Explanation Given information: The provided expression is 2 y 2 − 7 y + 3 2 y 2 + 3 y − 2 ÷ 6 y 2 − 5 y + 1 3 y 2 + 5 y − 2 . Formula used: Two rational numbers A B and C D are divided as below: A B ÷ C D = A B ⋅ D C or A B ⋅ D C = A D B C To divide the rational numbers, multiply by its reciprocal and factor or simplify the result if possible. Calculation: Consider the expression as below: 2 y 2 − 7 y + 3 2 y 2 + 3 y − 2 ÷ 6 y 2 − 5 y + 1 3 y 2 + 5 y − 2 The reciprocal of 6 y 2 − 5 y + 1 3 y 2 + 5 y − 2 is as below: 3 y 2 + 5 y − 2 6 y 2 − 5 y + 1 Further to solve the above expression change the division operation by multiplication operation and multiply by the reciprocal as shown below: 2 y 2 − 7 y + 3 2 y 2 + 3 y − 2 ÷ 6 y 2 − 5 y + 1 3 y 2 + 5 y − 2 = 2 y 2 − 7 y + 3 2 y 2 + 3 y − 2 ⋅ 3 y 2 + 5 y − 2 6 y 2 − 5 y + 1 Further simplify by multiplication: 2 y 2 − 7 y + 3 2 y 2 + 3 y − 2 ÷ 6 y 2 − 5 y + 1 3 y 2 + 5 y − 2 = 2 y 2 − 7 y + 3 2 y 2 + 3 y − 2 ⋅ 3 y 2 + 5 y − 2 6 y 2 − 5 y

9th Edition

ISBN: 9780321997173

Author: Marvin L. Bittinger, Judith A. Beecher

Publisher: PEARSON

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Chapter 12.2, Problem 33ES

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To calculate: The simplification of 2y2−7y+32y2+3y−2÷6y2−5y+13y2+5y−2 by division.

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Chapter 12.2, Problem 32ES

Chapter 12.2, Problem 34ES

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Chapter 12 Solutions

Developmental Mathematics (9th Edition)

Ch. 12.1 - Objective 11.3a: Factor trinomials of the type...Ch. 12.1 - Prob. 2SR Ch. 12.1 - Prob. 1DE Ch. 12.1 - Prob. 2DE Ch. 12.1 - Prob. 3DE Ch. 12.1 - Prob. 4DE Ch. 12.1 - Prob. 5DE Ch. 12.1 - Prob. 6DE Ch. 12.1 - Prob. 7DE Ch. 12.1 - Prob. 8DE

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The simplification of 2 y 2 − 7 y + 3 2 y 2 + 3 y − 2 ÷ 6 y 2 − 5 y + 1 3 y 2 + 5 y − 2 by division.

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To calculate: The simplification of 2y2−7y+32y2+3y−2÷6y2−5y+13y2+5y−2 by division.

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Chapter 12 Solutions