EBK DELMAR'S STANDARD TEXTBOOK OF ELECT
6th Edition
ISBN: 9781305537125
Author: Herman
Publisher: YUZU
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Chapter 12, Problem 9RQ
What determines the thickness of the coating during an electroplating process?
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Chapter 12 Solutions
EBK DELMAR'S STANDARD TEXTBOOK OF ELECT
Ch. 12 - 1. Conduction in a liquid depends on the movement...Ch. 12 - What is a negative ion?Ch. 12 - 3. What is a positive ion?
Ch. 12 - Name three basic substances that can be used to...Ch. 12 - What is an electrolyte?Ch. 12 - 6. What is used to hold a sulfate ion together?
Ch. 12 - What is the negative terminal of a power source...Ch. 12 - Prob. 8RQCh. 12 - What determines the thickness of the coating...Ch. 12 - What is electrolysis?
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- type (o) bT S+αT Profational controller a = b = 5, T-La |kp| 50 5+50 kp=20,50,70 ② type (1) bT 5(stat) a=b=5,T= 1 ✓ KT 5 SC5+5 kp=20, 50, 70 (Find Wny, ess for type (a) and (1))arrow_forward2. Write an expression of the two sinusoidal voltage waveforms whose effective value is 7.071 V and whose phase difference is 90 degrees. Draw the phasor of those two sinusoidal waveforms in the complex plane.arrow_forward2. Determine developed torque and shaft torque of 220-V, 4-pole series motor with 800 conductors wave-connected supplying a load of 8.2kW by taking 45A from the mains. The flux per pole is 25 mWb and its armature circuit resistance is 0.60. Ans.[143.25 Nm, 135.25 Nm]arrow_forward
- 7. resistance): The practical capacitor can be simplified as the model below (ESR: equivalent series 10 μF ESR W From a datasheet, it is known that a 10 µF aluminum electrolytic capacitor has an impedance of 2800 mOhm at the 100 kHz testing condition. (1) Calculate the ESR under the above testing condition; (2) Calculate the phase shift between the voltage and current at 100 Hz and 10k Hz sinusoidal excitation conditions.arrow_forward5. A circuit has the following AC sources: y₁ = 5 cos(wt + 30°), y₂ = 4 cos(2wt + 120°), y3 = 3 cos(4wt - 60°), y4 = 6 cos(2wt - 120°), y = 2√2cos(wt - 60°): (1) Identify fundamental sources and harmonics. (2) Using phasor approach to simplify y₁ + y2 y3 y4 y5 as much as possible.arrow_forward6. A practical 10 μH wire wounded inductor has a series parasitic resistance of 0.4 Ohm, as shown in the figure below. a 10 pH 0.4 Ω W° b If an AC current y₁ = 4cos (20πt + 60°) is supplied to this inductor, (1) calculate the voltage across the inductor terminals a and b. (2) express the inductor terminal voltage and current in the complex plane. (3) calculate the phase shift between inductor terminal voltage and current If an AC current y₂ = 4cos (2000лt + 60°) is supplied to this inductor, (4) calculate the voltage across the inductor terminals a and b. (5) express the inductor terminal voltage and current in the complex plane. (6) calculate the phase shift between inductor terminal voltage and currentarrow_forward
- 1. As shown below, an LED lightbulb is connected to the grid power. The LED lightbulb has a rated power of 15 W, and the gird voltage is 120 V 60 Hz. Based on the above information (1) what is the peak value and effective value of the current flowing through the LED light bulb, (2) write an expression of the current flowing through the LED light bulb.arrow_forwardQ4: Determine the reactions at support A in structure shown in figure below. 4 kN/m 2.5 kN/m 9 m 4 marrow_forward4. A circuit has three AC sources: y₁ = 5cos(wt + 30°), y2 = 4cos(wt + 120°), y3 2cos(wt 60°), calculating: = (1) y₁ + y2 y3, and express the addition in the complex plane using phasors. (2) y1 y2 y3, and express the subtraction in the complex plane using phasorsarrow_forward
- Don't use ai to answer I will report you answerarrow_forwardA 50-HP, 600-V compound motor, taking 80 A, operates at a speed of 495 r.p.m. at full-load. If the flux per pole is 9.1 x 106 Maxwells and the armature resistance is 0.01502, the field resistances are 0.006 ohms and 300 ohms. Calculate: a. Field currents and the armature current b. the counter emf c. the rotational loss Ans.[2A,78A,593.362 V,8982.236 W]arrow_forward1. A 600-V, 150-HP, 600 r.p.m. d.c. series motor has an armature and series field resistance of 0.120 and 0.040, respectively. The full-load current is 200A. (a) Find the back e.m.f. at full-load. (b) Find the armature developed power and torque at full-load. Ans. [568V, 1808.13 N.m]arrow_forward
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