Character by character text processing: Strings can be accessed or manipulated by using an individual text that is present. Different programming language access the string individually in a different way, some prefer the string gets accessed through subscript notation. String is considered as list of characters. Accessing string using subscript notation: The string that are accessed using the subscript notation uses subscript “0” to hold the first character and similarly till the last character. The last character of the string will be “\0”. The first value the index value will be “0” and to find the last character use “length(variable)-1” Example: //declare and define a string Declare String txt = "Hai" Explanation: In the above declaration, the given string gets processed in the following way: txt[0] will hold “H”. txt[1] will hold “a”. txt[2] will hold “i”.

Question

Want to see the full answer?

Answer 1

Question

Chapter 12.2, Problem 12.1CP

Program Plan Intro

Character by character text processing:

Strings can be accessed or manipulated by using an individual text that is present.

Different programming language access the string individually in a different way, some prefer the string gets accessed through subscript notation.

String is considered as list of characters.

Accessing string using subscript notation:

The string that are accessed using the subscript notation uses subscript “0” to hold the first character and similarly till the last character.

The last character of the string will be “\0”.

The first value the index value will be “0” and to find the last character use “length(variable)-1”

Example:

//declare and define a string

Declare String txt = "Hai"

Explanation:

In the above declaration, the given string gets processed in the following way:

txt[0] will hold “H”.

txt[1] will hold “a”.

txt[2] will hold “i”.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

Change the following code so that when player wins the game, the game continues by creating new GameGUI with the same player. However the player's starting position is same, everything else should be reseted. public static void main(String[] args) { Labyrinth labyrinth = new Labyrinth(10); Player player = new Player(9, 0); Random rand = new Random(); Dragon dragon = new Dragon(rand.nextInt(10), 9); JFrame frame = new JFrame("Labyrinth Game"); GameGUI gui = new GameGUI(labyrinth, player, dragon); frame.setLayout(new BorderLayout()); frame.setSize(600, 600); frame.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); frame.add(gui, BorderLayout.CENTER); frame.pack(); frame.setResizable(false); frame.setVisible(true); } public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private Timer timer; private long…

Create a menu item which restarts the game. Also add a timer, which counts the elapsed time since the start of the game level. When the restart is pressed, the restarted game should ask the player' name (in the GameGUI constructor) and set the score of player to 0 (player.setScore(0)), and the timer should restart again. And create a logic so that if the player loses his life (checkGame if the condition is false), then save this number together with his name into two variables. And display two buttons where one quits the game altogether (System.exit(0)) and the other restarts the game. public class GameGUI extends JPanel { private final Labyrinth labyrinth; private final Player player; private final Dragon dragon; private final ImageIcon playerIcon = new ImageIcon("data/images/player.png"); private final ImageIcon dragonIcon = new ImageIcon("data/images/dragon.png"); private final ImageIcon wallIcon = new ImageIcon("data/images/wall.png"); private final ImageIcon…

Please original work Analyze the complexity issues of processing big data What are five complexities and talk about the reasons they make the implementation complex. Please cite in text references and add weblinks