Computer Systems: A Programmer's Perspective Plus Mastering Engineering With Pearson Etext -- Access Card Package (3rd Edition)
Computer Systems: A Programmer's Perspective Plus Mastering Engineering With Pearson Etext -- Access Card Package (3rd Edition)
3rd Edition
ISBN: 9780134123837
Author: Randal E. Bryant, David R. O'Hallaron
Publisher: PEARSON
Expert Solution & Answer
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Chapter 12.4, Problem 12.6PP

A.

Explanation of Solution

Analysis from given section:

For variable instance “ptr”:

  • For main thread:
    • From the given code, the variable “ptr” is a global variable.
    • It is written by the main thread.
  • For peer thread 0 and thread 1:
    • The variable “ptr” is read by the peer threads.

For variable instance “cnt”:

  • For main thread:
    • From the given code, the variable “cnt” is a static variable and it is contains with only one instance in memory. Hence, it is not exist in the main thread.
  • For peer thread 0 and thread 1:
    • The variable “cnt” is read and written by the peer threads.

For variable instance “i.m”:

  • For main thread:
    • From the given code, the variable “i.m” is a local automatic variable.
    • It is stored on the stack of the main thread. Hence, this variable is exist in the main thread.
  • For peer thread 0 and thread 1:
    • The given variable is stored on the main thread, while its corresponding value is passed to the peer threads, the peer threads never place it on the stack. So, it is not shared.

For variable instance “msgs.m”:

  • For main thread:
    • From the given code, the variable “msgs.m” is a local automatic variable.
    • It is stored on the stack of the main thread. Hence, it is exist in the main thread.
  • For peer thread 0 and thread 1:
    • The given variable is stored on the main thread...

B.

Explanation of Solution

Analysis of shared variable from part A:

From the part A, the variables “ptr”,...

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