
(a)
Interpretation: The band that is the valence band should be determined.
Concept Introduction:The band that forms from bonding molecular orbital in a semiconductor is called the valence band
(b)
Interpretation: The band that is the conduction band should be determined.
Concept Introduction: The band that forms from anti-bonding molecular orbital in a semiconductor is called the conduction band.
(c)
Interpretation: The region of the diagram that represents the band gap should be determined.
Concept Introduction: The band gap is the gap between the valence band and conduction band.
(d)
Interpretation: The band that consists of bonding molecular orbital should be determined.
Concept Introduction:The band that forms from bonding molecular orbital in a semiconductor is called the valence band that contains bonding molecular orbital
(e)
Interpretation: The type of semiconductor represented by the diagram should be explained.
Concept Introduction:An n-type semiconductor is one in which the dopant element has more number of valence electrons than the host element and this leads to an increase in number of negatively charged electrons in the conduction band that can move easily. So, in an n-type semiconductor conduction band is not completely empty.
A p-type semiconductor is one in which the dopant element has less number of valence electrons than the host element and this leads to electron vacancies, known as holes, in the valence band. Thus in a p-type semiconductor the valence band has electron vacancies and is not completely filled with electrons.
(f)
Interpretation: The elements that could be dopant from the given elements
Concept Introduction:The doped semiconductor given in the diagram is a p-type semiconductor. It means the dopant element must have less valence electron than germanium.

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Chapter 12 Solutions
Laboratory Experiments for Chemistry: The Central Science (14th Edition)
- ✓ edict the products of this organic reaction: ---- ။ A CH3–C−NH–CH2–C−CH3 + KOH ? Specifically, in the drawing area below draw the condensed structure of the product, or products, of this reaction. If there's more than one product, draw them in any arrangement you like, so long as they aren't touching. If there aren't any products because this reaction won't happen, check the No reaction box under the drawing area. Explanation Check Click anywhere to draw the first atom of your structure. C 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibiliarrow_forwardPredict the product of this organic reaction: A HO-C-CH3 + CH3NH2 P+ H2O Specifically, in the drawing area below draw the condensed structure of P. If there is no reasonable possibility for P, check the No answer box under the drawing area. Explanation Check Click anywhere to draw the first atom of your structure. marrow_forwardH 1) OsO4, pyridine 2) Na2SO3 or NaHSO3 in H₂O 2 productsarrow_forward
- ● Biological Macromolecules Naming and drawing cyclic monosaccharides Your answer is incorrect. • Row 1: Your answer is incorrect. Row 3: Your answer is incorrect. • Row 4: Your answer is incorrect. Try again... 0/5 Give the complete common name, including anomer and stereochemistry labels, of the following molecules. You will find helpful information in the ALEKS resource. CH2OH OH OH H H I H OH OH H] H CH2OH H OH ẞ-L-sorbose HOCH2 OH OH H HOCH2 H OH OH H OH H H CH2OH OH H H OH H I- H OH H OH Explanation Recheck W E R % 25 α B Y X & 5 D F G H McGraw Hill LLC. All Rights Reserved. Terms of Use | Pr Parrow_forwardWhat is the missing reactant in this organic reaction? + R -A HO IN + H₂O Specifically, in the drawing area below draw the skeletal ("line") structure of R. If there is more than one reasonable answer, you can draw any one of them. If there is no reasonable answer, check the No answer box under the drawing area. Note for advanced students: you may assume no products other than those shown above are formed. Explanation Check Click and drag to start drawing a structure. © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Centerarrow_forwardStuc X ctclix ALE X A ALE אן A ALEX Lab (195 X Nut x M Inb x NU X NUT X Unt x + → C www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-IQ1g8NUi-mObKa_ZLx2twjEhK7mVG6PulJI006NcKTV37JxMpZuyrVCdQolLAKqp_7U3r1GUD3... New Chrome available: Naomi Question 26 of 39 (4 points) | Question Attempt: 1 of Unlimited Give the IUPAC name. 2,3-dimethylhexane Part: 1/2 Part 2 of 2 Draw the skeletal structure of a constitutional isomer of the alkane above that contains a different number of carbons in its longest chain. Skip Part Check Click and drag to start drawing a structure. 3 Finance headline Q Search mwa Harvard Intensifi... X Save For Later 00 dlo HB Submit Assignment 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility a 9:11 PM 4/22/2025arrow_forward
- Predict the product of this organic reaction: + NH2 HO A P+ H2O Specifically, in the drawing area below draw the skeletal ("line") structure of P. If there is no reasonable possibility for P, check the No answer box under the drawing area. Click and drag to start drawing a structure. ✓arrow_forward个 Stuc X ctclix ALE X A ALE × A ALE X Lab x (195 × Nut x M Inbx EF 目 → C www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-IgNslkr7j8P3jH-IQ1g8NUi-mObKa_ZLx2twjEhK7mVG6PulJI006NcKTV37JxMpz Chapter 12 HW = Question 27 of 39 (5 points) | Question Attempt: 1 of Unlimited Part: 1/2 Part 2 of 2 Give the IUPAC name. Check 3 50°F Clear ©2025 McGraw Hill L Q Search webp a عالياكarrow_forward个 Stuck x ctc xALE X A ALE × A ALE X Lab x (19: x - G www-awu.aleks.com/alekscgi/x/Isl.exe/10_u-lgNslkr7j8P3jH-1Q1g8NUi-mObka ZLx2twjEhK7mVG6PUUIO06 Chapter 12 HW 三 Question 26 of 39 (4 points) 1 Question Attempt: 1 of Unlimited Answer the following questions about the given alkane. Part: 0 / 2 Part 1 of 2 Give the IUPAC name. Skip Part 2 53°F Clear Check × Q Search hp hp 02arrow_forward
- Calculate the equilibrium constant at 25.0 oC for the following equation. Cd(s) + Sn+2(aq) ↔Cd+2(aq) + Sn(s) Group of answer choices 3.11x104 1.95x1018 9.66x108 1.40x109arrow_forwardWhat is the pH at the cathode for the following cell written in line notation at 25.0 oC with a Ecell = -0.2749 V? Ni(s)|Ni+2(aq, 1.00 M)||H+1(aq, ?M)|H2(g, 1.00 atm)|Pt(s)arrow_forwardCalculate Ecell for a hydrogen fuel cell at 95.0 oC using the following half-reactions with PH2 = 25.0 atm and PO2 = 25.0 atm. O2(g) + 4H+1(aq) + 4e-1 → 2H2O(l) Eo = 1.229 V 2H2(g) → 4H+1(aq) + 4e-1 Eo = 0.00 Varrow_forward
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