Explanation It is given that there are three boys and three girls at a party. The number of ways 3 boys can sit in three seats alternatively such as first, third and fifth seats is 3 ⋅ 2 ⋅ 1 = 6 . Similarly, the number of ways 3 girls can sit in three seats alternatively such as second, fourth and sixth seats is 3 ⋅ 2 ⋅ 1 = 6 . Thus, the total number of ways 3 boys and 3 girls can sit in a row is 6 ⋅ 6 = 36 . The number of ways 3 boys can sit in three seats alternatively such assecond, fourth and sixth is 3 ⋅ 2 ⋅ 1 = 6

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ISBN: 9780357325865

Author: SMITH

Publisher: CENGAGE L

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Chapter 12.2, Problem 52PS

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Whether use a permutation, a combination or neither to find the possible number of ways that they can be seated in a row if they must sit alternating boys and girls.

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Chapter 12.2, Problem 51PS

Chapter 12.2, Problem 53PS

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4. Negate the following sentences. Then (where appropriate) indicate whether the orig- inal statement is true, or the negation is true. ⚫ If I take linear algebra, then I will do my homework or go to class. • (x > 2 or x < −2) ⇒ |x| ≥ 2 • P⇒ (QVR) ⇒(¬PV QV R) Vn EN Em E Q (nm = 1) • Ex E N Vy & Z (x. y = 1)

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Chapter 12 Solutions

NATURE OF MATHEMATICS LL + WEBASSIGN

Ch. 12.1 - IN YOUR OWN WORDS What is a permutation? What is...Ch. 12.1 - Prob. 2PS Ch. 12.1 - Prob. 3PS Ch. 12.1 - Prob. 4PS Ch. 12.1 - Evaluate each expression in Problems 3-32. 9P2 Ch. 12.1 - Evaluate each expression in Problems 3-32. 9P3 Ch. 12.1 - Evaluate each expression in Problems 3-32. 9P4 Ch. 12.1 - Prob. 8PS Ch. 12.1 - Evaluate each expression in Problems 3-32. 52P3 Ch. 12.1 - Evaluate each expression in Problems 3-32. 4P4

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To decide: Whether use a permutation, a combination or neither to find the possible number of ways that they can be seated in a row if they must sit alternating boys and girls.

Solution Summary: The author explains that they can't use permutation, combination or neither to find the possible number of ways to be seated in a row if they must sit alternating boys and girls.