Explanation Given data: As the waste heat is removed from the reactor, that is Q reactor = − 2000 MW , T i = 18 ° C and T f = 30 ° C . Formula used: Write the expression for heat energy ( Q ) . Q = M c Δ T (1) Here, M is the mass, Δ T is the change in temperature, and c is the specific heat. Write the expression for change in temperature ( Δ T ) . Δ T = T f − T i (2) Here, T f is the finial temperature, and T i is the initial temperature. Explanation: Refer to TABLE 12.4 in the textbook for Specific heats of solids and liquids, that is specific heat of water is c water = 4190 J kg ⋅ K . Substitute 30 ° C for T f and 18 ° C for T i in equation (2), Δ T = 30 ° C − 18 ° C = 12 ° C = 12 K Consider the heat from the reactor in Δ t = 1 s . Therefore, Q reactor = − 2 , 000 MJ = − 2 , 000 × 10 6 J = − 2 × 10 9 J Modify equation (1). Q water = M water c water Δ T Consider the energy conservation

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ISBN: 9780134899978

Author: Knight

Publisher: PEARSON

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Chapter 12, Problem 91GP

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To find: How many kilograms of cooling water have to be pumped through the reactor in each minute.

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Chapter 12, Problem 90GP

Chapter 12, Problem 92GP

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How many kilograms of cooling water have to be pumped through the reactor in each minute.

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