PEARSON ETEXT ENGINEERING MECH & STATS
15th Edition
ISBN: 9780137514724
Author: HIBBELER
Publisher: PEARSON
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The weight of the spring held follower AB is 0.375 kg and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0.2 ft and z =
(0.1sin20) ft. If the cam is rotating at a constant rate of 6 rad/s, determine the force, in Ib, at the end A of the follower where 0 = 45°. In this position, the spring is
compressed 0.4 ft. Neglect friction at the bearing C. Round your answer to 3 decimal places.
z = 0.1 sin 20
C
0.2 ft
B
6 = 6 rad/s
k = 12 lb/ft
The spring-held follower AB has a mass of 0.5 kg and moves back andforth as its end rolls on the contoured surface of the cam, where r = 0.15 m and z =(0.02 cos 2θ) m. If the cam is rotating at a constant rate of 30 rad/s, determine theforce component Fz at the end A of the follower when θ = 30°. The spring isuncompressed when θ = 90°. Neglect friction at the bearing C.
The homogeneous, solid cylinder with mass m = 4.8 kg and radius r = 0.24 m rolls along the
inclined surface without slipping. If the initial angular velocity is w, = 2 rad/s (counterclockwise),
and after a certain time lapse the angular velocity is w2 = 2.2 rad/s (clockwise), determine the
magnitude of the linear impulse due to the frictional force during this time period. Let 0 = 46°.
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- The spring-held follower AB has a weight of 0.75 lb and moves back and forth as its end rolls on the contoured surface of the cam, where r=0.2 ft and z = (0.1sine) ft. If the cam is rotating at a constant rate of 6 rad/s, determine the force at the end A of the follower when e=90°. In this position the spring is compressed 0.4 ft. Neglect friction at the bearing C. z = 0.1 sin 20 0.2 ft e = 6 rad/s k = 12 lb/ft Fs FA- Tarrow_forwardPlease asaparrow_forwardThe spring-held follower AB has a mass of 0.4 kg and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0.15 m and z=(0.02cos2θ)m. The cam is rotating at a constant rate of 30 rad/s. The spring is uncompressed when θ = 90. Determine the maximum force component FzFz the follower exerts on the cam. Determine the minimum force component FzFz the follower exerts on the cam.arrow_forward
- The weight of the spring held follower AB is 0.367 kg and moves back and forth as its end rolls on the contoured surface of the cam, where r = 0.2 ft and z = (0.1sin20) ft. If the cam is rotating at a constant rate of 6 rad/s, determine the force, in lb, at the end A of the follower where 0 = 45°. In this position, the spring is compressed 0.4 ft. Neglect friction at the bearing C. Round your answer to 3 decimal places. 6 = 6 rad/s 0.2 ftX z = 0.1 sin 20 Z A k = 12 lb/ft с Barrow_forwardThe smooth surface of the vertical cam is defined in part by the curve r = (0.2 cos 0+0.3) m. Plac41 Figure ▼ Part A If the forked rod is rotating with a constant angular velocity of A = 4 rad/s, determine the force the cam and the rod exert on the 1.8-kg roller when 0 = 30°. The attached spring has a stiffnesss k= 30 N/m and an unstretched length of 0.1 m. Express your answers in newtons using three significant figures separated by a comma. Neam, Frod = ΑΣΦ Submit Request Answer vec ? 1 of 1 Narrow_forwardPart A The smooth surface of the vertical cam is defined in part by the curve r = (0.2 cos 0+0.3) m. The forked rod is rotating with an angular acceleration of 0 = 2 rad/s as shown in (Figure 1), and when 0 = 45°, the angular velocity is 6 = 6 rad/s. Determine the force the cam and the rod exert on the 1.8-kg roller at this instant. The attached spring has a stiffnesss k = 100 N/m and an unstretched length of 0.1 m. Express your answers in newtons using three significant figures separated by a comma. ? Neam, Frud = N Submit Request Answer Figure 1 of 1 Provide Feedback Next >arrow_forward
- 2/135 As the hydraulic cylinder rotates around O, the ex- posed length 1 of the piston rod P is controlled by the action of oil pressure in the cylinder. If the cyl- inder rotates at the constant rate 0 = 60 deg/s and 1 is decreasing at the constant rate of 150 mm/s, calculate the magnitudes of the velocity v and ac- celeration a of end B when 1 = 125 mm. Ans. U = 545 mm/s, a = 632 mm/s² 375 mm 0 Problem 2/135 Barrow_forwardAssuming there is no slippage for the belt assembly below, Determine the following: What is the average angular velocity of each pulley if the rope accelerates from 5 m/s to 10 m/s in 10 s? How many revolutions does the pulley turn in that time? R1 = 0.3 m R2 = 0.2 m R3 = 0.1 marrow_forward*13=108. The collar, which has a weight of 3 lb, slides along the smooth rod lying in the horizontal plane and having the shape of a parabola r = 4/(1 – cos 0), where 0 is in radians and r is in feet. If the collar's angular rate is constant and equals ò = 4 rad/s, determine the tangential retarding force P needed to cause the motion and the normal force that the collar exerts on the rod at the instant 0 = 90°.arrow_forward
- The rate of the rotating arm is 4 rad/s when it is 3 rad/s² and 0 = 180°. Determine the force it must exert on the 0.45 kg smooth cylinder if it is confined to move along the slotted path. Motion occurs in the horizontal plane. Round your answer to 2 decimal places. 6 = 4 rad/s, 0 = 3 rad/s²/ r 0 = 180° r = (²7) marrow_forwardAs in the figure, in an amusement vehicle rotating in the amusement park, the center shaft rotates at a speed of n=9 rpm. Meanwhile, the child is moved with the position equations r = (2 sinθ + 5) m and z = (3 cosθ) m. Find the forces generated in the child in all three axes (r, θ, z). The weight of the child is m = 31 kg. θ=115 degrees at the time the photo was taken.arrow_forwardIn the figure, rod AB has a mass of 10 kg, and must slide within the slots as shown. If the spring is unstretched when θ = 0°, determine the angular velocity of the bar when it reaches that angle after being released from θ = 30°.arrow_forward
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