1. Explanation Calculation: The given information suggests that the mean for group A is 4.00, the mean for group B is 6.63 and the mean for group C is 8.00. The ANOVA table suggests that the value of M S E is 8.66, the number of groups is 3 and the total number of observations is 24. That is, the 24 observations are distributed to three groups equally. Therefore, n 1 = 8 , n 2 = 8 , n 3 = 8 . Fisher’s LSD test: Step 1: Computing the test statistic by subtracting the two group means, respectively. Step 2: Computing the critical value for each pair by using Critical value = t α M S E ( 1 n 1 + 1 n 2 ) , where t α represents the t critical value, M S E represents the mean square error and n 1 , n 2 represents the sample sizes of the groups. Step 3: Making Decision by the rejection rule. Rejection Rule: If test statistic is greater than the critical value, then reject the null hypothesis. Critical value: The given significance level is α = 0.05 . The degrees of freedom are 21, and the alpha level is 0.05. From the Appendix C: Table C.2 the t Distribution: Locate the value 21 in the degrees of freedom ( df ) column. Locate the 0.05 in level of significance column. The intersecting value that corresponds to the 21 with level of significance 0.05 is 2.08. Thus, the value of t α is 2.08. Substitute 2.08 for t α , M S E = 8.66 and n 1 = 8 , n 2 = 8 in critical value formula. The critical value is, Critical value = t α M S E ( 1 n 1 + 1 n 2 ) = 2 2. To determine Identify the significant pairs of groups by using Tukey’s HSD test.

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Author: Gregory J. Privitera

Publisher: SAGE Publications, Inc

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Chapter 12.7, Problem 4.3LC

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Identify the significant pairs of groups by using Fisher’s LSD test.

To determine

Identify the significant pairs of groups by using Tukey’s HSD test.

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Chapter 12 Solutions

Statistics for the Behavioral Sciences

Ch. 12.2 - Prob. 1.1LC Ch. 12.2 - Prob. 1.2LC Ch. 12.2 - Prob. 1.3LC Ch. 12.2 - Prob. 1.4LC Ch. 12.4 - Prob. 2.1LC Ch. 12.4 - Prob. 2.2LC Ch. 12.4 - Prob. 2.3LC Ch. 12.4 - Prob. 2.4LC Ch. 12.6 - Prob. 3.1LC Ch. 12.6 - Prob. 3.2LC

Ch. 12.6 - Prob. 3.3LC Ch. 12.6 - Prob. 3.4LC Ch. 12.6 - Prob. 3.5LC Ch. 12.6 - Prob. 3.6LC Ch. 12.7 - Prob. 4.1LC Ch. 12.7 - Prob. 4.2LC Ch. 12.7 - Prob. 4.3LC Ch. 12.9 - Prob. 5.1LC Ch. 12.9 - Prob. 5.2LC Ch. 12 - Prob. 1FP Ch. 12 - Prob. 2FP Ch. 12 - Prob. 3FP Ch. 12 - Prob. 4FP Ch. 12 - Prob. 5FP Ch. 12 - Prob. 6FP Ch. 12 - Prob. 7FP Ch. 12 - Prob. 8FP Ch. 12 - Prob. 9FP Ch. 12 - Prob. 10FP Ch. 12 - Prob. 11FP Ch. 12 - Prob. 12FP Ch. 12 - Prob. 13CAP Ch. 12 - Prob. 14CAP Ch. 12 - Prob. 15CAP Ch. 12 - Prob. 16CAP Ch. 12 - Prob. 17CAP Ch. 12 - Prob. 18CAP Ch. 12 - Prob. 19CAP Ch. 12 - Prob. 20CAP Ch. 12 - Prob. 21CAP Ch. 12 - Prob. 22CAP Ch. 12 - Prob. 23CAP Ch. 12 - Prob. 24CAP Ch. 12 - Prob. 25CAP Ch. 12 - Prob. 26CAP Ch. 12 - Prob. 27CAP Ch. 12 - Prob. 28CAP Ch. 12 - Prob. 29PR Ch. 12 - Prob. 30PR Ch. 12 - Prob. 31PR Ch. 12 - Prob. 32PR Ch. 12 - Prob. 33PR Ch. 12 - Prob. 34PR

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Introduction to experimental design and analysis of variance (ANOVA); Author: Dr. Bharatendra Rai;https://www.youtube.com/watch?v=vSFo1MwLoxU;License: Standard YouTube License, CC-BY

Identify the significant pairs of groups by using Fisher’s LSD test.

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Identify the significant pairs of groups by using Fisher’s LSD test.

Identify the significant pairs of groups by using Tukey’s HSD test.

Chapter 12 Solutions