Consider a 100 mL of solution with 13.5% of NaCl by mass with a density of 1.12 g mL . What among solute and solvent and how much we need to add to given solution to make the boiling point of solution104.4°C (take i=1.8). Concept introduction: a) The percentage by mass means that that amount of solute is dissolved in 100 g of solution. b) The elevation in boiling point is a colligative property and is related to molality as ∆T b = i.K b .m where, ∆T b is change in boiling temperature i is Van’t Hoff factor K b is molal boiling-point elevation constant m is molality Given: The density of solution is 1.12 g mL Volume of solution is 100 mL Mass percentage of NaCl is 13.5 % Van’t Hoff factor = i = 1.8

Question

b) 8. Indicate whether the following carbocation rearrangements are likely to occur Please explain your rational using 10 words or less not likely to occur • The double bond is still in the Same position + Likely to oc occur WHY? -3 H3C Brave Chair Conformers. Draw the chair conformer of the following substituted cyclohexane. Peform a RING FLIP and indicate the most stable conformation and briefly explain why using 20 words or less. CI 2 -cobs ?? MUST INDICATE H -2 -2 Br EQ Cl OR AT Br H& most stable WHY? - 4

Answer 1

Question

Chapter 13, Problem 119E

Interpretation Introduction

Interpretation:

Consider a 100 mL of solution with 13.5% of NaCl by mass with a density of 1.12 $\frac{g}{mL}$ . What among solute and solvent and how much we need to add to given solution to make the boiling point of solution104.4°C (take i=1.8).

Concept introduction:

a) The percentage by mass means that that amount of solute is dissolved in 100 g of solution.

b) The elevation in boiling point is a colligative property and is related to molality as

∆T_b = i.K_b.m

where,

∆T_b is change in boiling temperature

i is Van’t Hoff factor

K_b is molal boiling-point elevation constant

m is molality

Given:

The density of solution is 1.12 $\frac{g}{mL}$

Volume of solution is 100 mL

Mass percentage of NaCl is 13.5 %

Van’t Hoff factor = i = 1.8

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