Explanation Given Information: The exponential equations are 5 x + y = 25 , 2 2 x − y = 64 . Formula used: The principle of exponent equality: For any real number b , where b ≠ − 1 , 0 or 1, b m = b n is equivalent to m = n . Calculation: Consider the exponential equations. 5 x + y = 25 , 2 2 x − y = 64 Simplify the exponents 5 x + y = 25 . 5 x + y = 5 2 Use the principle of exponent equality and solve. x + y = 2 Simplify, y = 2 − x Simplify the exponents 2 2 x − y = 64 . 2 2 x − y = 2 6 Use the principle of exponent equality and solve. 2 x − y = 6 Substitute y = 2 − x in 2 x − y = 6 . 2 x − ( 2 − x ) = 6 2 x − 2 + x = 6 3 x = 8 x = 8 3 Substitute x = 8 3 in y = 2 − x

Pearson eText Elementary and Intermediate Algebra: Concepts and Applications -- Instant Access (Pearson+)

7th Edition

ISBN: 9780137361847

Author: Marvin Bittinger, David Ellenbogen

Publisher: PEARSON+

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Chapter 12, Problem 79RE

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Chapter 12, Problem 78RE

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Chapter 12 Solutions

Pearson eText Elementary and Intermediate Algebra: Concepts and Applications -- Instant Access (Pearson+)

Ch. 12.1 - 1. Given , find. Ch. 12.1 - Prob. 2YT Ch. 12.1 - Prob. 3YT Ch. 12.1 - Prob. 4YT Ch. 12.1 - Prob. 5YT Ch. 12.1 - Prob. 6YT Ch. 12.1 - Prob. 7YT Ch. 12.1 - Prob. 8YT Ch. 12.1 - 9. Let. Use composition of inverse functions to...Ch. 12.1 - Prob. 1CYU

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The solution of the system 5 x + y = 25 , 2 2 x − y = 64 .

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Chapter 12 Solutions