Explanation Given information: The function s ( t ) = − 16 t 2 + 3 t Explanation: To find s ( 1 ) replace t by 1 in s ( t ) = − 16 t 2 + 3 t ⇒ s ( 1 ) = − 16 ( 1 2 ) + 3 ( 1 ) = − 13 Substitute the value of s ( 1 ) and s ( t ) in s ( t ) − s ( 1 ) t − 1 , ⇒ s ( t ) − s ( 1 ) t − 1 = ( − 16 t 2 + 3 t ) − ( − 13 ) t − 1 By simplifying, ⇒ s ( t ) − s ( 1 ) t − 1 =

Mylab Math With Pearson Etext -- Standalone Access Card -- For Precalculus (11th Edition)

11th Edition

ISBN: 9780135189795

Author: Michael Sullivan

Publisher: PEARSON

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differentia…

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Chapter 12.3, Problem 119AYU

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The difference quotient s(t)−s(1)t−1 for s(t)=−16t2+3t

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Chapter 12.3, Problem 118AYU

Chapter 12.3, Problem 120AYU

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Chapter 12 Solutions

Mylab Math With Pearson Etext -- Standalone Access Card -- For Precalculus (11th Edition)

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The difference quotient s ( t ) − s ( 1 ) t − 1 for s ( t ) = − 16 t 2 + 3 t

Solution Summary: The author explains how to determine the difference quotient s(t)-s

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The difference quotient s(t)−s(1)t−1 for s(t)=−16t2+3t

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Chapter 12 Solutions