Explanation Given: A particle follows the trajectory x ( t ) = 1 4 t 3 + 2 t y ( t ) = 20 t − t 2 with t in seconds and distance in centimeters. Calculation: (a) In order to find the maximum height y ( t ) of the particle , set the derivative of y ( t ) equal to zero. that is, d y d t = 0 20 − 2 t = 0 t = 20 2 t = 10 Now, we can calculate the maximum height as follows y ( 10 ) = 20 × 10 − ( 10 ) 2 =200-100 =100 Hence, the maximum height of the particle is 100 cm...

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 12.1, Problem 20E

To determine

To find:

(a) What is the particle’s maximum height?

(b) When does the particle hit the ground and how far from the origin does it land?

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Chapter 12.1, Problem 19E

Chapter 12.1, Problem 21E

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Ch. 12.1 - Prob. 1PQ Ch. 12.1 - Prob. 2PQ Ch. 12.1 - Prob. 3PQ Ch. 12.1 - Prob. 4PQ Ch. 12.1 - Prob. 5PQ Ch. 12.1 - Prob. 6PQ Ch. 12.1 - Prob. 7PQ Ch. 12.1 - Prob. 1E Ch. 12.1 - Prob. 2E Ch. 12.1 - Prob. 3E

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(a) What is the particle’s maximum height? (b) When does the particle hit the ground and how far from the origin does it land?

Solution Summary: The author explains how the particle's maximum height is 100 cm, and its distance from the origin is 2040 cm.

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To find: (a) What is the particle’s maximum height? (b) When does the particle hit the ground and how far from the origin does it land?

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Chapter 12 Solutions

To find:

(a) What is the particle’s maximum height?

(b) When does the particle hit the ground and how far from the origin does it land?