curved arrows for the following reaction step.
Arrow-pushing Instructions
CH3
CH3 H
H-O-H
+/
H3C-C+
H3C-C-0:
CH3
CH3 H
Chapter 13 Solutions
Bundle: Chemistry, 10th + Laboratory Handbook for General Chemistry, 3rd + Student Resource Center Printed Access Card + Student Solutions Manual for ... Access Card for Zumdahl/Zumdahl/DeCoste
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell