IA MODIFIED MASTERING BIOLOGY WITH E TEX
12th Edition
ISBN: 9780136781752
Author: Urry
Publisher: PEARSON
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Textbook Question
Chapter 12.3, Problem 1CC
In Figure 12.14, why do the nuclei resulting from experiment 2 contain different amounts of DNA?
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Please answer all the parts of the question a, b and c
In the Hershey–Chase experiment, the radioactive label 32P was present inside bacterial cells (i.e., in the pellet), whereas the radioactive label 35S waspresent outside bacterial cells (in the supernatant). What would the researchers have concluded had the reverse been true, that is, if the radioactive label 35S were inside the cells and the radioactive label 32P were outside the cells?
Question 2
The discovery of the DNA structure started the modern era of biotechnology.
A) True
B False
Chapter 12 Solutions
IA MODIFIED MASTERING BIOLOGY WITH E TEX
Ch. 12.1 - How many chromosomes are drawn in each part of...Ch. 12.1 - WHAT IF? A chicken has 78 chromosomes in its...Ch. 12.2 - How many chromosomes are shown in the illustration...Ch. 12.2 - Compare cytokinesis in animal cells and plant...Ch. 12.2 - During which stages of the cell cycle does a...Ch. 12.2 - Compare the roles of tubulin and actin during...Ch. 12.2 - A kinetochore has been compared to a coupling...Ch. 12.2 - MAKE CONNECTIONS What other functions do actin...Ch. 12.3 - In Figure 12.14, why do the nuclei resulting from...Ch. 12.3 - How does MPF allow a cell to pass the G2 phase...
Ch. 12.3 - MAKE CONNECTIONS Explain how receptor tyrosine...Ch. 12 - Differentiate between these terms: chromosome,...Ch. 12 - In which of the three phases of interphase and the...Ch. 12 - Explain the significance of the G1, G2, and M...Ch. 12 - Through a microscope, you can see a cell plate...Ch. 12 - Vinblastine is a standard chemotherapeutic drug...Ch. 12 - One difference between cancer cells and normal...Ch. 12 - The decline of MPF activity at the end of mitosis...Ch. 12 - In the cells of some organisms, mitosis occurs...Ch. 12 - Which of the following does not occur during...Ch. 12 - Cell A has half as much DNA as cells B, C, and D...Ch. 12 - The drug cytochalasin B blocks the function of...Ch. 12 - VISUAL SKILLS The light micrograph shows dividing...Ch. 12 - DRAW IT Draw one eukaryotic chromosome as it would...Ch. 12 - EVOLUTION CONNECTION The result of mitosis is that...Ch. 12 - SCIENTIFIC INQUIRY Although both ends of a...Ch. 12 - WRITE ABOUT A THEME: INFORMATION The continuity of...Ch. 12 - SYNTHESIZE YOUR KNOWLEDGE For selected answers,...
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- At the end of an experiment, you extract DNA from ten yeast colonies. You divide the DNA from each colony into two tubes, and send all twenty samples for sequencing. How many experimental replicates do you have?arrow_forwardYou mutagenized bacteria and isolated two mutants that you suspected to be defective in DNA synthesis. You measured incorporation of radioactivity (Y- axis) for various times (X-axis) at two temperatures (30 deg C shown as open circles and 40 deg C shown a filled circles in both figures) for the two mutants of bacteria (left and right figures). For this experiment, you can conclude that 20,000 1,000 30° 0- 40° 15,000- 10,000- 500 5,000- 0 40 40 80 120 120 0 Time (min) None of these conclusions O You have isolated a component of RNA synthesis that is temperature insensitive You have isolated mutants that are temperature insensitive You have isolated temperature-sensitive mutants that are defective in DNA synthesis O You have isolated a component of protein synthesis ³H-thymidine incorporated (cpm) O 80arrow_forwardThe Bacteria Escherichia coli DNA genome has a molecular mass of about 3.1 X 10° D. In your answers, show how you came up to each result? (a) How many base pairs does this bacterium contain? (b) How many full double-helical turns does this DNA contain? (c) How long is this DNA in µm?arrow_forward
- You have 2 solutions of DNA. Solution 1 contains single stranded viral DNA while Solution 2 has double stranded form of the same viral DNA. Both solutions contain 1 mg/ml of DNA. You then expose each of these solutions to UV light at 260 nm. Which of the following results would you expect to see after UV light exposure? a.Neither solution will absorb any UV light but the DNA in both solutions will be broken by the action of the UV light. b.Solution 1 will absorb less light than Solution 2 c.Solution 1 will absorb more light than solution 2. d.Nothing will occur. DNA can only absorb UV light if it is interchelated with ethidium bromide. e.Both solutions will absorb the same amount of light since their concentrations are the same.arrow_forwardQUESTION 4: Why does a PCR reaction require a primer? Would you expect this primer to be composed of DNA or RNA? Explain your reasoning.arrow_forwardThe table below summarises the three stages of Meselson and Stahl's experiment and their results. (a) Complete the table by drawing, in the appropriate boxes, diagrams of the DNA molecules and mark the position and size of the DNA bands in the tubes. Experimental stage Diagram to show the strands in the DNA Position and size of DNA bands in the tube of molecules of the bacteria separating solution Stage 1 Bacteria grown for several generations in culture medium containing heavy nitrogen Stage 2 The bacteria from the end of stage 1 were grown for another generation in culture medium containing light nitrogen TA2G - Completed forms must be available for Open Awards extermal moderation purposes. Page 7 of 13 Stage 3 The bacteria from the end of stage 2 were grown for one more generation in culture medium containing light nitrogen (b) The bacteria at the end of stage two were grown for five more generations. After each generation, what would you expect to see in the test tube? Draw these…arrow_forward
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- If you tiled a floor with the planar rings from the bases of all the DNA molecules of living creatures on Earth, approximately how many times could you cover the Earth’s surface? This is meant to be an estimation/Fermi problem so it does not have to be exact.arrow_forwardIf the DNA of one human cell is stretched out, it would be almost 6 feet long and contain over three billion base pairs. How does all this fit into the nucleus of one cell?arrow_forwardYou are trying to determine the base content for a number of samples in the lab (mouse DNA, bacterial DNA, single-stranded DNA virus and double-stranded RNA virus). Unfortunately, you failed to use an alcohol-proof marker and during the ethanol precipitation of your samples the labels came off the tubes. You finish the experiment anyway and try to use the data to determine the samples. Can you determine the source of each sample based on your results? Briefly explain how you come to your designations. Sample % adenine % cytosine % guanine % thymine % uracil A 18 32 32 18 0 B 26 18 32 24 0 C 31 19 19 0 31 D 10 40 40 10 0arrow_forward
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