COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 12, Problem 74QAP
To determine

(a)

The when the object is at equilibrium

Expert Solution
Check Mark

Answer to Problem 74QAP

At t2=0.0816sec the object is at equilibrium

Explanation of Solution

Given:

Mass of the object m=0.10kg

Spring constant K=15N/m

Displacement x1=0.15m

Body is released from rest v1=0m/s

Formula used:

Conservation of energy
  12Kx12+12mv12=12Kx22+12mv22

Calculation:

  12Kx12+12mv12=12Kx22+12mv22

  12Kx12=12mv22

  v22=Kx12m

  v2= K x 1 2 m= (15) (0.15) 2 0.1=1.837m/s

Speed at equilibrium point is v2=1.837m/s

Time taken to reach the equilibrium position
  t2t1=Δt=ΔxΔv=0.151.837=8.165×102=0.0816sec

  t2t1=0.0816sec(t1=0)t2=0.0816sec

Conclusion:

At t2=0.0816sec the object is at equilibrium

To determine

(b)

When the object is 10.0cm to the left of equilibrium

Expert Solution
Check Mark

Answer to Problem 74QAP

At t3=0.204s(t1=0) the object is at equilibrium

Explanation of Solution

Given:

  x3=10cm=0.1m

Calculation:

  12Kx32=12mv32

  v32=Kx32m

  v3= K x 3 2 m= (15) (0.1) 2 0.1=1.224m/s

Speed at equilibrium point is v3=1.224m/s

Time taken to reach the equilibrium position
  t3t1=Δt=ΔxΔv=0.150.11.224=0.204s

  t3=0.204s(t1=0)

Conclusion:

At t3=0.204s(t1=0) the object is at equilibrium

To determine

(c)

When the object is 5.0cm to the left of equilibrium

Expert Solution
Check Mark

Answer to Problem 74QAP

At t4=0.163s(t1=0) the object is at equilibrium

Explanation of Solution

Given:

  x3=5cm=0.05m

Calculation:

  12Kx42=12mv42

  v42=Kx42m

  v4= K x 4 2 m= (15) (0.05) 2 0.1=0.612m/s

Speed at equilibrium point is v4=1.167m/s

Time taken to reach the equilibrium position
  t4t1=Δt=ΔxΔv=0.10.612=0.163s

  t4=0.163s(t1=0)

Conclusion:

At t4=0.163s(t1=0) the object is at equilibrium

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
A positively charged disk has a uniform charge per unit area σ. dq R P x The total electric field at P is given by the following. Ek [2 - x (R² + x2) 1/2 Sketch the electric field lines in a plane perpendicular to the plane of the disk passing through its center.
Consider a closed triangular box resting within a horizontal electric field of magnitude E = 8.02  104 N/C as shown in the figure below. A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN · m2/C(b) Calculate the electric flux through the slanted surface of the box. kN · m2/C(c) Calculate the electric flux through the entire surface of the box. kN · m2/C
The figure below shows, at left, a solid disk of radius R = 0.600 m and mass 75.0 kg. Tu Mounted directly to it and coaxial with it is a pulley with a much smaller mass and a radius of r = 0.230 m. The disk and pulley assembly are on a frictionless axle. A belt is wrapped around the pulley and connected to an electric motor as shown on the right. The turning motor gives the disk and pulley a clockwise angular acceleration of 1.67 rad/s². The tension T in the upper (taut) segment of the belt is 145 N. (a) What is the tension (in N) in the lower (slack) segment of the belt? N (b) What If? You replace the belt with a different one (one slightly longer and looser, but still tight enough that it does not sag). You again turn on the motor so that the disk accelerates clockwise. The upper segment of the belt once again has a tension of 145 N, but now the tension in the lower belt is exactly zero. What is the magnitude of the angular acceleration (in rad/s²)? rad/s²

Chapter 12 Solutions

COLLEGE PHYSICS

Ch. 12 - Prob. 11QAPCh. 12 - Prob. 12QAPCh. 12 - Prob. 13QAPCh. 12 - Prob. 14QAPCh. 12 - Prob. 15QAPCh. 12 - Prob. 16QAPCh. 12 - Prob. 17QAPCh. 12 - Prob. 18QAPCh. 12 - Prob. 19QAPCh. 12 - Prob. 20QAPCh. 12 - Prob. 21QAPCh. 12 - Prob. 22QAPCh. 12 - Prob. 23QAPCh. 12 - Prob. 24QAPCh. 12 - Prob. 25QAPCh. 12 - Prob. 26QAPCh. 12 - Prob. 27QAPCh. 12 - Prob. 28QAPCh. 12 - Prob. 29QAPCh. 12 - Prob. 30QAPCh. 12 - Prob. 31QAPCh. 12 - Prob. 32QAPCh. 12 - Prob. 33QAPCh. 12 - Prob. 34QAPCh. 12 - Prob. 35QAPCh. 12 - Prob. 36QAPCh. 12 - Prob. 37QAPCh. 12 - Prob. 38QAPCh. 12 - Prob. 39QAPCh. 12 - Prob. 40QAPCh. 12 - Prob. 41QAPCh. 12 - Prob. 42QAPCh. 12 - Prob. 43QAPCh. 12 - Prob. 44QAPCh. 12 - Prob. 45QAPCh. 12 - Prob. 46QAPCh. 12 - Prob. 47QAPCh. 12 - Prob. 48QAPCh. 12 - Prob. 49QAPCh. 12 - Prob. 50QAPCh. 12 - Prob. 51QAPCh. 12 - Prob. 52QAPCh. 12 - Prob. 53QAPCh. 12 - Prob. 54QAPCh. 12 - Prob. 55QAPCh. 12 - Prob. 56QAPCh. 12 - Prob. 57QAPCh. 12 - Prob. 58QAPCh. 12 - Prob. 59QAPCh. 12 - Prob. 60QAPCh. 12 - Prob. 61QAPCh. 12 - Prob. 62QAPCh. 12 - Prob. 63QAPCh. 12 - Prob. 64QAPCh. 12 - Prob. 65QAPCh. 12 - Prob. 66QAPCh. 12 - Prob. 67QAPCh. 12 - Prob. 68QAPCh. 12 - Prob. 69QAPCh. 12 - Prob. 70QAPCh. 12 - Prob. 71QAPCh. 12 - Prob. 72QAPCh. 12 - Prob. 73QAPCh. 12 - Prob. 74QAPCh. 12 - Prob. 75QAPCh. 12 - Prob. 76QAPCh. 12 - Prob. 77QAPCh. 12 - Prob. 78QAPCh. 12 - Prob. 79QAPCh. 12 - Prob. 80QAPCh. 12 - Prob. 81QAPCh. 12 - Prob. 82QAPCh. 12 - Prob. 83QAPCh. 12 - Prob. 84QAPCh. 12 - Prob. 85QAPCh. 12 - Prob. 86QAPCh. 12 - Prob. 87QAP
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
SIMPLE HARMONIC MOTION (Physics Animation); Author: EarthPen;https://www.youtube.com/watch?v=XjkUcJkGd3Y;License: Standard YouTube License, CC-BY