The degree of freedom and outline the ANOVA table with the sources of variance.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

You have been hired as an intern to run analyses on the data and report the results back to Sarah; the five questions that Sarah needs you to address are given below. Does there appear to be a positive or negative relationship between price and screen size? Use a scatter plot to examine the relationship. Determine and interpret the correlation coefficient between the two variables. In your interpretation, discuss the direction of the relationship (positive, negative, or zero relationship). Also discuss the strength of the relationship. Estimate the relationship between screen size and price using a simple linear regression model and interpret the estimated coefficients. (In your interpretation, tell the dollar amount by which price will change for each unit of increase in screen size). Include the manufacturer dummy variable (Samsung=1, 0 otherwise) and estimate the relationship between screen size, price and manufacturer dummy as a multiple linear regression model. Interpret the…

Does there appear to be a positive or negative relationship between price and screen size? Use a scatter plot to examine the relationship. How to take snapshots: if you use a MacBook, press Command+ Shift+4 to take snapshots. If you are using Windows, use the Snipping Tool to take snapshots. Question 1: Determine and interpret the correlation coefficient between the two variables. In your interpretation, discuss the direction of the relationship (positive, negative, or zero relationship). Also discuss the strength of the relationship. Value of correlation coefficient: Direction of the relationship (positive, negative, or zero relationship): Strength of the relationship (strong/moderate/weak): Question 2: Estimate the relationship between screen size and price using a simple linear regression model and interpret the estimated coefficients. In your interpretation, tell the dollar amount by which price will change for each unit of increase in screen size. (The answer for the…

In this problem, we consider a Brownian motion (W+) t≥0. We consider a stock model (St)t>0 given (under the measure P) by d.St 0.03 St dt + 0.2 St dwt, with So 2. We assume that the interest rate is r = 0.06. The purpose of this problem is to price an option on this stock (which we name cubic put). This option is European-type, with maturity 3 months (i.e. T = 0.25 years), and payoff given by F = (8-5)+ (a) Write the Stochastic Differential Equation satisfied by (St) under the risk-neutral measure Q. (You don't need to prove it, simply give the answer.) (b) Give the price of a regular European put on (St) with maturity 3 months and strike K = 2. (c) Let X = S. Find the Stochastic Differential Equation satisfied by the process (Xt) under the measure Q. (d) Find an explicit expression for X₁ = S3 under measure Q. (e) Using the results above, find the price of the cubic put option mentioned above. (f) Is the price in (e) the same as in question (b)? (Explain why.)

Answer 2

Question

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

Answer 6

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

Answer 7

Chapter 13, Problem 10E

(a)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

Answer 8

(a)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor sex is 1 and for age, the degree of freedom is 2. The degree of freedom of interaction factor is 2.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=66−3×2=60

The degree of freedom for Sex can be calculated as:

d.f=I−1=2−1=1

The degree of freedom for Age can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=1×2=2

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Sex	1
Age	2
Interaction	2
Error	60
Total	65

Answer 13

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

Answer 14

(b)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

Answer 15

(b)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for week after harvest is 4 and for amount of water, the degree of freedom is 1. The degree of freedom of interaction factor is 4.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=30−10=20

The degree of freedom for Week after harvest can be calculated as:

d.f=I−1=5−1=4

The degree of freedom for Amount of water can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=4×1=4

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Week after harvest	4
Amount of water	1
Interaction	4
Error	20
Total	29

Answer 20

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

Answer 21

(c)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

Answer 22

(c)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor mixture is 5 and for freezing/thawing, the degree of freedom is 2. The degree of freedom of interaction factor is 10.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=54−6×3=36

The degree of freedom for Mixture can be calculated as:

d.f=I−1=6−1=5

The degree of freedom for freezing /thawing can be calculated as:

d.f=J−1=3−1=2

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=5×2=10

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Mixture	5
freezing/thawing	2
Interaction	10
Error	36
Total	53

Answer 27

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.

Explanation of Solution

Calculation: For the provided data, the error term can be calculated as:

Error term=N−IJ=138−4×2=130

The degree of freedom for different colored tags can be calculated as:

d.f=I−1=4−1=3

The degree of freedom for the type of buyers can be calculated as:

d.f=J−1=2−1=1

The degree of freedom for Interaction can be calculated as:

d.f=(I−1)(J−1)=3×1=3

The ANOVA table with different sources of variance and degree of freedom is as follows:

Sources	Degree of freedom
Different colored tags	3
Type of buyers	1
Interaction	3
Error	130
Total	137

Answer 28

(d)

To determine

To find: The degree of freedom and outline the ANOVA table with the sources of variance.

Answer 29

(d)

Expert Solution

Answer to Problem 10E

Solution: The degree of freedom for factor different colored tags is 3 and for the type of buyers, degree of freedom is 1. The degree of freedom of interaction factor is 3.