To construct a scatter plot .

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 12.5, Problem 12.28E

a)

To determine

To construct a scatter plot.

a)

Expert Solution

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Following is the scatter plot:

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 1

The assumption of linearity holds in the scatter plot.

b)

To determine

To find regression equation.

b)

Expert Solution

Answer to Problem 12.28E

Final exam= −26.8215+1.2617×Posttest

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 2

The regression equation is,

Final exam= −26.8215+1.2617×Posttest

c)

To determine

To explain if data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

c)

Expert Solution

Answer to Problem 12.28E

Data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 3

The p-value = 6.22E-07 < 0.05 hence rejecting null hypothesis. Hence, data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

d)

To determine

To find the 99% confidence interval for slope of the regression equation.

d)

Expert Solution

Answer to Problem 12.28E

the 99% confidence interval for slope of the regression equation= (0.7767,1.7468)

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Regression output	confidence interval
variables	coefficients	std. error	t (df=18)	p-value	99% lower	99% upper
Intercept	-26.8215	14.7603	-1.817	.0859	-69.3083	15.6652
Posttest	1.2617	0.1685	7.487	6.22E-07	0.7767	1.7468

Confidence interval = (0.7767,1.7468)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

Twenty-eight applicants interested in working for the Food Stamp program took an examination designed to measure their aptitude for social work. A stem-and-leaf plot of the 28 scores appears below, where the first column is the count per branch, the second column is the stem value, and the remaining digits are the leaves. a) List all the values. Count 1 Stems Leaves 4 6 1 4 6 567 9 3688 026799 9 8 145667788 7 9 1234788 b) Calculate the first quartile (Q1) and the third Quartile (Q3). c) Calculate the interquartile range. d) Construct a boxplot for this data.

Pam, Rob and Sam get a cake that is one-third chocolate, one-third vanilla, and one-third strawberry as shown below. They wish to fairly divide the cake using the lone chooser method. Pam likes strawberry twice as much as chocolate or vanilla. Rob only likes chocolate. Sam, the chooser, likes vanilla and strawberry twice as much as chocolate. In the first division, Pam cuts the strawberry piece off and lets Rob choose his favorite piece. Based on that, Rob chooses the chocolate and vanilla parts. Note: All cuts made to the cake shown below are vertical.Which is a second division that Rob would make of his share of the cake?

Three players (one divider and two choosers) are going to divide a cake fairly using the lone divider method. The divider cuts the cake into three slices (s1, s2, and s3). If the choosers' declarations are Chooser 1: {s1 , s2} and Chooser 2: {s2 , s3}. Using the lone-divider method, how many different fair divisions of this cake are possible?

Answer 2

Question

Chapter 12.5, Problem 12.28E

a)

To determine

To construct a scatter plot.

a)

Expert Solution

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Following is the scatter plot:

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 1

The assumption of linearity holds in the scatter plot.

b)

To determine

To find regression equation.

b)

Expert Solution

Answer to Problem 12.28E

Final exam= −26.8215+1.2617×Posttest

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 2

The regression equation is,

Final exam= −26.8215+1.2617×Posttest

c)

To determine

To explain if data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

c)

Expert Solution

Answer to Problem 12.28E

Data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 3

The p-value = 6.22E-07 < 0.05 hence rejecting null hypothesis. Hence, data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

d)

To determine

To find the 99% confidence interval for slope of the regression equation.

d)

Expert Solution

Answer to Problem 12.28E

the 99% confidence interval for slope of the regression equation= (0.7767,1.7468)

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Regression output	confidence interval
variables	coefficients	std. error	t (df=18)	p-value	99% lower	99% upper
Intercept	-26.8215	14.7603	-1.817	.0859	-69.3083	15.6652
Posttest	1.2617	0.1685	7.487	6.22E-07	0.7767	1.7468

Confidence interval = (0.7767,1.7468)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 12.5, Problem 12.28E

a)

To determine

To construct a scatter plot.

a)

Expert Solution

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Following is the scatter plot:

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 1

The assumption of linearity holds in the scatter plot.

b)

To determine

To find regression equation.

b)

Expert Solution

Answer to Problem 12.28E

Final exam= −26.8215+1.2617×Posttest

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 2

The regression equation is,

Final exam= −26.8215+1.2617×Posttest

c)

To determine

To explain if data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

c)

Expert Solution

Answer to Problem 12.28E

Data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 3

The p-value = 6.22E-07 < 0.05 hence rejecting null hypothesis. Hence, data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

d)

To determine

To find the 99% confidence interval for slope of the regression equation.

d)

Expert Solution

Answer to Problem 12.28E

the 99% confidence interval for slope of the regression equation= (0.7767,1.7468)

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Regression output	confidence interval
variables	coefficients	std. error	t (df=18)	p-value	99% lower	99% upper
Intercept	-26.8215	14.7603	-1.817	.0859	-69.3083	15.6652
Posttest	1.2617	0.1685	7.487	6.22E-07	0.7767	1.7468

Confidence interval = (0.7767,1.7468)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 12.5, Problem 12.28E

a)

To determine

To construct a scatter plot.

a)

Expert Solution

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Following is the scatter plot:

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 1

The assumption of linearity holds in the scatter plot.

b)

To determine

To find regression equation.

b)

Expert Solution

Answer to Problem 12.28E

Final exam= −26.8215+1.2617×Posttest

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 2

The regression equation is,

Final exam= −26.8215+1.2617×Posttest

c)

To determine

To explain if data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

c)

