A 4.72-g sample of methanol (CH 3 OH) was placed in an otherwise empty 1.00-L flask and heated to 250.°C to vaporize the methanol. Over time, the methanol vapor decomposed by the following reaction : CH 3 OH ( g ) ⇌ CO ( g ) + 2 H 2 ( g ) After the system has reached equilibrium, a tiny hole is drilled in the side of the flask allowing gaseous compounds to effuse out of the flask. Measurements of the effusing gas show that it contains 33.0 times as much H 2 ( g ) as CH 3 OH( g ). Calculate K for this reaction at 250.°C.
A 4.72-g sample of methanol (CH 3 OH) was placed in an otherwise empty 1.00-L flask and heated to 250.°C to vaporize the methanol. Over time, the methanol vapor decomposed by the following reaction : CH 3 OH ( g ) ⇌ CO ( g ) + 2 H 2 ( g ) After the system has reached equilibrium, a tiny hole is drilled in the side of the flask allowing gaseous compounds to effuse out of the flask. Measurements of the effusing gas show that it contains 33.0 times as much H 2 ( g ) as CH 3 OH( g ). Calculate K for this reaction at 250.°C.
Solution Summary: The author explains the decomposition reaction of methanol to form carbon monoxide and hydrogen gas and the value of the equilibrium constant (K) for the reaction.
A 4.72-g sample of methanol (CH3OH) was placed in an otherwise empty 1.00-L flask and heated to 250.°C to vaporize the methanol. Over time, the methanol vapor decomposed by the following reaction:
CH
3
OH
(
g
)
⇌
CO
(
g
)
+
2
H
2
(
g
)
After the system has reached equilibrium, a tiny hole is drilled in the side of the flask allowing gaseous compounds to effuse out of the flask. Measurements of the effusing gas show that it contains 33.0 times as much H2(g) as CH3OH(g). Calculate K for this reaction at 250.°C.
Hi!!
Please provide a solution that is handwritten.
this is an inorganic chemistry question please answer accordindly!!
its just one question with parts JUST ONE QUESTION, please answer EACH part till the end and dont just provide wordy explanations wherever asked for structures, please DRAW DRAW them on a paper and post clearly!! answer the full question with all details EACH PART CLEARLY please thanks!!
im reposting this please solve all parts and drawit not just word explanations!!
8b. Explain, using key intermediates, why the above two products are formed instead of the 1,2-and 1,4- products
shown in the reaction below.
CI
(5pts) Provide the complete arrow pushing mechanism for the chemical transformation
depicted below
Use proper curved arrow notation that explicitly illustrates all bonds being broken, and
all bonds formed in the transformation.
Also, be sure to include all lone pairs and formal charges on all atoms involved in the
flow of electrons.
CH3O
H
I I
CH3O-H
H
I ①
H
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