Chapter 13, Problem 111E

Interpretation Introduction

Interpretation:

The vapor pressure of water is to be calculated above given solution at 338K.

Concept introduction:

a) Lowering of vapor pressure and elevation in boiling point are colligative property and depends upon only number of molecules and not nature.

b) The boiling point increases on addition of a non volatile solute.

c) The ebullioscopic constant of water is $\text{0}\text{.512}\frac{{}^{\text{0}}\text{C}\text{.kg}}{\text{m}}$.

Given:

Boiling point of solution with non-volatile solute = 375.3 K

Vapor pressure of pure water = 0.2467 atm,at 338 K