Expert Solution

Answer to Problem 12.28E

Data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 3

The p-value = 6.22E-07 < 0.05 hence rejecting null hypothesis. Hence, data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

d)

To determine

To find the 99% confidence interval for slope of the regression equation.

d)

Expert Solution

Answer to Problem 12.28E

the 99% confidence interval for slope of the regression equation= (0.7767,1.7468)

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Regression output	confidence interval
variables	coefficients	std. error	t (df=18)	p-value	99% lower	99% upper
Intercept	-26.8215	14.7603	-1.817	.0859	-69.3083	15.6652
Posttest	1.2617	0.1685	7.487	6.22E-07	0.7767	1.7468

Confidence interval = (0.7767,1.7468)

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 12.5, Problem 12.28E

a)

To determine

To construct a scatter plot.

a)

Expert Solution

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Following is the scatter plot:

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 1

The assumption of linearity holds in the scatter plot.

b)

To determine

To find regression equation.

b)

Expert Solution

Answer to Problem 12.28E

Final exam= −26.8215+1.2617×Posttest

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 2

The regression equation is,

Final exam= −26.8215+1.2617×Posttest

c)

To determine

To explain if data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

c)

Expert Solution

Answer to Problem 12.28E

Data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 3

The p-value = 6.22E-07 < 0.05 hence rejecting null hypothesis. Hence, data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

d)

To determine

To find the 99% confidence interval for slope of the regression equation.

d)

Expert Solution

Answer to Problem 12.28E

the 99% confidence interval for slope of the regression equation= (0.7767,1.7468)

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Regression output	confidence interval
variables	coefficients	std. error	t (df=18)	p-value	99% lower	99% upper
Intercept	-26.8215	14.7603	-1.817	.0859	-69.3083	15.6652
Posttest	1.2617	0.1685	7.487	6.22E-07	0.7767	1.7468

Confidence interval = (0.7767,1.7468)

Answer 6

Chapter 12.5, Problem 12.28E

a)

To determine

To construct a scatter plot.

a)

Expert Solution

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Following is the scatter plot:

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 1

The assumption of linearity holds in the scatter plot.

Answer 7

Chapter 12.5, Problem 12.28E

a)

To determine

To construct a scatter plot.

Answer 8

a)

Expert Solution

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Following is the scatter plot:

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 1

The assumption of linearity holds in the scatter plot.

Answer 9

a)

Expert Solution

Answer 10

a)

Expert Solution

Answer 11

Expert Solution

Answer 12

b)

To determine

To find regression equation.

b)

Expert Solution

Answer to Problem 12.28E

Final exam= −26.8215+1.2617×Posttest

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 2

The regression equation is,

Final exam= −26.8215+1.2617×Posttest

Answer 13

b)

To determine

To find regression equation.

Answer 14

b)

Expert Solution

Answer to Problem 12.28E

Final exam= −26.8215+1.2617×Posttest

Answer 15

b)

Expert Solution

Answer 16

b)

Expert Solution

Answer 17

Expert Solution

Answer 18

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 2

The regression equation is,

Final exam= −26.8215+1.2617×Posttest

Answer 19

c)

To determine

To explain if data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

c)

Expert Solution

Answer to Problem 12.28E

Data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 3

The p-value = 6.22E-07 < 0.05 hence rejecting null hypothesis. Hence, data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Answer 20

c)

To determine

To explain if data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Answer 21

c)

Expert Solution

Answer to Problem 12.28E

Data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Answer 22

c)

Expert Solution

Answer 23

c)

Expert Solution

Answer 24

Expert Solution

Answer 25

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Introduction to Probability and Statistics, Chapter 12.5, Problem 12.28E , additional homework tip 3

The p-value = 6.22E-07 < 0.05 hence rejecting null hypothesis. Hence, data present sufficient evidence to indicate that final exam score is linearly related to the posttest score.

Answer 26

d)

To determine

To find the 99% confidence interval for slope of the regression equation.

d)

Expert Solution

Answer to Problem 12.28E

the 99% confidence interval for slope of the regression equation= (0.7767,1.7468)

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Regression output	confidence interval
variables	coefficients	std. error	t (df=18)	p-value	99% lower	99% upper
Intercept	-26.8215	14.7603	-1.817	.0859	-69.3083	15.6652
Posttest	1.2617	0.1685	7.487	6.22E-07	0.7767	1.7468

Confidence interval = (0.7767,1.7468)

Answer 27

d)

To determine

To find the 99% confidence interval for slope of the regression equation.

Answer 28

d)

Expert Solution

Answer to Problem 12.28E

the 99% confidence interval for slope of the regression equation= (0.7767,1.7468)

Answer 29

d)

Expert Solution

Answer 30

d)

Expert Solution

Answer 31

Expert Solution

Answer 32

Explanation of Solution

Given:

The data is,

Student	Posttest	Final Exam
1	100	98
2	96	97
3	88	88
4	100	100
5	100	100
6	96	78
7	80	68
8	68	47
9	92	90
10	96	94
11	88	84
12	92	93
13	68	57
14	84	84
15	84	81
16	88	83
17	72	84
18	88	93
19	72	57
20	88	83

Calculation:

Using excel,

Regression output	confidence interval
variables	coefficients	std. error	t (df=18)	p-value	99% lower	99% upper
Intercept	-26.8215	14.7603	-1.817	.0859	-69.3083	15.6652
Posttest	1.2617	0.1685	7.487	6.22E-07	0.7767	1.7468