
Concept explainers
Show that if the point (a, b, c) lies on the hyperbolic paraboloid z = y2 − x2, then the lines with parametric equations x = a + t, y = b + t, z = c + 2(b − a)t and x = a + t, y = b − t, z = c − 2(b + a)t both lie entirely on this paraboloid. (This shows that the hyperbolic paraboloid is what is called a ruled surface; that is, it can be generated by the motion of a straight line. In fact, this exercise shows that through each point on the hyperbolic paraboloid there are two generating lines. The only other quadric surfaces that are ruled surfaces are cylinders, cones, and hyperboloids of one sheet.)

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Chapter 12 Solutions
Bundle: Multivariable Calculus, 8th + WebAssign Printed Access Card for Stewart's Calculus, 8th Edition, Single-Term
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- Matrix A is factored in the form PDP 1. Use the Diagonalization Theorem to find the eigenvalues of A and a basis for each eigenspace. 30 -1 - 1 0 -1 400 0 0 1 A= 3 4 3 0 1 3 040 3 1 3 0 0 4 1 0 0 003 -1 0 -1 Select the correct choice below and fill in the answer boxes to complete your choice. (Use a comma to separate vectors as needed.) A basis for the corresponding eigenspace is { A. There is one distinct eigenvalue, λ = B. In ascending order, the two distinct eigenvalues are λ₁ ... = and 2 = Bases for the corresponding eigenspaces are { and ( ), respectively. C. In ascending order, the three distinct eigenvalues are λ₁ = = 12/2 = and 3 = Bases for the corresponding eigenspaces are {}, }, and { respectively.arrow_forwardN Page 0.6. 0.4. 0.2- -0.2- -0.4- -6.6 -5 W 10arrow_forwardDiagonalize the following matrix, if possible. 8 0 6 - 8 Select the correct choice below and, if necessary, fill in the answer box to complete your choice. 8 0 OA. For P= D= 0 3 6 0 B. For P = D= 0 -6 8 0 C. For P = D= 0 - 8 D. The matrix cannot be diagonalized.arrow_forward
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