Introduction to Algorithms
3rd Edition
ISBN: 9780262033848
Author: Thomas H. Cormen, Ronald L. Rivest, Charles E. Leiserson, Clifford Stein
Publisher: MIT Press
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Chapter 12.2, Problem 6E
Program Plan Intro
To show that if right sub-tree of a node x in T is empty and x has a successor y then y is the lowest ancestor of x whose left child is also an ancestor of x.
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Q4: Consider the following MAILORDER relational schema describing the data for a mail order
company. (Choose five only).
PARTS(Pno, Pname, Qoh, Price, Olevel)
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Qoh stands for quantity on hand: the other attribute names are self-explanatory. Specify and
execute the following queries using the RA interpreter on the MAILORDER database schema.
a. Retrieve the names of parts that cost less than $20.00.
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$50.00.
c. Retrieve the pairs of customer number values of customers who live in the same ZIP Code.
d. Retrieve the names of customers who have ordered parts from employees living in Wichita.
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Q4: Consider the following MAILORDER relational schema describing the data for a mail order
company. (Choose five only).
(10 Marks)
PARTS(Pno, Pname, Qoh, Price, Olevel)
CUSTOMERS(Cno, Cname, Street, Zip, Phone)
EMPLOYEES(Eno, Ename, Zip, Hdate)
ZIP CODES(Zip, City)
ORDERS(Ono, Cno, Eno, Received, Shipped)
ODETAILS(Ono, Pno, Qty)
Qoh stands for quantity on hand: the other attribute names are self-explanatory. Specify and
execute the following queries using the RA interpreter on the MAILORDER database schema.
a. Retrieve the names of parts that cost less than $20.00.
b. Retrieve the names and cities of employees who have taken orders for parts costing more than
$50.00.
c. Retrieve the pairs of customer number values of customers who live in the same ZIP Code.
d. Retrieve the names of customers who have ordered parts from employees living in Wichita.
e. Retrieve the names of customers who have ordered parts costing less than$20.00.
f. Retrieve the names of customers who have not placed…
Chapter 12 Solutions
Introduction to Algorithms
Ch. 12.1 - Prob. 1ECh. 12.1 - Prob. 2ECh. 12.1 - Prob. 3ECh. 12.1 - Prob. 4ECh. 12.1 - Prob. 5ECh. 12.2 - Prob. 1ECh. 12.2 - Prob. 2ECh. 12.2 - Prob. 3ECh. 12.2 - Prob. 4ECh. 12.2 - Prob. 5E
Ch. 12.2 - Prob. 6ECh. 12.2 - Prob. 7ECh. 12.2 - Prob. 8ECh. 12.2 - Prob. 9ECh. 12.3 - Prob. 1ECh. 12.3 - Prob. 2ECh. 12.3 - Prob. 3ECh. 12.3 - Prob. 4ECh. 12.3 - Prob. 5ECh. 12.3 - Prob. 6ECh. 12.4 - Prob. 1ECh. 12.4 - Prob. 2ECh. 12.4 - Prob. 3ECh. 12.4 - Prob. 4ECh. 12.4 - Prob. 5ECh. 12 - Prob. 1PCh. 12 - Prob. 2PCh. 12 - Prob. 3PCh. 12 - Prob. 4P
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