Explanation By constructing the normal distribution curve considering many random samples for the percentage of people liking different sports, suppose the mean is r % of people like one particular sport, some samples will show that the percentage of people liking that particular sport is more than r % and some samples will show it is less than r %. The calculated standard deviation for the normal distribution for these samples is 1 2 n × 100 % , where n is the total number. Almost 95% of the total numbers of samples have the percentage in the range of 2 deviations of the true mean percentage, r %. So, 2 times of standard deviations will be as follows: 2 Standard Devitaion = 2 × 1 2 n

Thinking Mathematically, Books a la carte Edition plus MyLab Math with Pearson eText -- Access Card Package (6th Edition)

6th Edition

ISBN: 9780321999061

Author: Robert F. Blitzer

Publisher: PEARSON

See similar textbooks

Concept explainers

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Videos

Question

Features Features Normal distribution is characterized by two parameters, mean (µ) and standard deviation (σ). When graphed, the mean represents the center of the bell curve and the graph is perfectly symmetric about the center. The mean, median, and mode are all equal for a normal distribution. The standard deviation measures the data's spread from the center. The higher the standard deviation, the more the data is spread out and the flatter the bell curve looks. Variance is another commonly used measure of the spread of the distribution and is equal to the square of the standard deviation.

Chapter 12.4, Problem 4CVC

To determine

To fill: The given statement, “If a statistic is obtained from a random sample of size n, there is a 95% probability that it lies within 1n×100%, of the true population percent, where ±1n×100%, is called the ________.”

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 12.4, Problem 3CVC

Chapter 12.4, Problem 5CVC

Students have asked these similar questions

The manager of a fleet of automobiles is testing two brands of radial tires and assigns one tire of each brand at random to the two rear wheels of eight cars and runs the cars until the tires wear out. The data (in kilometers) follow. CAR BRAND1 BRAND2 DIFFERENCE = (BRAND1 - BF 1 36,925 33,018 3,907 2 45,300 43,280 2,020 3 36,240 35,500 740 4 32,100 31,200 900 5 37,210 37,015 195 6 48,360 46,800 1,560 7 38,200 37,810 390 8 33,500 33,215 285

Diabetes and obesity are serious health concerns in the United States and much of the developed world. Measuring the amount of body fat a person carries is one way to monitor weight control progress, but measuring it accurately involves either expensive X-ray equipment or a pool in which to dunk the subject. Instead body mass index (BMI) is often used as a proxy for body fat because it is easy to measure: BMI = mass(kg)/(height(m))² = 703 mass(lb)/(height(in))². In a study of 15 men at TXST, both BMI and body fat were measured. Researchers imported the data into statistical software for analysis. A few values are missing from the output. Complete the table by filling in the missing values. Model Summary S R-sq % (three decimal places) (two decimal places. e.g. 12.3456%, enter 12.35) Analysis of Variance Source Model Error Total DF SS MS F P 17.600 0.001 DF: whole numbers SS or MS; three decimal places 34.810 Does a simple linear regression model seem reasonable in this situation?…

The use of electromyostimulation (EMS) as a method to train healthy skeletal muscle is studied. EMS sessions consisted of 30 contractions (4-second duration, 85 Hz) and were carried out three times per week for three weeks on 17 ice hockey players. The 10-meter skating performance test showed a standard deviation of 0.90 seconds. Is there strong evidence to conclude that the standard deviation of performance time exceeds the historical value of 0.75 seconds? Use a = 0.05.

Chapter 12 Solutions

Thinking Mathematically, Books a la carte Edition plus MyLab Math with Pearson eText -- Access Card Package (6th Edition)

Ch. 12.1 - CHECK POINT 1 A city government wants to conduct a...Ch. 12.1 - CHECK POINT 2 Explain why the sampling technique...Ch. 12.1 - CHECK POINT 3 Construct a frequency distribution...Ch. 12.1 - CHECK POINT 4 Use the classes in Table 12.3 to...Ch. 12.1 - CHECKPOINTS 5 Construct a stem-and-leaf plot for...Ch. 12.1 - A sample obtained in such a way that every member...Ch. 12.1 - Prob. 2CVC Ch. 12.1 - Fill in each blank so that the resulting statement...Ch. 12.1 - 4. Data can be displayed using a bar graph with...Ch. 12.1 - Prob. 5CVC

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, subject and related others by exploring similar questions and additional content below.

The given statement, “If a statistic is obtained from a random sample of size n , there is a 95% probability that it lies within 1 n × 100 % , of the true population percent, where ± 1 n × 100 % , is called the ________ .”

Solution Summary: The author explains that if a statistic is obtained from random samples of size n, it lies within 1sqrtntimes 100%.

Concept explainers

Videos

To fill: The given statement, “If a statistic is obtained from a random sample of size n, there is a 95% probability that it lies within 1n×100%, of the true population percent, where ±1n×100%, is called the ________.”

Want to see the full answer?

Chapter 12 Solutions