Business and Economics The candy Shoppe charge $0.08 per copy for quantities up to and including 100 copies. For quantities above 100, the charge is $0.06 per copy. If x represents the number of copies, the price function is p ( x ) = { 0.08 x , for x ≤ 100 , 0.06 x , for x > 100. Find lim x → 100 − p ( x ) , lim x → 100 + p ( x ) , and lim x → 100 p ( x ) .
Business and Economics The candy Shoppe charge $0.08 per copy for quantities up to and including 100 copies. For quantities above 100, the charge is $0.06 per copy. If x represents the number of copies, the price function is p ( x ) = { 0.08 x , for x ≤ 100 , 0.06 x , for x > 100. Find lim x → 100 − p ( x ) , lim x → 100 + p ( x ) , and lim x → 100 p ( x ) .
Solution Summary: The author explains how to calculate the value of limit undersetxto 100-mathrmlimp(x-).
The candy Shoppe charge $0.08 per copy for quantities up to and including 100 copies. For quantities above 100, the charge is $0.06 per copy. If x represents the number of copies, the price function is
p
(
x
)
=
{
0.08
x
,
for
x
≤
100
,
0.06
x
,
for
x
>
100.
Find
lim
x
→
100
−
p
(
x
)
,
lim
x
→
100
+
p
(
x
)
,
and
lim
x
→
100
p
(
x
)
.
Consider the function f(x) = x²-1.
(a) Find the instantaneous rate of change of f(x) at x=1 using the definition of the derivative.
Show all your steps clearly.
(b) Sketch the graph of f(x) around x = 1. Draw the secant line passing through the points on the
graph where x 1 and x->
1+h (for a small positive value of h, illustrate conceptually). Then,
draw the tangent line to the graph at x=1. Explain how the slope of the tangent line relates to the
value you found in part (a).
(c) In a few sentences, explain what the instantaneous rate of change of f(x) at x = 1 represents in
the context of the graph of f(x). How does the rate of change of this function vary at different
points?
1. The graph of ƒ is given. Use the graph to evaluate each of the following values. If a value does not exist,
state that fact.
и
(a) f'(-5)
(b) f'(-3)
(c) f'(0)
(d) f'(5)
2. Find an equation of the tangent line to the graph of y = g(x) at x = 5 if g(5) = −3 and g'(5)
=
4.
-
3. If an equation of the tangent line to the graph of y = f(x) at the point where x 2 is y = 4x — 5, find ƒ(2)
and f'(2).
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